What occurs when there are oh ions in a solution

Answers

Answer 1

Answer: the solution is considered basic. The more H⁺ a solution has the more acidic it is and the more OH⁻ a solution has the more basic it is. pH=-Log[H⁺] and pOH=-log[OH⁻]. pOH+pH=14

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An ion that consists of 7 protons, 6 neutrons, and 10 electrons has a net charge of(I ) 4- (3) 3+(2) 3- (4) 4+

Answers

Answer : The correct option is 2.

Explanation :

Number of protons = 7

Number of neutrons = 6

Number of electrons = 10

Protons are those which carries positive charge.

Electrons are those which carries negative charge.

Neutrons are those which do not carry any charge that means neutrons are neutral.

The net charge on an ion = Number of protons present in an ion + Number of electrons present in an ion

The net charge on an ion = (+7) + (-10) = -3

Therefore, the net charge on an ion is (-3).

The answer is (2) 3-. The proton has one positive charge. Neutrons do not have charge. And electron has one negative charge. So the net charge is 3 negative charge.

Count the total number of atoms in sio2:

Answers

Atoms are the basic units of matter and the defining structure of elements. We count the number of atoms by the total number of elements present in the compound. In this case, we have 1 atom of Si and 2 atoms of oxygen which would have 3 total number of atoms.

When the compound, Ba(C2H3O2)2, is mixed with water, the Ba(C2H3O2)2 is:soluble because compounds containing the C2H3O2− ion are soluble in water

insoluble because most compounds containing the C2H3O2− ion are insoluble in water

soluble because all Ba+2 compounds are soluble in water

insoluble because no Ba+2 are soluble in water

Answers

Answer:

the answer is soluble because compounds containing the C2H3O2− ion are soluble in water

When the compound, Ba(C2H3O2)2, is mixed with water, the Ba(C2H3O2)2 is insoluble because most compounds containing the C2H3O2− ion are insoluble in water

Hydrogen and helium in the universe were formed by which of these phenomena?a. Big bang
b. Fusion in small stars
c. Fusion in very large stars
d. Supernova

Answers

I think the answer is a

When sodium metal is added to water, an orange flame is observed on the metal surface. Based on this observation, what can best be concluded

Answers

Answer:

the answer i belive is c

Explanation:

A chemical reaction occurs because heat and light are given off.

Explanation:

A property which causes change in chemical composition of a substance is known as a chemical property. For example, reactivity, toxicity, combustion etc.

Whereas a property which causes no change in chemical composition of a substance is known as a physical property. For example, mass, volume, density etc.

Sodium is a very reactive metal and it reacts readily with oxygen, water etc. So, when sodium is added to water then occurrence of an orange flame represents its reactivity.

Thus, based on given observation it can be concluded that chemical reaction takes place when sodium is added to water.

Which isotope will spontaneously decay and emit particles with a charge of +2?(1) 53Fe (3) 198Au
(2) 137Cs (4) 220Fr

Answers

Answer: The correct option is 4.

Explanation: All the options will undergo some type of radioactive decay processes. There are 3 decay processes:

1) Alpha decay: It is a decay process in which alpha particle is released which has has a mass number of 4 and a charge of +2.

$_Z^A\textrm{X}\rightarrow _(Z-2)^(A-4)\textrm{Y}+_2^4\alpha$

2) Beta-minus decay: It is a decay in which a beta particle is released. The beta particle released has a mass number of 0 and a charge of (-1).

$_Z^A\textrm{X}\rightarrow _(Z+1)^A\textrm{Y}+_(-1)^0\beta$

3) Beta-plus decay: It is a decay process in which a positron is released. The positron released has a mass number of 0 and has a charge of +1.

$_Z^A\textrm{X}\rightarrow _(Z-1)^A\textrm{Y}+_(+1)^0\beta$

For the given options:

Option 1: This nuclei will undergo beta-plus decay process to form $_(25)^(53)\textrm{Mn}$

$_(26)^(53)\textrm{Fe}\rightarrow _(25)^(53)\textrm{Mn}+_(+1)^0\beta$

Option 2: This nuclei will undergo beta-minus decay process to form $_(80)^(198)\textrm{Hg}$

$_(79)^(198)\textrm{Au}\rightarrow _(80)^(198)\textrm{Hg}+_(-1)^0\beta$

Option 3: This nuclei will undergo a beta minus decay process to form $_(56)^(137)\textrm{Ba}$

$_(55)^(137)\textrm{Cs}\rightarrow _(56)^(137)\textrm{Ba}+_(-1)^0\beta$

Option 4: This nuclei will undergo an alpha decay process to form $_(85)^(216)\textrm{At}$

$_(87)^(220)\textrm{Fr}\rightarrow _(85)^(216)\textrm{At}+_2^4\alpha$

Hence, the correct option is 4.

It is 220Fr that would spontaneously decay and emit particles with a charge of +2.

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