John has taken out a loan for college. He started paying off the loan with a first payment of $100. Each month he pays, he wants to pay back 1.1 times as the amount he paid the month betore. Explain to Jo howto represent his first 20 payment n sigma notation.Then esplain how to tind the sum of his frst 20 pyments, using complete sentences. Esplain why this series is convergent or divergent

Answers

Answer 1
Answer: Since each term of the series is 1.1 times the previous one, the series is geometric. The generic term of a geometric series is
  a_(n)=a_(0)\cdot r^((n-1))

The sum in sigma notation simply adds these terms. The leading factor of 100 can be factored out.
sum=\displayform{100\cdot\sum\limits_(n=1)^(20){1.1^((n-1))}}

The sum can be found by adding the terms or by using the formula for the sum of a geometric series. In the latter case, we have
sum=100\cdot(1.1^(20)-1)/(1.1-1)\approx5727.50

The series is divergent because the common ratio of terms is greater than 1. (Of course, any finite number of terms will have a finite sum.)

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Solve the following system of equations using the elimination method.7x + 20y = 142x – 10y = 4Question 18 options:A) (3,1)B) (2,0)C) (4,–5)D) (–3,4)

Help please !!!! ASAP

Answers

Answer: 1: cant figure out sorry :(

2: 2.5

3: 5

4: 20

5: 25

10: 50

Step-by-step explanation: What i did here was divided by 5 the numbers below 3 and multiply by 5 for the numbers above 3. Hope this helps :)

A zoo has a circular pool for its seals. The diameter of the pool is 32 feet. How much fence is needed to enclose the pool?

Answers

Answer:

The answer is 32 \pi\ feet or 100.53\ feet

Step-by-step explanation:

we know that

To calculate how much fence is needed to enclose the circular pool, find the circumference of the circular pool

The circumference of a circle is equal to

C=\pi D

where

D is the diameter of the circle

In this problem we have

D=32\ feet

Substitute

C=\pi (32)=32 \pi\ feet

C=32 \pi\ feet=100.53\ feet

9 + 1.34 + .5 (3.50 +1.74) How would you simplify the expression? Explain your steps.

Answers

1. Using PEMDAS, I would first solve the equation inside the parenthesis
(3.50+1.74)= 5.24
Now the equation is:
9+1.34+.5(5.24)
2. Multiply .5(5.24)
9+1.34+2.62=
12.96

What is the sum of 18 23/30+ 2/3

Answers

Answer:

See image

Step-by-step explanation:

Three 3.0 g balls are tied to 80-cm-long threads and hung from a single fixed point. Each of the balls is given the same charge q. At equilibrium, the three balls form an equilateral triangle in a horizontal plane with 20 cm sides. What is q?

Answers

Answer:

q = 0.105uC

Step-by-step explanation:

We can determine the force on one ball by assuming two balls are stationary, finding the E field at the lower right vertex and calculate q from that.

Considering the horizontal and vertical components.

First find the directions of the fields at the lower right vertex. From the lower left vertex the field will be at 0° and from the top vertex, the field will be at -60° or 300° because + charge fields point radially outward in all directions. The distances from both charges are the same since this is an equilateral triangle. The fields have the same magnitude:

E=kq/r²

Where r = 20cm

= 20/100

= 0.2m

K = 9.0×10^9

9.0×10^9 × q /0.2²

9.0×10^9/0.04

2.25×10^11 q

These are vector fields of course

Sum the horizontal components

Ecos0 + Ecos300 = E+0.5E

= 1.5E

Sum the vertical components

Esin0 + Esin300 = -E√3/2

Resultant = √3E at -30° or 330°

So the force on q at the lower right corner is q√3×E

The balls have two forces, horizontal = √3×E×q

and vertical = mg, therefore if θ is the angle the string makes with the vertical tanθ = q√3E/mg

mg×tanθ = q√3E.

..1

Then θ will be...

Since the hypotenuse = 80cm

80cm/100

= 0.8m

The distance from the centroid to the lower right vertex is 0.1/cos30 =

0.1/0.866

= 0.1155m

Hence,

0.8×sinθ = 0.1155

Sinθ = 0.1155/0.8

Sin θ = 0.144375

θ = arch sin 0.144375

θ = 8.3°

From equation 1

mg×tanθ = q√3E

g = 9.8m/s^2

m = 3.0g = 0.003kg

0.003×9.8×tan(8.3)

0.00428 = q√3E

0.00428 = q×1.7320×E

Where E=kq/r²

Where r = 0.2m

0.0428 = kq^2/r² × 1.7320

K = 9.0×10^9

0.0428/1.7320 = 9.0×10^9 × q² / 0.2²

0.02471×0.04 = 9.0×10^9 × q²

0.0009884 = 9.0×10^9 × q²

0.0009884/9.0×10^9 = q²

q² = 109822.223

q = √109822.223

q = 0.105uC

Perform the operation. (10x2 – 10x – 6) + (x+6)

Answers

Answer:

10x² - 9x

Step-by-step explanation:

(10x² - 10x - 6) + (x + 6)

10x² - 10x - 6 + x + 6

10x² - 9x - 6 + 6

10x² - 9x