G purchased a family income policy at age 40. the policy has a 20-year rider period. if g were to die at age 50, how long would g's family receive an income?

Answers

Answer 1

Answer: Rider period is the period which is offered by the insurer to the policy holder in which the policy would be revived and the benefits pertaining to the policy. In the current scenario, the policy has 20 years of rider policy and is taken when the holder is 40 years old. At the age of 50 years, half of the rider period is consumed and thus the family will wait for the remaining half of the rider period to access the benefits.

Therefore, g's family will receive income for 10 years.

Answer 2

Answer:

Final answer:

If G, who bought a family income policy with a 20 years rider at age 40, dies at age 50, his family would continue to receive income for another 10 years, which is the remaining period of the policy.

Explanation:

The question refers to a family income policy, which is a type of life insurance. In this situation, G bought a policy at the age of 40 which includes a term life insurance policy and a decreasing term rider of 20 years. If G were to die at age 50, the remaining term of the rider would dictate how much longer the family receives income. As G has held the policy for 10 years, there would be another 10 years remaining on the policy. Therefore, G's family would continue to receive an income for an additional 10 years after G's death.

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Answers

1. y = x^2 - 4x - 5
= x^2 - 4x + 4 - 4 - 5
= (x^2 - 4x + 4) -4 - 5
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Answer:

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Answers

asssuming you mean

evaluate $10+20log_4(3+1)$

remember $log_a(a)=1$
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A furniture company makes large and small chairs. A small chair takes 30 minutes of machine time and 75 minutes of labor to build. A large chair takes 40 minutes of machine time and 80 minutes of labor to build. The company has 57 hours of labor time and 26 hours of machine time available each day. How many of each type of chair is built in a day?

Answers

Let the number of large chairs be x and small chairs be y
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80x + 75y = 57 x 60 = 3,420 . . . . (2)

(1) x 2 => 80x + 60y = 3,120 . . . . (3)

(2) - (3) => 15y = 300 => y = 300/15 = 20

From (2), 80x + 75(20) = 3,420 => 80x + 1,500 = 3,420 => 80x = 3,420 - 1,500 = 1,920 => x = 1,920/80 = 24

Therefore, the company should produce 24 large chairs and 20 small chairs.

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