A scientist isolates a water-soluble compound from spider venom. the substance has nitrogen, carbon, hydrogen, and oxygen in its chemical structure. when the scientist injects the compound under the skin of mice, it causes certain structural materials in cell membranes to break down. in her next experiment, the researcher will determine whether the compound is toxic to humans. based on this information, the compound is a

Answers

Answer 1
Answer:

Answer : Protein


Explanation : When the scientist isolated the water soluble compound from the spider venom it had elements such as carbon,nitrogen, hydrogen and oxygen in its chemical structure this gives an assumption of the compound being a protein. But, further confirmation was given when it was injected under the mice skin and which broke down the structural materials in the cell membrane, this is one of the property of protein. And he is going to find out about its toxicity to humans.

Answer 2
Answer:

Final answer:

The compound from spider venom is likely an alkaloid, a class of compounds often involved in cell membrane disruption and known for their psychotropic and physiological effects on humans. It might have potential medicinal uses like other animal toxins currently under research.

Explanation:

The compound described in the question, which is derived from spider venom and contains nitrogen, carbon, hydrogen, and oxygen, is most likely a type of alkaloid. Alkaloids are naturally occurring chemical compounds containing mostly basic nitrogen atoms. They have a range of effects on living organisms but are often involved in cell membrane disruption. Examples include substances like morphine, codeine, and heroin, as well as various animal toxins currently under study for their medicinal potential. It's worth noting, that medicinal uses of animal toxins is not a new concept. Compounds similar to snake venom, for example, have found uses as antivirals and painkillers. Future research will reveal the exact mechanism and potential medicinal uses of this spider venom-derived compound.

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1.81 g H2 is allowed to react with 10.2 g N2, producing 2.19 g NH3.What is the theoretical yield in grams for this reaction under the given conditions?3H2(g)+N2(g)→2NH3(g)

Answers

The theoretical yield : = 10.251 g

Further explanation

Given

Reaction

3H₂(g)+N₂(g)→2NH₃(g)

1.81 g H₂

10.2 g N₂

2.19 g NH₃

Required

The theoretical yield

Solution

Find limiting reactant :

H₂ : 1.81 g : 2 g/mol = 0.905 mol

N₂ : 10.2 g : 28 g/mol = 0.364 mol

mol : coefficient

H₂ = 0.905 : 3 = 0.302

N₂ = 0.364 : 1 = 0.364

H₂ as a limiting reactant(smaller ratio)

Moles NH₃ based on H₂, so mol NH₃ :

= 2/3 x mol H₂

= 2/3 x 0.905

=0.603

Mass NH₃ :

= mol x MW

=0.603 x 17 g/mol

= 10.251 g

Which is the electron configuration for lithium? A. 1s2 B. 2s3 C. 1s22s1 D. 1s12s2

Answers

The electron configuration for lithium 1s^(2)  2s^(1). So, the correct answer is C.

Electronic configuration:-

The electron configuration of an element describes how electrons are distributed in its atomic orbitals. Electron configurations of atoms follow a standard notation in which all electron-containing atomic subshells (with the number of electrons they hold written in superscript) are placed in a sequence.

Electronic configuration for lithium:-

The atomic number of lithium is 3. So, the electronic configuration is as follows:-

Li= 1s^(2)  2s^(1)\n=(He)  2s^(1)

So, the correct option is C.

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Answer:

C

Explanation:

just took the test on edge

The ratio of oxygen-16 and oxygen-18 isotopes in plankton fossils in deep-sea sediments can be used to determine ________.

Answers

The ratio of oxygen-16 and oxygen-18 isotopes in plankton fossils in deep-sea sediments can be used to determine past temperatures.

Answer;

-past temperatures

The ratio of oxygen-16 and oxygen-18 isotopes in plankton fossils in deep-sea sediments can be used to determine past temperatures.

Explanation;

-O-16 will evaporate more readily than O-18 since it is lighter, therefore; during a warm period, the relative amount of O-18 will increase in the ocean waters since more of the O-16 is evaporating.

-Hence, looking at the ratio of O16 to O18 in the past can give clues about global temperatures.

What is the difference between solid, liquid and ice? Use ice, water and steam as examples.

Answers

Answer: A solid is something that can hold its own shape and is hard to compress (squash). However, ice is different from most solids because its molecules are less densely packed than in liquid water so ice takes up a little more space than the same amount of liquid water. This is why ice floats.

Explanation: Hope it works!!!!!

How many mL of 0.100 M NaOH are needed to neutralize 50.00 mL of a 0.150 M solution of CH3CO2H, a monoprotic acid? How many mL of 0.100 M NaOH are needed to neutralize 50.00 mL of a 0.150 M solution of CH3CO2H, a monoprotic acid? a. 37.50 mL
b. 50.00 mL
c. 75.00 mL
d. 100.00 mL
e. 25.00 mL

Answers

Answer:

We need 75 mL of 0.1 M NaOH ( Option C)

Explanation:

Step 1: Data given

Molarity of NaOH solution = 0.100 M

volume of 0.150 M CH3COOH = 50.00 mL = 0.05 L

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles of CH3COOH

Moles CH3COOH = Molarity * volume

Moles CH3COOH = 0.150 M * 0.05 L

Moles CH3COOH =  0.0075 moles

Step 4: Calculate moles of NaOH

For 1 mol of CH3COOH we need 1 mol of NaOH

For 0.0075 mol CH3COOH we need 0.0075 mole of NaOH

Step 5: Calculate volume of NaOH

volume = moles / molarity

volume = 0.0075 moles / 0.100 M

Volume = 0.075 L = 75 mL

We need 75 mL of 0.1 M NaOH

Determine the number of moles of oxygen atoms in each of the following.1) 4.93 mol H2O2
2) 2.01 mol N2O

Answers

Answer :

Part 1: 4.93 moles of H_2O_2 contains 9.86 moles of oxygen atoms.

Part 2: 2.01 moles of N_2O contains 2.01 moles of oxygen atoms.

Explanation :

Part 1: 4.93 mol H_2O_2

In 1 mole of H_2O_2, there are 2 atoms of hydrogen and 2 atoms of oxygen.

As, 1 mole of H_2O_2 contains 2 moles of oxygen atoms.

So, 4.93 moles of H_2O_2 contains 4.93* 2=9.86 moles of oxygen atoms.

Thus, 4.93 moles of H_2O_2 contains 9.86 moles of oxygen atoms.

Part 2: 2.01 mol N_2O

In 1 mole of N_2O, there are 2 atoms of nitrogen and 1 atom of oxygen.

As, 1 mole of N_2O contains 1 mole of oxygen atoms.

So, 2.01 moles of N_2O contains 2.01* 1=2.01 moles of oxygen atoms.

Thus, 2.01 moles of N_2O contains 2.01 moles of oxygen atoms.