CHEMISTRY COLLEGE

A 135 g sample of H20 at 85°C is cooled. The water loses a total of 15 kJ of energy in the coolingprocess. What is the final temperature of the water? The specific heat of water is 4.184 J/g.°C.

A. 112°C

B. 58°C

C. 70°C

D. 84°C

E. 27°C

Answers

Answer 1

Answer:

Answer:

B. 58°C

Explanation:

Hello,

In this case, the relationship among heat, mass, specific heat and temperature for water is mathematically by:

$Q=mCp\Delta T=mCp(T_2-T_1)$

In such a way, solving for the final temperature $T_2$ we obtain:

$T_2=T_1+(Q)/(mCp)$

Therefore, we final temperature is computed as follows, considering that the involved heat is negative as it is lost for water:

$T_2=85\°C+(-15kJ*(1000J)/(1kJ) )/(135g*4.184(J)/(g\°C) )\n\nT_2=58\°C$

Thereby, answer is B. 58°C.

Regards.

Answer 2

Answer:

Final answer:

The final temperature of the water is approximately 58°C (Option B) after it has lost 15 kJ of energy in the cooling process.

Explanation:

To calculate the final temperature of the water, we can use the formula of heat loss or gain, Q = mcΔT, where Q is the heat loss or gain, m is the mass, c is the specific heat, and ΔT is the change in temperature.

Setting the given values into our formula: -15,000 J = (135 g) * (4.184 J/g°C) * (T_final - 85°C).

Solving this equation for T_final gives us T_final ≈ 58°C. Hence, the suitable answer would be option B: 58°C.

Learn more about Heat Transfer here:

brainly.com/question/13433948

#SPJ3

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A weather system moving through the American Midwest produced rain with an average pH of 5.02. By the time the system reached New England, the rain it produced had an average pH of 4.66. How much more acidic was the rain falling in New England?

Answers

Answer:

The rain falling in New England is 2.29 times more acidic than the one in the American Midwest.

Explanation:

The acidity of a solution depends on the concentration of H⁺ ions ([H⁺]). We can calculate this concentration from the pH using the following expression.

pH = -log ([H⁺])

American Midwest

pH = -log ([H⁺])

5.02 = -log ([H⁺])

[H⁺] = antilog (-5.02) = 9.55 × 10⁻⁶ M

New England

pH = -log ([H⁺])

4.66 = -log ([H⁺])

[H⁺] = antilog (-4.66) = 2.19 × 10⁻⁵ M

The ratio of concentrations is:

$(2.19 * 10^(-5) M )/(9.55 * 10^(-6) M) =2.29$

The rain falling in New England is 2.29 times more acidic than the one in the American Midwest.

The change in the acidity of the rain falling in New England is mathematically given as

r=2.29

What is the change in the acidity of the rain falling in New England?

Question Parameter(s):

American midwest pH of 5.02

New England pH of 4.66

Generally, the equation for the pH is mathematically given as

pH = -log ([H⁺])

Therefore American midwest

pH = -log ([H⁺])

5.02 = -log ([H⁺])

[H⁺] = antilog (-5.02) = 9.55 × 10⁻⁶ M

and New england

pH = -log ([H⁺])

4.66 = -log ([H⁺])

[H⁺] = antilog (-4.66) = 2.19 × 10⁻⁵ M

In conclusion, the concentration ratio is

$r=(2.19 * 10^(-5) M )/(9.55 * 10^(-6) M)$

r=2.29

Answers

Answer:

c) 0.080 M Al₂(SO₄)₃

Explanation:

Ion [SO₄²⁻] concentration of each solution is:

a) 0.075 M H₂SO₄: [SO₄²⁻] = 0.075M. Because 1 mole of H₂SO₄ contains 1 mole of SO₄²⁻

b) 0.15 M Na₂SO₄: [SO₄²⁻] = 0.15M. Also, 1 mole of Na₂SO₄ contains 1 mole of SO₄²⁻

c) 0.080 M Al₂(SO₄)₃ [SO₄²⁻] = 0.080Mₓ3 = 0.240M. Because 1 mole of Al₂(SO₄)₃ contains 3 moles of SO₄²⁻.

Thus, the soluion that has the greatest [SO₄²⁻] is 0.080 M Al₂(SO₄)₃

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Answers

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