Chuck must save a total of 180 for a new bike. So far he has saved 4/5 of the amount. How much money has chuck saved for the bike
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5x - 5x = 6x² - 5x - 3
0 = 6x² - 5x - 3
x = -(-5) ± √((-5)² - 4(6)(-3))
2(6)
x = 5 ± √(25 + 72)
12
x = 5 ± √(97)
12
x = 5 + √(97) U x = 5 - √(97)
12 12
The value of x are; x = 5 + √(97)/12 and x = 5 - √(97)/12.
What is a quadratic equation?
A quadratic equation is the second-order degree algebraic expression in a variable.
The standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.
Given;
5x = 6x² - 3
Subtract 5x on both sides
5x - 5x = 6x² - 5x - 3
0 = 6x² - 5x - 3
x = -(-5) ± √((-5)² - 4(6)(-3)) / 2(6)
x = 5 ± √(25 + 72)/ 12
x = 5 ± √(97)/ 12
The value of x are;
x = 5 + √(97)/12
x = 5 - √(97)/12
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x1 = -0.8; x2 = -3;
5x^2+19x+12 = 5( x + 0.8)( x + 3) = ( 5x + 4)( x + 3);
Answer:
( x − 3 )( 5x − 4 )
Step-by-step explanation:
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Answer:
11.37 lb-ft
Step-by-step explanation:
We are given that
Force,F=3 pounds
Let Point A (3,7) and point B(8,8)
We have to find the work done by the force.
feet
We know that Work done by the force
Substitute the values
Hence, the work done by the force =11.37 lb-ft
Final answer:
The work done by a force of 3 pounds moving an object along a straight line from point (3,7) to (8,8) at an angle of 42 degrees with the horizontal is calculated to be approximately 11.7 foot-pounds.
Explanation:
The student's question relates to the concept of work done by a force. According to the equation for work, W = Fd cos θ, the work done by a force is the product of the magnitude of the force, the distance over which it acts and the cosine of the angle between the force and the displacement vectors. In this case, the force is 3 pounds, the displacement can be calculated using Pythagorean theorem from the points (3,7) to (8,8) yielding approximately 5.1 feet, and the angle with the horizontal is 42 degrees. Using these values, the work done can be calculated as:
W = 3 pounds * 5.1 feet * cos(42 degrees) = approximately 11.7 foot-pounds
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f(x + 2) = (x + 2)³ - 7
f(x + 2) = (x + 2)(x + 2)(x + 2) - 7
f(x + 2) = (x(x + 2) + 2(x + 2))(x + 2) - 7
f(x + 2) = (x(x) + x(2) + 2(x) + 2(2))(x + 2) - 7
f(x + 2) = (x² + 2x + 2x + 4)(x + 2) - 7
f(x + 2) = (x² + 4x + 4)(x + 2) - 7
f(x + 2) = (x²(x + 2) + 4x(x + 2) + 4(x + 2)) - 7
f(x + 2) = (x²(x) + x²(2) + 4x(x) + 4x(2) + 4(x) + 4(2)) - 7
f(x + 2) = (x³ + 2x² + 4x² + 8x + 4x + 8) - 7
f(x + 2) = (x³ + 6x² + 12x + 8) - 7
f(x + 2) = x³ + 6x² + 12x + 8 - 7
f(x + 2) = x³ + 6x² + 12x + 1
g(x) = f(x + 2) + 4
g(x) = (x³ + 6x² + 12x + 1) + 4
g(x) = x³ + 6x² + 12x + 1 + 4
g(x) = x³ + 6x² + 12x + 5