The stopping distance (s) of a car varies directly as the square of its speed (v). If a car traveling 20 mph requires 60 ft to stop, find the stopping distance for a car traveling 40 mph. Round to the nearest tenth.

Answers

Answer 1
Answer:

Answer:

The stopping distance for a car traveling 40 mph is 240 feet.

Step-by-step explanation:

We are given the following in the question:

The stopping distance (s) of a car varies directly as the square of its speed (v)

s\propto v^2

Removing the sign of proportionality and adding constant of proportionality, we get

s = kv^2

where k is constant of proportionality.

Now, when s = 60 feet, v = 20 mph

Putting values, we get,

60 = k(20)^2\n\nk = (60)/(400) = 0.15

Putting value of k in the equation, we get,

s = 0.15v^2

We have to find the stopping distance for a car traveling 40 mph.

s = 0.15(40)^2 = 240\text{ feet}

Thus, the stopping distance for a car traveling 40 mph is 240 feet.


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Step-by-step explanation:

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Answers

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Step-by-step explanation:

Lines that are parallel have the same slope.  The slope of the given equation is 1.  This means that the new equation will also have a slope of 1.

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Answers

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Answers

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▹ Answer

35x + 72y

▹ Step-by-Step Explanation

(38x + 61y) - (3x - 11y)

38x + 61y - (3x - 11y)

38x + 61 y - 3x + 11y

35x + 61y + 11y

35x + 72y

Hope this helps!

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Brainliest is greatly appreciated!

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