Marcia can make 5 candles in an hour. Kevin can make only 4 candles in an hour, but he already has 7 completed candles. how can Marcia use a system of equations to determine when she will have the same number of candles as Kevin?
Answers
5h = 4h+7
h = 7 … subtract 4h from each side
In 7 hours, each will have the same number of candles.
Answer:
After 7 hours.
Step-by-step explanation:
Let Marcia and Kevin can make candles in h hours.
Now Marcia can make 5 candles per hour
so total number of candles made = 5h
similarly Kevin can make only 4 candles in one hour.
So total candles made in h hours = 4h
But Kevin has already completed 7 candles so total candles made by Kevin = (4h + 7)
Now it is given that both Marcia and Kevin made same number of candles in h hours.
so 5h = (4h + 7)
5h - 4h = 7
h = 7
After 7 hours candles made by both Marcia and Kevin will be same.
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Answers
Answer:
the other guy is wrong take my advice its diffidently B:
"1 and 2 are congruent because they are a pair of corresponding angles"
Step-by-step explanation:
i took the test and this is the correct answer.
-hope you all do good on your tests.
-here's proof so you know you don't get the answer wrong.
-have a good day :)
Answers
Answer:
(a) The inequality for the number of items, x, produced by the labor, is given as follows;
250 ≤ x ≤ 600
(b) The inequality for the cost, C is $1,000 ≤ C ≤ $3,000
Step-by-step explanation:
The total time available for production = 1000 hours per week
The time it takes to produce an item on line A = 1 hour
The time it takes to produce an item on line B = 4 hour
Therefore, with both lines working simultaneously, the time it takes to produce 5 items = 4 hours
The number of items produced per the weekly labor = 1000/4 × 5 = 1,250 items
The minimum number of items that can be produced is when only line B is working which produces 1 item per 4 hours, with the weekly number of items = 1000/4 × 1 = 250 items
Therefore, the number of items, x, produced per week with the available labor is given as follows;
250 ≤ x ≤ 1250
Which is revised to 250 ≤ x ≤ 600 as shown in the following answer
(b) The cost of producing a single item on line A = $5
The cost of producing a single item on line B = $4
The total available amount for operating cost = $3,000
Therefore, given that we can have either one item each from lines A and B with a total possible item
When the minimum number of possible items is produced by line B, we have;
Cost = 250 × 4 = $1,000
When the maximum number of items possible, 1,250, is produced, whereby we have 250 items produced from line B and 1,000 items produced from line A, the total cost becomes;
Total cost = 250 × 4 + 1000 × 5 = 6,000
Whereby available weekly outlay = $3000, the maximum that can be produced from line A alone is therefore;
$3,000/$5 = 600 items = The maximum number of items that can be produced
The inequality for the cost, C, becomes;
$1,000 ≤ C ≤ $3,000
The time to produce the maximum 600 items on line A alone is given as follows;
1 hour/item × 600 items = 600 hours
The inequality for the number of items, x, produced by the labor, is therefore, given as follows;
250 ≤ x ≤ 600
(a) The inequality for the number of items, x, produced by the labor, is given as follows;
250 ≤ x ≤ 600
(b) The inequality for the cost, C is $1,000 ≤ C ≤ $3,000
What is inequality?
Inequality is a statement shows greater the, greater then equal to, less then,less then equal to between two algebraic expressions.
The total time available for production = 1000 hours per week
The time it takes to produce an item on line A = 1 hour
The time it takes to produce an item on line B = 4 hour
Therefore, with both lines working simultaneously, the time it takes to produce 5 items = 4 hours
The number of items produced per the weekly labor = 1000/4 × 5 = 1,250 items
The minimum number of items that can be produced is when only line B is working which produces 1 item per 4 hours, with the weekly number of items = 1000/4 × 1 = 250 items
Therefore, the number of items, x, produced per week with the available labor is given as follows;
250 ≤ x ≤ 1250
Which is revised to 250 ≤ x ≤ 600 as shown in the following answer
(b) The cost of producing a single item on line A = $5
The cost of producing a single item on line B = $4
The total available amount for operating cost = $3,000
Therefore, given that we can have either one item each from lines A and B with a total possible item
When the minimum number of possible items is produced by line B, we have;
Cost = 250 × 4 = $1,000
When the maximum number of items possible, 1,250, is produced, whereby we have 250 items produced from line B and 1,000 items produced from line A, the total cost becomes;
Total cost = 250 × 4 + 1000 × 5 = 6,000
Whereby available weekly outlay = $3000, the maximum that can be produced from line A alone is therefore;
$3,000/$5 = 600 items = The maximum number of items that can be produced
The inequality for the cost, C, becomes;
$1,000 ≤ C ≤ $3,000
The time to produce the maximum 600 items on line A alone is given as follows;
1 hour/item × 600 items = 600 hours
The inequality for the number of items, x, produced by the labor, is therefore, given as follows;
250 ≤ x ≤ 600
Hence the inequality for the number of items, x, produced by the labor, is 250 ≤ x ≤ 600 and the inequality for the cost, C is $1,000 ≤ C ≤ $3,000
To know more about Inequality follow
|y+5|> 2
Answers
Answer:
y>-3 y>-7
Step-by-step explanation:
-(y+5)>2
y<-7
Answers
Answers
Pi is seldom useful as an exponent, and is hardly ever used as one.
If you need to show somebody an example of an exponent, I think
that pi is one of the worst examples you can choose.
4x + 2y = 6
2) 5x + 2y = 12
-6x - 2y = -14
3) 5x + 4y = 12
7x - 6y = 40
4) 5m + 2n = -8
4m + 3n = 2
Answers
y=-2
4x+2(-2)=6
4x-4=6
4x=10
x=5/2
(5/2,-2)
-x=-2
x=2
5(2)+2y=12
10+2y=12
2y=2
y=1
(2,1)
35x+28y=84
-35x+30y=-200
58y=-116
y=-2
5x+4(-2)=12
5x-8=12
5x=20
x=4
(4,-2)
20m+8n=-32
-20m-15n=-10
-7n=-42
n=6
5m+2(6)=-8
5m+12=-8
5m=-20
m=-4
(-4,6)