What is the square root of 3 to the square root of 2 power times the square root of 3 to the negative square root of 2 power?

Answers

Answer 1

Answer: the square root of 3 to the square root of 2 power times the square root of 3 to the negative square root of 2 power = 1

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3D shape practice. I'm stuck in this problem. Pleas help.

Answers

1)we calculate the volume of the right rectangular prism
volume=lenght x width x heigth
volume=12 ft * 8.5 ft * 4 ft=408 ft³

density= mass / volume ⇒ mass=volume * density.
density=0.25 pound /ft³

2) we calculate the mass of the right rectangular prism.
mass=volume * density
mass=408 ft³(0.25 pound / ft³)=102 pounds.

answer: c. 102

What’s the value of c if e^3x+6=8

Answers

Answer:

Step-by-step explanation:

The diagonals of a kite __________.A.
meet at a right angle
B.
are congruent
C.
bisect each other
D.
do not intersect

Answers

The diagonals of a kite meet at 90°. It is filled from A option.

What is diagonal?

It is a line segment which joins two vertices of a shape when those vertices are not on the same edge.

How to find diagonal of a kite?

The shape of a kite is rhombus whose all sides are equal to each other. Because all the sides are equal to each other, the triangles formed by the diagonals of the rhombus are congruent and the angle made on a line is equal to 180 degrees. By dividing the line into two equal parts by bisecting we can find all angles at which the diagonals are bisecting equal to 90 degrees.

Hence the diagonals of a kite meets at a right angle.

Learn more about rhombus at brainly.com/question/20627264

#SPJ2

The diagonals of a kite meet always meet at a right angle and bisect each other perpendicularly, the answer is A.

Y=4x-7 make x the subject of the equation

Answers

Step-by-step explanation:

y=4x-7

y+7=4x

x=y+7

hope it helps.

Find the equation of all tangent lines having slope of -1 that are tangent to the curve y=(9)/(x+1)

Answers

Answer: y = -x + 5 and y = -x - 7 (see attached graph)

Step-by-step explanation:

y = $(9)/(x + 1)$

= 9(x + 1)⁻¹

Use the product rule to find the derivative

a = 9 a' = 0

b = (x + 1)⁻¹ b' = -(x + 1)⁻²

ab' + a'b

= 9[-(x + 1)⁻²] + 0[(x + 1)⁻¹ ]

= $(-9)/((x + 1)^(2))$

Set the derivative equal to the desired slope of -1 to solve for x

-1 = $(-9)/((x + 1)^(2))$

-(x + 1)² = -9

(x + 1)² = 9

√(x + 1)² = √9

x + 1 = +/- 3

x + 1 = 3 x + 1 = -3

x = 2 x = -4

Plug those values into the original equation to solve for y:

y = $(9)/(x + 1)$

= $(9)/(2 + 1)$

= 3

(2, 3)

y = $(9)/(x + 1)$

= $(9)/(-4 + 1)$

= -3

(-4, -3)

Next, plug in the given slope (-1) and the coordinates above into the Point-Slope formula y - y₁ = m(x - x₁) to find the equations:

m = -1, (x₁ y₁) = (2, 3) m = -1, (x₁ y₁) = (-4, -3)

y - 3 = -1(x - 2) y + 3 = -1(x + 4)

y - 3 = -x + 2 y + 3 = -x - 4

y = -x + 5 y = -x - 7

Answer:

$f(x)=\frac9{x+1}\n f'(x)=-\frac9{(x+1)^2}\n f'(x)=-1\ \iff\ -\frac9{(x+1)^2}=-1\ \to \ \frac9{(x+1)^2}=1\ \to \ (x+1)^2=9\n |x+1|=3\ \to \ x+1=3\ \vee\ x+1=-3\n x_1=2\ \vee\ x_2=-4\n f(x_1)=f(2)=\frac9{2+1}=3\n f(x_2)=f(-4)=\frac9{-4+1}=-3$