mike constructed a closed box that measures 2.5 feet long by 3 feet wide by 1.5 feet high. what is the total area of the material mike needs to construct the box??

Answers

Answer 1
Answer: The total area is 2( 2.5*3 +3*1.5 + 2.5*1.5) =2( 7.5 + 4.5 + 3.75) =2*15.75 = 31.5 ;


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Bob has taken out a loan of $15,000 for a term of 48 months (4 years) at an interest rate of 6.5%. Using the amortization table provided, what will be his total finance charge over the course of his loan?Monthly Payment per $1,000 of Principal
Rate 1 Year 2 Years 3 Years 4 Years 5 Years
6.5% $86.30 $44.55 $30.65 $23.71 $19.57
7.0% $86.53 $44.77 $30.88 $23.95 $19.80
7.5% $86.76 $45.00 $31.11 $24.18 $20.04
8.0% $86.99 $45.23 $31.34 $24.41 $20.28
8.5% $87.22 $45.46 $24.65 $24.65 $20.52
9.0% $87.45 $45.68 $31.80 $24.89 $20.76
A.
$355.65
B.
$975.00
C.
$1,682.40
D.
$2,071.20
E.
$17,071.20

Answers

The total finance charge over the course of his loan is $2071.20.

It is required to find the total finance charge.

What is simple & compound interest?

Simple Interest can be defined as the sum paid back for using the borrowed money, over a fixed period of time. Compound Interest can be defined as when the sum principal amount exceeds the due date for payment along with the rate of interest, for a period of time. Formula. S.I. = (P × T × R) ⁄ 100.

Given that:

Loan= $15,000

The table tells you that Bob's monthly payment on a 4-year loan at 6.5% will be 23.71 per thousand borrowed.

The sum of those 48 payments is ...

=48 × $23.71 =

 =$1138.08

That means, Bob pays $138.08 in total finance charge for each $1000 he borrows. He is borrowing 15 times $1000.

so his total finance charge will be

= 15 × $138.08

= $2071.20

Therefore, the total finance charge over the course of his loan is $2071.20.

Learn more about simple & compound interest here:

brainly.com/question/16666364

#SPJ5

Answer:

D.

$2,071.20

Step-by-step explanation:

In ΔPQR, sin P= 3/4, sin R= 2/5, and p=40. Find the exact value of r.

Answers

Hello,

sin (P)/p=sin (R)/r
==>r=sin (P)/(p* sin (R))
r= (3/4)/(40*2/5)
r=3/4 * 5 /(40*2)=(3/4) /16=3/64

To simplify each expression and use positive exponents for m^3n^-6p^0.

Answers

m^(3n) -6 p^(0)
=m^(3n) -6
m^3n^-6p^0 

Use \ Negative \ Power \ Rule x^-^a= (1)/(x^a) 

m^3* (1n)/(6) p^0 

Use \ Rule \ of \ Zero  x^0=1

m^3*1 (1)/(n^6) *1 

\boxed{\boxed{(m^3)/(n^6)}}    Solution


The magnitude and direction of two forces acting on an object are 100100 ​pounds, S7878degrees°​E, and 5050 ​pounds, N5353degrees°​E, respectively. Find the​ magnitude, to the nearest hundredth of a​ pound, and the direction​ angle, to the nearest tenth of a​ degree, of the resultant force.

Answers

Answer:

  138.06 lb N86.1°E

Step-by-step explanation:

There are several ways you can work this. One of the most straightforward is to resolve each vector into its north and east components, add those, and then covert the result back to magnitude and direction.

A diagram can help immensely.

We note that S78°E is the same as E12°S. Since we're used to seeing the coordinate system with the +x axis aligned with east, it can be convenient to think of the first force as 100 lb at -12°.

The angle of the second force is N53°E, which can be expressed as E37°N. Then in x-y coordinates, this force is 50 lb at +37°.

The components of the sum are the sum of the components:

  R = F1 +F2 = (100cos(-12°) +50cos(37°), 100sin(-12°) +50sin(37°))

  = (137.747, 9.300)

The the magnitude of the resultant is computed using the Pythagorean theorem:

  ||R|| = √(137.747² +9.300²) ≈ 138.06

and the angle is computed using the arctangent function. Here, our diagram tells us the angle is in the first quadrant, so is positive (relative to +x, or East).

  ∠R = arctan(9.300/137.747) ≈ 3.9°

__

We want to express the answer in terms similar to the way the given forces are expressed, so we want the angle relative to north. The resultant is then described by ...

  R = 138.06 lb at N86.1°E

Solve each system.
y=2x+6
y= -3x+16

Answers

y=2x+6\ny= -3x+16\n\n2x+6=-3x+16\n2x+6+3x-6=-3x+16+3x-6\n5x=10\ /:5\nx=2\n\ny=2x+6\ \ \ \Rightarrow\ \ \ y=2\cdot2+6=4+6=10\n\nAns.\ \ x=2\ \ and\ \ y=10
y= 2x+6  so therefor ----> x=2 and y=10 

During the lunch break a deli sold 36 large sodas. If the ratio of large sodas sold to small sodas sold was 4:1, how many sodas were sold?

Answers

36/x = 4/1 4x=36 x=9 + 36 = 45
Since for every small soda 4 large sodas were sold U divide 36 by 4. You get 9 so that is the total of small sodas. Then add 9 and 36 and get 45 total sodas. :) hope this helped