CHEMISTRY COLLEGE

A carbon dioxide sample weighing 44.0 g occupies 32.68 l at 65°c and 645 torr. what is its volume at stp?

Answers

Answer 1

Answer:

Combined gas law,

$(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))$

$((645torr)(32.68 L))/(338 K) = ((760 torr)V_(2))/(273 K)$

$v_(2)=22.4 L$

So, the gas will occupy 22.4 L at STP

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1.81 g H2 is allowed to react with 10.2 g N2, producing 2.19 g NH3.What is the theoretical yield in grams for this reaction under the given conditions?3H2(g)+N2(g)→2NH3(g)

Answers

The theoretical yield : = 10.251 g

Further explanation

Given

Reaction

3H₂(g)+N₂(g)→2NH₃(g)

1.81 g H₂

10.2 g N₂

2.19 g NH₃

Required

The theoretical yield

Solution

Find limiting reactant :

H₂ : 1.81 g : 2 g/mol = 0.905 mol

N₂ : 10.2 g : 28 g/mol = 0.364 mol

mol : coefficient

H₂ = 0.905 : 3 = 0.302

N₂ = 0.364 : 1 = 0.364

H₂ as a limiting reactant(smaller ratio)

Moles NH₃ based on H₂, so mol NH₃ :

= 2/3 x mol H₂

= 2/3 x 0.905

=0.603

Mass NH₃ :

= mol x MW

=0.603 x 17 g/mol

= 10.251 g

Calcium and bromine have formed a bond. Leading up to this, calcium gave up electrons. It was a(n)

Answers

Leading up to this, calcium gave up 2 valence electrons and thus was denoted as a cation. These 2 electrons were transferred to bromine, which received an overall negative charge because of the addition of 2 valence electrons in its valence shell, and thus formed a negatively charged ion, an anion.

Both formed an ionic bond, due to the electrostatic charge of attraction between the 2 oppositely charged ions. If many ions of Ca and Br are present and numerous ionic bonds have formed it will undergo an arrangement which is that of an ionic lattice, type of structure.

Ammonia is produced by the reaction of nitrogen and hydrogen: N2(g) + H2(g)  NH3(g)(a) Balance the chemical equation.
(b) Calculate the mass of ammonia produced when 35.0g of nitrogen reacts with hydrogen.

Answers

Answer:

a) N2 (g) + H2 = 2 NH3

b) You have to state the mass of hydrogen

In living organisms, C-14 atoms disintegrate at a rate of 15.3 atoms per minute per gram of carbon. A charcoal sample from an archaeological site has a C-14 disintegration rate of 9.16 atoms per minute per gram of carbon. Estimate the age of this sample in years. The half-life of C-14 is 5730 years. (enter only the number of years in standard notation, not the unit years)

Answers

Rate of disintegration is defined as the time required by a sample or substance at which half of the radioactive substance disintegrates. It depends on the nature of disintegration and amount of substance.

The age of the sample is approximately 4241.17 years.

Given that:

C-14 atoms disintegration rates = 15.3 atom/ min-g

Rate of disintegration of the sample = 9.16 atom/ min-g

The digit proportion of carbon-14 is = $(9.16)/(15.3)$ = 0.5987

Now, also the half-life of carbon-14 is 5730 years.

Such that:

$(1)/(2)^n = \text A$

$(1)/(2) = 0.5987$

Taking log:

n log 2 = -log 0.5987

Thus, n = $(0.227)/(0.3010)$

n = 0.740

The age of the sample can be given by:

Age = n x half-life

Age = 0.740 x 5730

Age = 4241.17 years.

Therefore, the age of the substance is 4241.17 years.

To know more about disintegration rate, refer to the following link:

brainly.com/question/14021442

Answer:

The answer is "4,241 .17 years"

Explanation:

The disintegration rate, which shows in C-14 atoms = $15.3 (atoms)/(min-g)$

Rate of sample disintegration = $9.16 \frac{atoms} {min-gram}$

The digit proportion of C-14 can be determined that is included in the sample $= \frac {9.16}{15.3} \n\n = 0.5987$

5730 years from half-life.

The number with half-lives (n) which are repelled must be determined:

$((1)/(2))^n= A\n\nA= fraction of C-14, which is remaining \n\n((1)/(2))^n= 0.5987 \n\n n \log 2 = - \log 0.5987\n\n$

$\therefore \n\n \Rightarrow n= (0.227)/(0.3010) \n\n = 0.740\n$

So, the age of the sample is given by = $n *\ half-life$

$= 0.740 * 5730 \ years \n\n=4241.17 \ years\n\n$

What is shown by a half-reaction?A. oxidation or reduction of an elementB. neutralization of an ion or moleculeC. decomposition of an ion or moleculeD. none of the above

Answers

Answer

A. oxidation or reduction of an element

Explanation

A half reaction can be either oxidation or reduction reaction from a REDOX reaction.

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