In general, the solubility of ________ in water decreases as temperature increases.

Answers

Answer 1

Answer:

Solubility of a gas in a liquid is directly proportional to the partial pressure of the gas present above the liquid and is inversely proportional to the temperature.

So, the solubility of gas in water decreases as the temperature increases.

Answer 2

Answer:

Answer:

solubility increases

Explanation:

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Consider the following reaction to generate hydrogen gas: Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g) The hydrogen gas is collected by displacement of water at 35.0 °C at a total pressure of 745 torr. The vapor pressure of water at 35.0 °C is 42 torr. Calculate the partial pressure of H2 (in atm) if 353.2 mL of gas is collected over water from this method.

What is the total number of joules released when a 5.00-gram sample of water changes from liquid to solid at 0°C?(1) 334 J (3) 2260 J
(2) 1670 J (4) 11 300 J

Answers

Energy released from changing the phase of a substance from the liquid phase to solid phase can be calculated by using the specific latent heat of fusion. The heat of fusion of water at 0 degrees Celsius is 334 J/g. Calculation are as follows:

Energy = 5 grams x 334 J/g
Energy = 1670 J

Answer:

It’s 2)

Explanation:

210.0 °C a gas has a volume of 8.00 L. What is the volume of this gas at -23.0°C?

Answers

V₁ = 8.00 L

T₁ = 210.0ºC + 273 = 483 K

V₂ = ?

T₂ = - 23.0ºC + 273 = 250 K

V₁/ T₁ = V₂ / T₂

8.00 / 483 = V₂ / 250

483 x V₂ = 8.00 x 250

483 V₂ = 2000

V₂ = 2000 / 483

V₂ = 4.14 L

hope this helps!

When writing an electron configuration for a transition metal, what is the last orbital type to be filled – an s, p, d or f orbital?

Answers

It would be d.

Reason being said...

the electron configuration normally goes like this...

1s2 2s2 2p6 3s2 3p6 4s2....

until you hit the transition metals..remember those have a special rule..

even though you are in the 4 sublevels for the orbitals ... it goes down 1

Making it 3d..(1,2,3,4,5,6,7,8,9,10)

Going on...

at 5s2 then, 4d1, 4d2, 4d3, 4d4, etc..

at 6s2 then, 5d1, 6d2, 6d3, 6d4, etc..

Thus, D orbital is your answer.

Mercury has a specific gravity of 13.6. how many milliliters of mercury have a mass of 0.35 kg

Answers

The formula for specific gravity is:

$Specific gravity = (\rho _(substance))/(\rho _(water))$

where $\rho _(substance)$ is the density of the substance and $\rho _(water)$ is the density of water.

The density of water, $\rho _(water)$ = $1 g/mL$

Substituting the values in above formula we get,

$13.6 = (\rho _(substance))/(1)$

$\rho _(substance) = 13.6 g/mL$

The formula of density is:

$density = (mass)/(volume)$

The density of mercury is $13.6 g/mL$

The mass of mercury is $0.35 kg = 0.35 kg * 1000 (g)/(kg) = 350 g$

Substituting the values in density formula:

$13.6 g/mL = (350 g)/(volume)$

$volume = (350 g)/(13.6 g/mL) = 25.73 mL$

The amount, in milliliters, of mercury that will have a mass of 0.35 kg would be 25.74 mL.

If the specific gravity of mercury is 13.6, the density can be obtained such that:

Density of mercury = specific gravity of mercury/density of water

The density of water is 1 g/mL. Thus:

Density of mercury = 13.6/1

= 13.6 g/mL

Also; density = mass/volume

volume = mass/density

= 350/13.6

= 25.74 mL

Thus, the number of milliliters of mercury that will have a mass of 0.35 kg would be 25.74.

More on density can be found here: brainly.com/question/14940265?referrer=searchResults

Which Kelvin temperature is equal to 200.°C?

Answers

C = Celsius
K = k=Kelvin

C + 273.15 = K
200 + 273.15 = K
473.15 = K

Celsius + 273.15 = temperature in Kelvins

200 + 273.15 = 473.15 Kelvins

Helpppp pleaseee for 15 points

Answers

Answer:

What is filteration:

Filtration, the process in which solid particles in a liquid or gaseous fluid are removed by the use of a filter medium that permits the fluid to pass through but retains the solid particles. ... In some processes used in the production of chemicals, both the fluid filtrate and the solid filter cake are recovered.

Whendoweuseit:

Filtration is used to separate particles and fluid in a suspension, where the fluid can be a liquid, a gas or a supercritical fluid. Depending on the application, either one or both of the components may be isolated.

Inordertoseparateasalt-watermixture,

shouldastudentusefiltration:

The mixture can be separated by filtration, by dissolving the mixture in water. Salt will dissolve in the water, whereas sand will not.

Explanation:

hope it help's. pls mark as the brainliest.Rocket out.

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