Which of the following is not a correct formula? A)Ba2O B)Ca3N2 C)KCl D)Li2S

Answers

Answer 1
Answer:

Answer:- A. Ba_2O is not the correct formula.

Explanations:- Charge for Ba is +2 and charge for O is -2, Here the charges are in equal and opposite so their ratio is 1:1 and hence the formula must be BaO and not Ba_2O.

Rest of the formulas are correct as charge for Ca is +2 and charge for N is -3 . On criss cross we get the formula Ca_3N_2 .

Charge for K is +1 and charge for Cl is -1 and so KCl is correct.

Charge for Li is +1 and that for S is -2. On criss cross we get the formula Li_2S .


Related Questions

Which event must always occur for a chemical reaction to take place?(1) formation of a precipitate(2) formation of a gas(3) effective collisions between reacting particles(4) addition of a catalyst to the reaction system
Why am i not good enough :,(
In the following reaction: Ca+2 + 2Br- ---> BaBr2, which of the reactants is LEO and which is GER?
Which is defined as moles of solute per liter of solution?a. Molarity b. Formality c. Density d. Molality e. Normality
Which object is more dense?!

When a mixture of iron powder and sulphur is heated it glows more brightly than that of iron filings and sulphur.Explain this observation

Answers

Answer:

I don't know

Explanation:

mixture of iron powder and sulphur heated it glows because sulphur and iron are more reactive metals that they shine and sulphur can react with water produce fire it's write

Degradates, unlike their parent compounds, are always completely harmless true or false

Answers

The correct answer fro above statement is:

False

Explanation:

Some elements in the atmosphere start the body and are consistent when they are dropped. Others are diminishing. Degradation stocks may be more lethal or less virulent than the first chemical. Other chemicals are deposited momentarily in the organs and are discharged shortly after. After a while, most chemicals and degradation stocks are ordered of as body waste, in the stool, urine, sweat and breathed air.

Answer:

false

Explanation:

The standard enthalpy change for the reaction of SO3(g) with H2O(l) to yield H2SO4(aq) is ΔH∘ = -227.8 kJ . Use the following information S(s)+O2(g)→SO2(g), ΔH∘ = -296.8kJ SO2(g)+12O2(g)→SO3(g) , ΔH∘ = -98.9kJ to calculate ΔH∘f for H2SO4(aq) (in kilojoules per mole). [For H2O(l),ΔH∘f = -285.8kJ/mol].

Answers

Answer:

-909.3KJ/mole

Explanation:

The heat of reaction is accessible from the heat of formation of reactants and products using the formula below:

ΔH = Σ ΔHf products - Σ ΔHf reactants

Before we proceed, it is important to know that the enthalpy of formation of element is zero ,be it a single element or a molecule of an element.

From the reaction for the formation of sulphuric acid, we know we need to know the heat of formation of sulphur (vi) oxide and water. The examiner is quite generous and have us for water already.

Now we need to calculate for sulphur (vi) oxide. This is calculated as follows:

We first calculate for sulphur(iv)oxide. This can be obtained from the reaction between sulphur and oxygen. The calculation goes thus:

ΔH = Σ ΔHf products - Σ ΔHf reactants

ΔH = [ 1 mole suphur(iv) oxide × x] - [ (1 mole of elemental sulphur × 0) + (1 mole of elemental oxygen × 0]

We were already told this is equal to -296.8KJ. Hence the heat of formation of sulphur(iv) oxide is -296.8KJ.

We then proceed to the second stage.

Now, here we have 1 mole sulphur (iv) oxide reacting with 0.5 mole oxygen molecule.

We go again :

ΔH = Σ ΔHf products - Σ ΔHf reactants

ΔH = [ 1 mole of sulphur (vi) oxide × y] - [ (1 mole of sulphur (iv) oxide × -296.8) + (0.5 mole of oxygen × 0)].

We already know that the ΔH here equals -98.9KJ.

Hence, -98.9 = y + 296.8

y = -296.8KJ - 98.9KJ = -395.7KJ

We now proceed to the final part of the calculation which ironically comes first in the series of sentences.

Now, we want to calculate the standard heat of formation for sulphuric acid. From the reaction, we can see that one mole of sulphur (vi) oxide, reacted with one mole of water to yield one mole of sulphuric acid.

Mathematically, we go again :

ΔH = Σ ΔHf products - Σ ΔHf reactants

ΔH = [ 1 mole of sulphuric acid × z] - [( 1 mole of sulphur vi oxide × -395.7) + ( 1 mole of water × -285.8)].

Now, we know that the ΔH for this particular reaction is -227.8KJ

We then proceed to to open the bracket.

-227.8 = z - (-395.7 - 285.8)

-227.8 = z - ( -681.5)

-227.8 = z + 681.5

z = -227.8-681.5 = -909.3KJ

Hence, ΔH∘f for sulphuric acid is -909.3KJ/mol

Which subatomic particle will be attracted by a positively charged object?(1) proton (3) electron
(2) neutron (4) positron

Answers

The subatomic particle which will be attracted by a positively charged object is: Choice 3: Electrons.

By law of electricity; like charges repel while unlike charges attract.

In essence, the subatomic particle which will be attracted to a positively charged object is a negatively charged particle.

Since, protons are positively charged, neutrons have no charge, positrons are positively charged but electrons are negatively charged,

The subatomic particle which will be attracted by a positively charged object is; Electron.

Read. more:

brainly.com/question/10045946

(1) Protons have a positive charge, so will be repelled by other positive charges
(2) Neutrons have no charge, so won't be affected by positive charges
(3) Electrons have a negative charge, so will be attracted by a positive charge
(4) Positrons have a positive charge, so will be repelled by other positive charges

The answer is (3)

What process causes dissolved substances to be left behind to form minerals after water in lakes or ponds evaporates?

Answers

well in this case its percipitation rain hail sleet snow  itll set like water after so long it dissolve itll turn into gases

Draw .. the structural formula ( using c and h ) for 2- pentyne

Answers

Answer : The structural formula of 2-pentyne is shown below.

Explanation :

Structural formula : In the structural formula, the bonding and type of bonds which holds the atoms in molecule together are shown.

The given name of compound is, 2-pentyne.

A suffix '-yne' present at the end of the name represent the alkyne group.

For the number of carbon atom, we use prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.

In this compound, the parent chain is 5 membered and a triple bond is present at 2nd position of the parent chain.

Thus, the structural formula of 2-pentyne is shown below.

answer is below.........