MATHEMATICS COLLEGE

Rita's graduation picnic will cost $3 for every attendee. At most how many attendees can there be if Rita only budgets a total of $87 dollars for her graduation picnic?

Answers

Answer 1
Answer:

To figure out how many attendees Rita can have at her picnic, we must divide the total amount that she has in her budget for her graduation picnic ($87) by the cost for every attendee ($3).

$87/$3 = 29

Therefore, Rita can have at most 29 attendees if Rita has the above cost parameters.

Hope this helps!

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X/2 + 5= -8 what does x equal and show work

Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm) is summarized in the GFDT below. Lengths (mm) Frequency
140 - 143 1
144 - 147 16
148 - 151 71
152 - 155 108
156 - 159 83
160 - 163 18
164 - 167 3

What is the class boundary between the sixth and seventh classes?

Answers

Answer:

Class Boundary = 1 between the sixth and seventh classes.

Step-by-step explanation:

              Lengths (mm)                   Frequency

1.                  140 - 143                                  1

2.                 144 - 147                                 16

3.                 148 - 151                                 71

4.                 152 - 155                              108

5.                 156 - 159                               83

6.                 160 - 163                                18

7.                  164 - 167                                 3

The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.

Therefore the class boundary between the sixth and seventh classes

= 164 - 163  = 1

Therefore Class Boundary = 1.

It can be seen that class boundary for the frequency distribution is 1.

If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.

Therefore, Class width,

w = lower limit of second class - lower limit of first class

   = 144 - 140

   = 4

A part-time shelf stocker made $8912.03 last year. If she claimed herself asan exemption for $3650 and had a $5700 standard deduction, what was her
taxable income last year?
A. $5262.03
B. $437.97
C. $0
D. $3212.03

Answers

Final answer:

The part-time shelf stocker's taxable income is calculated by subtracting the exemption of $3650 and the standard deduction of $5700 from her annual income of $8912.03, resulting in a negative number, which means her taxable income was $0.

Explanation:

To calculate the taxable income for the part-time shelf stocker who made $8912.03 last year, we need to subtract the exemption and standard deduction from her annual income. The exemption claimed is $3650, and the standard deduction is $5700.

Here's the calculation:

  1. Start with the total annual income: $8912.03.
  2. Subtract the exemption amount: $8912.03 - $3650 = $5262.03.
  3. Subtract the standard deduction: $5262.03 - $5700 = -$437.97.

Since the taxable income cannot be negative, the correct answer is $0. Thus, her taxable income last year was $0.

Learn more about Taxable Income Calculation here:

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Answer: C) $0

Step-by-step explanation:

Demon slayer

A restaurant offers a dinner special that has 12 choices for entrees, 10 choices for side dishes, and 6 choices for dessert. How many different meals are possible?

Answers

there are 720 meal possibilities.

If anyone can help that would be great!

Answers

Answer:

-120/119

Step-by-step explanation:

cos α = -5/13 = adj/hyp

using Pythagoras theorem

hypotenuse ² = opposite² + adjacent ²

13² =opp²+ (-5)²

169 = opp² + 25

169-25 = 144 = opp²

opp = √144 = 12

sinα = opp/hyp = -12/13

sin β = -12/13

tan(α+β) = (tanα + tanβ)/ (1-tanαtanβ)

cos α = -5/13

sinα = 12/13

tanα= sinα/cosα = 12/13 / -5/13 = 12/-5 = -12/5

sin β = -12/13

cos β = 5/13

tan β = sinβ/cosβ = -12/13 / 5/13 = -12/5

tan(α+β) = (tanα + tanβ)/ (1-tanαtanβ)

tanα = -12/5

tanβ= -12/5

tan(α+β) = (tanα + tanβ)/ (1-tanαtanβ) = (-12/5+(-12/5))/(1-(-12/5)(-12/5))

(-12/5+(-12/5)) = -12-12/5 = -24/5

(1-(-12/5)(-12/5)) = 1-(144/25) = (25-144)/25 = 119/25

tan(α+β) = (tanα + tanβ)/ (1-tanαtanβ) = (-12/5+(-12/5))/(1-(-12/5)(-12/5)) =-24/5/119/25 = -24/5 x 25/119 = -24x5/119 = -120/119

Based on the data, select the most reasonable prediction about the height ofsecond-grade students.A. The typical second-grade student is less than 45 inches tall.B. The typical second-grade student is about 45 inches tall.C. The typical second-grade student is more than 50 inches tall.D. The typical second-grade student is about 48 inches tall.

Answers

second-gradeWe are given the following data set:

44,45,47,49,48,48,49,50,48,52

We can calculate the mean of this data set, by adding all the terms and dividing by the number of terms, that is 10:

\text{mean}=(44+45+47+49+48+48+49+50+48+52)/(10)=(480)/(10)=48

Since the mean is 48 this means that the typical second grade student is 48 inches tall. the right answer would be D.

What does the expression (8x)2 represent

Answers

Option D is correct.

We have an expression that is used to calculate the area of a square - s^(2), where s is the side of the square.

We have to estimate the value of the expression(8x)^(2)

What is the area and perimeter of a square of side 'a' ?

The area of a square is - Area = a^(2) and the perimeter is - P  = 4a.

In the question, we have to estimate the value of the expression (8x)^(2).

Let f(x) = (8x)^(2)

The expression given to us is s^(2).

Let f(s) = s^(2)

Compare f(s) and f(x), you will get -

s = 8x

Hence, the expression (8x)^(2) represents the area of square with side length of 8x.

Hence, Option D is correct.

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Answer:

option d

Step-by-step explanation:

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