Input numbers have been changed by a rule to get output numbers which of these could be the rule for changing the input numbers to the output numbers? Input: 3,6,9. Output:4,5,6.

Answers

Answer 1
Answer:

Changes in output are evenly spaced for evenly spaced changes in input, so the rule is linear. Changes in output are 1 for changes in input of 3, so the rule involves a factor of 1/3. One possible rule is

... output = (1/3)·input + 3

If y and x are used to represent output and input, respectively, this is

... y = (1/3)x + 3


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Forty-five CEO’s from the electronics industry were randomly sampled and a 99 % % confidence interval for the average salary of all electronics CEO’s was constructed. The interval was $101,866<μ<$115,016 $101,866<μ<$115,016 To make more useful inferences from the data, it is desired to reduce the width of the confidence interval. What will result in a reduced interval width? Select one: a. Any of these methods will result in a reduced interval width. b. Keep the sample size the same and decrease the confidence level. c. Keep the sample size the same and increase the confidence level. d. Decrease the sample size and keep the same confidence level.

Answers

Answer:

b. Keep the sample size the same and decrease the confidence level.

Step-by-step explanation:

We first have to find the critical value of z, which depends of the confidence level.

90% confidence level

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = (1-0.9)/(2) = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

99% confidence level

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = (1-0.99)/(2) = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

The width of the interval is:

W = z*(\sigma)/(√(n))

In which \sigma is the standard deviation of the population and n is the size of the sample.

So, as z increses, so does the width. If z decreases, the width decreases. Lower confidence levels have lower values of z.

As n increases, the width decreses.

What will result in a reduced interval width?

b. Keep the sample size the same and decrease the confidence level.

The best fit line is given by the equation y=0.5x+0.4, where y represents the distance in miles, and x represents the time for the trip in minutes.

Use the best fit line to estimate the distance for a trip that takes 20 minutes.

Enter your response in the box. Give the answer to the tenths place.

miles

Answers

Answer:

The anwser is 10.4

Step-by-step explanation:

0.5(20)+0.4

2(x – 9) = 10x + 11
Help

Answers

Answer:

exact form: -28/8

decimal form: -3.625

mixed number form: -3 5/8

Answer:

x = -3.625

Step-by-step explanation:

There are 3 bags each containing 100 marbles. Bag 1 has 75 red and 25 blue marbles. Bag 2 has 60 red and 40 blue marbles. Bag 3 has 45 red and 55 blue marbles. Now a bag is chosen at random and a marble is also picked at random. 1) What is the probability that the marble is blue? 2) What is the probability that the marble is blue when the first bag is chosen with probability 0.5 and other bags with equal probability each? Make sure to clearly define your probabilistic events and mathematically show how different probability laws and rules that you learned in class could be applied to solve the problems.

Answers

Answer:

0.4 ; 0.6125

Step-by-step explanation:

Given the following :

Bag 1 : 75 red ; 25 blue

Bag 2: 60 red ; 40 blue

Bag 3: 45 red ; 55 blue

Probability = (required outcome / Total possible outcomes)

A) since the probability of choosing each bag is equal :

BAG A:

P(choosing bag A) = 1 / total number of bags = 1/3 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100

HENCE, choosing a blue marble from bag A : = (1/3 × 75/100) = 25/300

BAG B:

P(choosing bag B) = 1/3 ;

P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100

HENCE, choosing a blue marble from bag A : = (1/3 × 40/100) = 40/300

BAG C:

P(choosing bag C) = 1/3

P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100

HENCE, choosing a blue marble from bag A : = (1/3 × 55/100) = 55/300

= (25/300) × (40/300) × (55/300) = (25 + 40 + 55)/300 = 120/300 = 0.4

2) What is the probability that the marble is blue when the first bag is chosen with probability 0.5 and other bags with equal probability each?

BAG A:

P(choosing bag A) = 0.5 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100

HENCE, choosing a blue marble from bag A : = (0.5 × 75/100) = (0.5 * 0.75) = 0.375

BAG B:

P(choosing bag B) = (1-0.5) / 2 = 0.25 ;

P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100

HENCE, choosing a blue marble from bag A : = (0.25 × 40/100) = (0.25 × 0.4) = 0.1

BAG C:

P(choosing bag C) = (1 - (0.5+0.25)) = 0.25

P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100

HENCE, choosing a blue marble from bag A : = (0.25 × 55/100) = 0.25 × 0.55 = 0.1375

= 0.1375 + 0.1 + 0.375 = 0.6125

Evaluate the expression 28C14

Answers

For choose notation, you...
xCy = x! / (x-y)! y!
! means factorial

(28 x 27 x 26...x 3 x 2 x 1)/(14 x 13 x 12...x 3 x 2 x 1)(14 x 13 x 12...x 3 x 2 x 1) = 40116600

Write 1/10 as a decimal number

Answers

Answer:

0.1

Step-by-step explanation:

hope this helps