Find the perimeter and area. (plz help with the answer)
Find the perimeter and area. (plz help with the answer) - 1

Answers

Answer 1
Answer:

Hello!

PERIMETER:

To find the perimeter of the trapezoid, simply add all sides together.

15 + 5 + 9 + 5 = 34

The perimeter is \boxed{ \bf 34~units.}

____________________________________________________________

AREA:

A = (1)/(2) h(b_(1) + b_(2))

A = (1)/(2) 4(9 + 15)

A = (1)/(2) 4(24)

A = 2(24)

A = 48

The area of the trapezoid is\boxed{ \bf 48~units^2}


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What is 41/70 in simplest form

Answers

Since the numerator of the fraction is prime, and not a factor of the denominator, the proper fraction 41/70 is already expressed in its simplest form.
it is already 41 / 70 so its a proper fraction

What is the product of 6 x 107

Answers

6x107=642 happy to help
107
x 6
------
642
Just use a calculator, it is faster

How do you find out if something is as likely as not?

Answers

Well if the definition is very probably then it should be easy.

What is 97.356 in base ten numerals

Answers

97.356

ninety seven and three hundred fifty six thousandths

How many ways can 3 students be chosen from a class of 20 to represent their class at a banquet?

Answers

Slot method 20 options 3 slots First slot: 20 options Second slot: 19 options (one used up for 1st slot) Third slot: 18 (one less than last) Multiply them 20 times 19 times 18=6840 Answer is 6840 ways
60 ways because the easy way to solve this problem is identify the numbers being used and than multiply them by each other.

Su has 5 times as many marbles as Bertha. When Su gives Bertha 10 marbles, they have the same amount. How many marbles did they EACH have at the begining? How many did they EACH have at the end?

Answers

Answer:

Part A)

The number of marbles that Su has at the beginning is 25

The number of marbles that Bertha has at the beginning is 5

Part B)

The number of marbles that Su has at the end is 15

The number of marbles that Bertha has at the end is 15

Step-by-step explanation:

Let

x------> number of marbles that Su has at the beginning

y------> number of marbles that Bertha has at the beginning

we know that

x=5y ----> equation A

x-10=y+10 ----> equation B

substitute equation A in equation B

(5y)-10=y+10

4y=20

y=5

Find the value of x

x=5(5)=25

Part A) How many marbles did they EACH have at the begining?

The number of marbles that Su has at the beginning is 25

The number of marbles that Bertha has at the beginning is 5

Part B) How many did they EACH have at the end?

x-10=y+10

so

25-10=5+10

15=15

therefore

The number of marbles that Su has at the end is 15

The number of marbles that Bertha has at the end is 15