The ratio of oxygen to carbon by mass in carbon monoxide is 1.33:1.00. part a find the formula of an oxide of carbon in which the ratio by mass of oxygen to carbon is 2.00:1.00.
Answers
To calculate the molecular formula, convert the mass ratio into molar ratio as follows:
mass ratio of O:C=2:1
molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus, number of moles can be calculated as follows:
n=\frac{m}{M}
calculating ratio,
O:C=\frac{2 g}{16 g/mol}:\frac{1 g}{12 g/mol}=\frac{1}{8}:\frac{1}{12}=12:8=3:2
thus, molecular formula will be C_{2}O_{3}
Final answer:
If the ratio of oxygen to carbon by mass is 2.00:1.00, the formula of the oxide of carbon is CO₂ (carbon dioxide). This is because CO₂ has twice as much oxygen per amount of carbon as compared to CO (carbon monoxide). This situation adheres to the law of multiple proportions.
Explanation:
This question revolves around the concept of stoichiometry in chemistry, particularly in relation to the law of multiple proportions and finding the formula of an oxide of carbon given specific mass ratios.
Firstly, in carbon monoxide (CO), the ratio of oxygen to carbon by mass is 1.33:1.00.
However, when the ratio of oxygen to carbon by mass increases to 2.00:1.00, we are now dealing with a compound that contains twice as much oxygen per amount of carbon. In essence, this would be carbon dioxide (CO₂). The mass ratio of oxygen to carbon in CO₂ is indeed 2:1 (32 g/mol oxygen: 12 g/mol carbon).
This situation illustrates the law of multiple proportions - in this case, the two oxides of carbon (CO and CO₂) contain elements combined in ratios of small whole numbers.
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I REALLY NEED HELP WITH THIS CHEMESTRY PROJECT. I DO NOT UNDERSTAND ANYTHING OF THIS. CAN YOU GUYS PLZ HELP ME?Problem: You and your team work at Southern Nevada Water Authority and have been given the job of managing fluoride levels for the municipal water system. Today, you will need to measure the mass of the mineral sample fluorite (chemically, CaF2). Use this sample to determine how much water must be added to yield a 1 ppm fluoride solution. Your supervisor is requesting tanker trucks to bring the excess water. He needs to know how many tanker trucks to request and the total cost.Notes: 1 mol CaF2 = 78.08 g CaF2 = 6.02 x 1023 molecules of CaF21 molecules of CaF2 = 2 atoms of F1 mol H2O = 18 g H2O Density of water is 1 g/mL1000 mL = 1 L and 3.78 L = 1 gallonmass of sample of CaF2 = 287.185 g1 part per million = 1 atom of fluorine per 999,999 water molecules. 1 truck can carry 12,800 litters of water at a cost of $2,852.42 dollars.Before you begin mixing a solution of fluorite and water your team must first calculate the amount of water you will need. Your team will create a presentation that will show all of the necessary calculations to ensure that the greater Las Vegas area will have cavity free teeth. The presentation should include the following information:- Draw a diagram that points out the basic design of the water system and transport.- Demonstrate the following calculations (a) Calculate how many moles of mineral fluorite (CaF2) are in you sample. (b) Calculate the number of fluorine atoms in the sample of the mineral fluorite (CaF2). (b) Calculate how many molecules of water you will need. (c) Calculate the number of gallons of water that are needed to dissolve a 287.185 gram sample of fluorite to yield 1ppm solution.(e) How many trucks will be needed? Show your calculations!(f) what is will be the total cost?- Bonus points for creativity or “WOW” factor (i.e. pictures, color, neatness)!
Answers
?? --------------- 10 J
10 x 1 / 1000 => 0.01 Kj
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Answer:
It is 33.8.
Explanation:
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Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1.
where:
n - a number of half-lives
x - a remained fraction of a sample
2.
where:
t - total time elapsed
n - a number of half-lives
The half-life of Sr-90 is 28.8 years.
So, we know:
t = 87.3 years
We need:
n = ?
x = ?
We could first use the second equation, to calculate n:
If:
Then:
⇒
⇒
⇒ n ≈ 3
Now we can use the first equation to calculate the remained amount of the sample.
⇒
⇒
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For example,
"Which of the following molecules is expected to have one or more unpaired electrons? Check all that apply.
O2-
F2+
N22-
O22-"
Any help would be appreciated. ...?
Answers
Final answer:
To determine unpaired electrons, look at the valence electrons in an ion's molecule, accounting for extra or absent electrons due to the ion's charge. For instance, O2- and F2+ have one unpaired electron, but N22- is not a valid ion, and O22- electrons are all paired.
Explanation:
To determine if a molecular ion will have one or more unpaired electrons, we need to look at the number of valence electrons in the molecule and take into account any extra or absent electrons due to the charge of the ion.
For example, O2- has 12 + 1 = 13 valence electrons (6 from each oxygen atom and 1 extra due to the negative charge). It requires 14 for all the electrons to be paired (2 in each oxygen's inner shell and 4 bonds or lone pairs in the outer shell), thus there is one unpaired electron in O2-.
However, in F2+, there are only 13 electrons because one electron is lost due to the positive charge. Like oxygen, fluorine also prefers to have 7 electrons in its outer shell, so there are also unpaired electrons in F2+.
N22- doesn’t exist because nitrogen normally forms triple bond and doesn’t need or want to take extra electrons, so this molecular ion is not valid.
O22- has 14 + 2 = 16 valence electrons and this total number of valence electrons is an even number, which indicates all the electrons are paired.
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b. the presence of air
c. the presence of soil
d. the presence of trees