MATHEMATICS HIGH SCHOOL

∆STV ~ ∆PQR. Find m∠P.129

9

86

6

Answers

Answer 1

Answer:

Answer: $86^(\circ)$

Step-by-step explanation:

Given : $\triangle{STV}\sim\triangle{PQR}$

We know that the corresponding angles of two similar triangles are congruent.

i.e. $\angle{S}\cong\angle{P}$ (1)

$\angle{T}\cong\angle{Q}$

$\angle{V}\cong\angle{R}$

From the given picture , we have $\angle{S}=86^(\circ)$

Then from (1), $\angle{P}=86^(\circ)$

Hence, $\angle{P}=86^(\circ)$

Answer 2

Answer:

m < P = m < S becuase the triangles are similar.

m < P = 86 degrees

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74 3/5 + 19 2/3 = Please Explain

Answers

Ok 74 $(3)/(5)$
So 19 $(2)/(3)$

= 373/5 + 59/3

= ((373 × 3) + (59 × 5)) / (5 × 3)

= (1119 + 295) / 15

= 1414/15

= 1414/15

= 94 4/15

74 3/5 + 19 2/3
74+19= 93
for 3/5+2/3 we need a common denominator which in this case would be 15 (the product of the two already existing denominators)
3x3=9 (the 3s are first numerator and the second denominator) so the first fraction is 9/15
5x2=10 (the first denominator and the second numerator) so the second fraction would be 10/15
9+10=19 (the numerators in both fractions) so it's 19/15 which we convert to a mixed numeral which is 1 4/15
93+1 4/15=94 4/15

hope this helps :)

The terminal speed for a person parachuting (with the chute open) is abouta. 0 km/h.
b. 15 km/h.
c. 150 km/h.
d. 1500 km/h.

Answers

The terminal speed for a person parachuting with the chute open is about
15 km/h.

Hope this helped! :)

Shane has a segment with endpoints C(3, 4) and D(11, 3) that is divided by a point E such that CE and DE form a 3:5 ratio. He knows that the distance between the x-coordinates is 8 units. Which of the following fractions will let him find the x-coordinate for point E?a. $(3)/(5)$ b. $(5)/(3)$
c. $(3)/(8)$
d. $(5)/(8)$

Answers

B=5/3 is the answer.........

Zach brought two jet skis for $15,480 He will make 36 equal payments. How much will each be?

Answers

15,480 divided into 36 payments is $430 per payment

He will pay $430 each for his jet skis.

You read that a statistical test at the a 0. 01 level has probability 0. 14 of making a type ii error when a specific alternative is true. What is the power of the test against this alternative?

Answers

The power of the test against the specific alternative is given by 1 minus the probability of making a Type II error. Therefore, the power is 0.86= 86%

In statistical hypothesis testing, the power of a test is the probability that it correctly rejects a null hypothesis when a specific alternative hypothesis is true. In this case, we are given that the test has a significance level of α = 0.01, which means that the test rejects the null hypothesis if the probability of obtaining the observed result, or one more extreme, under the null hypothesis is less than 0.01.

However, we also know that when a specific alternative hypothesis is true, the test has a probability of making a Type II error of 0.14. This means that there is a 14% chance that the test fails to reject the null hypothesis, even though the alternative hypothesis is true.

Therefore, the power of the test against this specific alternative hypothesis is given by 1 minus the probability of making a Type II error, which is:

Power = 1 - P(Type II error) = 1 - 0.14 = 0.86

So, the power of the test against the specific alternative hypothesis is 0.86 or 86%. This means that when the alternative hypothesis is true, the test correctly rejects the null hypothesis 86% of the time.

To learn more about probability Click here:
brainly.com/question/30034780

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Write the equation of the line with a slope of 3 passing through the point (4,10)