MATHEMATICS COLLEGE

Find the y intercept of the straight line with the following equations y=7+3x

3y=6x+12

Answers

Answer 1

Answer:

y = 7 + 3x

y = 3x + 7

y = mx + b, therefore the y-intercept is 7.

3y = 6x + 12

y = 2x + 4

y = mx + b, therefore the y-intercept is 4.

Related Questions

Which of these is the triangle proportionality theorem? First person to answer CORRECTLY gets brainliest
Q # 18,Graph the inequality on a coordinate plane, - y < 3 x - 5
Jenny cut a wire into 4 equal pieces. The wire was originally 7.92 meters long. How long is each piece?
Question part points submissions used two cars start moving from the same point. one travels south at 32 mi/h and the other travels west at 24 mi/h. at what rate is the distance between the cars increasing three hours later? mi/h
More on the Leaning Tower of Pisa. Refer to the previous exercise. (a) In 1918 the lean was 2.9071 meters. (The coded value is 71.) Using the least-squares equation for the years 1975 to 1987, calculate a predicted value for the lean in 1918. (Note that you must use the coded value 18 for year.)

A circle is divided into 6 equal parts. What is the angle measure of 1 part?

Answers

The angle measure of one part will be 60.

360/6 = 60

That is because the circle it divided into 6 equal parts and the whole circle is 360.

Hope this helps :)

Pleaseee help last question

Answers

P(Larger or blue) = 7/10. In a bag we have blue and red marbels, which are large and small as in the table shown in the image, the probability of taking a large or blue marble is 7/10.

The key to solve this problem is find the probability of the union events using the equation P(A∪B) = P(A) + P(B) - P(A∩B).

For this problem we have P(Large or Blue) = P(Large) + P(Blue) - P(Large and Blue). The total of the large ones is 25 and the small ones is 15, meaning that the sum of both is 40. P(large) = 25/40, P(Blue) 20/40, and P(Large and Blue) = 17/40

P(Large or Blue) = 25/40 + 20/40 - 17/40 = 28/40 dividing by 4 both terms of the fraction.

P(large or Blue) = 7/10

A random survey of teachers found that 224 of 395 elementary school teachers, and 126 of 266 high school teachers, were very satisfied with their work. Find a 95% confidence interval for the difference (elementary minus high school) in proportions of teachers who are very satisfied with their work.

Answers

Answer: 95% confidence interval would be (0.013,0.167).

Step-by-step explanation:

Since we have given that

survey of teachers found that 224 of 395 elementary school teachers,

So, n₁ = 395

x₁ = 224

So, $p_1=(224)/(395)=0.567$

n₂ = 266

x₂ = 126

So, $p_2=(x_2)/(n_2)=(126)/(266)=0.473$

At 95% confidence level, z = 1.96

So, interval would be

$(p_1-p_2)\pm z\sqrt{((p_1(1-p_1))/(n_1)+(p_2(1-p_2))/(n_2)}}\n\n=(0.567-0.473)\pm 1.96\sqrt{(0.567* 0.433)/(395)+(0.527* 0.473)/(266)}}\n\n=0.09\pm 1.96* 0.0394\n\n=0.09\pm 0.077\n\n=(0.09-0.077,0.09+0.077)\n\n=(0.013,0.167)$