The ratio of squirrels to chipmunks in the yard was 2:7. How many squirrels were in the yard if there were 49 chipmunks?Explain please.

Answers

Answer 1

Answer: Let the number of squirells be 2x and number of chipmunks be 7x ,

Given that number of chipmunks is 49, so

= > 7x = 49

= > x = 49 / 7

= > x = 7

So the number of squirells will be 2x = 2( 7 ) = 14

$\bold{There \: were \: 14 \: squirells \: in \: the \: yard}$

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Answers

Step-by-step explanation:

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Answers

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$\begin{gathered} -x\leq15-2x \n 2x-x\leq15 \n x\leq15 \end{gathered}$

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$(-\infty,15\rbrack$

1. Trapezoid BEAR has a height of 8.5 centimeters and parallel bases that measure 6.5 centimeters and 11.5 centimeters. To the nearest square centimeter, find the area of the trapezoid.Area of trapezoid BEAR = ___________ square centimeters

2. Regular pentagon PENTA has side lengths that are 9 meters long. To the nearest square meter, find the area of the pentagon.

Area of pentagon PENTA = _____square centimeter

Answers

Given

1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.

2) Regular pentagon PENTA with side lengths 9 m

Find

The area of each figure, rounded to the nearest integer

Solution

1) The area of a trapezoid is given by

... A = (1/2)(b1 +b2)h

... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77

The area of BEAR is about 77 cm².

2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...

... A = (1/2)ap

... A = (1/2)(s/(2tan(180°/n)))(ns)

... A = (n/4)s²/tan(180°/n)

We have a polygon with s=9 and n=5, so its area is

... A = (5/4)·9²/tan(36°) ≈ 139.36

The area of PENTA is about 139 m².

Answer:139 cm squared

The area of a trapezoid is given by

... A = (1/2)(b1 +b2)h

... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77

The area of BEAR is about 77 cm².

The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...

... A = (1/2)ap

... A = (1/2)(s/(2tan(180°/n)))(ns)

... A = (n/4)s²/tan(180°/n)

We have a polygon with s=9 and n=5, so its area is

... A = (5/4)·9²/tan(36°) ≈ 139.36

The area of PENTA is about 139 m².

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Answers

10×10=100

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