MATHEMATICS MIDDLE SCHOOL

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Key features of Graphs
Please help!!!!! Key features of Graphs - 1

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Answer 1
Answer: The graph is **increasing on the interval (-2, 1)**because the graph has a positive slope from x=-2 to x=1. It’s **decreasing at the intervals (-infinity, -2) and (1, infinity)**because the graph has a negative slope between the x values -infinity to -2 and is also decreasing between the x values of 1 and infinity.

Related Questions

Find the next three term in the sequence-8, 24,-72,216
A 30-30-120 isosceles triangle has two legs of length 4 units. If it is rotated around an axis that contains one leg, what is the volume of the solid of revolution?
Write the ratio 54 inches to 7 feet as a fraction in simplest form.
Find the measure for angle A.
Show your work 25.04×3.005

Z - 2/3 = 1/8

Please Help!!!

Answers

The answer would be Z=19/24 because 1/8 plus 2/3 equals 19/24. To get that, first find the LCM.The LCM is 24. Make all denominators 24. 1/8 times 3 equals 3/24, so keep that in mind, and next 2/3 times 8 equals 16/24. Now do addition, 16 plus 3 equals 19, so there's your answer. 19/24.

What is the solution to 5x−2=13 ? Plot the solution on the number line.

Answers

Answer:

x= 3

Step-by-step explanation:

5x-2=13 - Add 2 to both sides which cancels out the -2 and turns 13 into 15

5x=15 - Divide 5 on both sides which cancels the 5 and leaves x=3

x=3 - Is the final answer or the solution to the problem

Line segment AB has endpoints A(2, 9) and B(5, 8) . A dilation, centered at the origin, is applied to AB¯¯¯¯¯ . The image has endpoints A′(43, 6) and B′(103, 163) . What is the scale factor of this dilation? 32
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Answer:  The correct option is (B) (2)/(3).

Step-by-step explanation:  Given that the co-ordinates of the end-points of a line segment AB are A(2, 9) and B(5, 8). After being dilated about the origin (0, 0), the co-ordinates of the end-points of image A'B' are A^\prime\left((4)/(3),6\right) and B^\prime\left((10)/(3),(16)/(3)\right).

We are to find the scale factor of the dilation.

The scale factor of the dilation will be

S=\frac{\textup{length of the image line}}{\textup{length of the original line}}.

The lengths of the lines AB and A'B' are calculated using distance formula as follows:

AB=√((5-2)^2+(8-9)^2)=√(9+1)=√(10),\n\n\nA'B'=\sqrt{\left((10)/(3)-(4)/(3)\right)^2+\left((16)/(3)-6\right)^2\right)}=\sqrt{4+(4)/(9)}=\sqrt{(40)/(9)}=(2)/(3)√(10)~\textup{units}.

Therefore, the required scale factor of dilation is

S=(A'B')/(AB)=((2)/(3)√(10))/(√(10))=(2)/(3).

Thus, the scale factor of the dilation is (2)/(3).

Option (B) is CORRECT.
the answer is 2/3 
i took the test
hope this helps!

on a scale drawing, the scale is inch = 1 foot. What are the dimensions on the scale drawing for a room that is 15 feet by 16 feet?

Answers

Answer:

15 inches by 16 inches

OR

1 foot 3 inches by 1 foot four inches

F(x)=x^3+3g(c)=x^2+2
Approximate the solution to the equation f(x)=g(x) using three iterations of successive approximation. Use this graph as a starting point. (It’s not x= -7/8)

In the graphing tool, choose the custom option in the Relationship menu to graph the functions f(x) = x^3 + 3 and g(x) = x^2 + 2.

Adjust the zoom level of the graph so you can see the point where the two graphed functions intersect. Then, left-click on the point where the functions intersect. The values of the point you click on, rounded to the nearest hundredth, will appear for about 2 seconds.

Note: If you’re not using a mouse (or a mouse with left-click ability), perform the equivalent zoom-in action on your device to see the intersection point values rounded to the nearest hundredth.

Then, approximate (to the nearest hundredth) the solution of f(x) = g(x) from part A of this question.

15 points PLZZZZZ URGENTTT! Urgent maximum wait is 24 hours!

Answers

Answer:

  (a)   -3/4

  (b)  -0.75

  (c)  -0.75

Step-by-step explanation:

It's a bit hard to tell what constitutes an "iteration" when using the bisection method to approximate a polynomial root. For the purpose here, we'll say one iteration consists of ...

  • evaluating the function at the midpoint of the bracketing interval
  • choosing a smaller bracketing interval
  • identifying the x-value known to be closest to the solution

Thus, the result of the iteration consists of a bracketing interval and the choice of one of the interval's ends as the solution approximation.

__

(a) We observe that the graphs intersect in the interval (-1, 0). For the first iteration, we evaluate f(x)-g(x) at x=-1/2. This tells us the solution is in the interval (-1, -1/2). The x-value closest to the root is x=-1/2.

For the second iteration, we evaluate the function f(x)-g(x) at x=-3/4. This tells us the solution is in the interval (-1, -3/4). The x-value closest to the root is x=-3/4.

For the third iteration, we evaluate the function f(x)-g(x) at x=-7/8. This tells us the solution is in the interval (-7/8, -3/4). The x-value closest to the root is x=-3/4.

__

(b) The graph tells us the solution is approximately 0.7549. Rounded to 2 decimal places, the solution is approximately 0.75.

__

(c) The above solution found after 3 iterations rounded to 2 decimal places is exactly 0.75.

__

See the attached table for function values.

_____

Comment on bisection iteration

Since you cut the interval containing the root in half with each iteration, you gain approximately one decimal place for each 3 iterations. When the function value is very nearly zero at one of the interval endpoints, it can take many more iterations to achieve a better result.

Here, it takes 4 more iterations before an x-value becomes closer to the solution (x≈-97/128). And it takes one more iteration to move the end of the interval away from -3/4. After these 5 more iterations (8 total), the solution is known to lie in the interval (-97/128, -193/256). The corresponding solution approximation is -193/256. It is still only correct to 2 decimal places.

, _ . ’ make 11. Sam is the best running back on his football ' ' a . My fl team Last-year he ran feet during his « ‘ .1. ten games How did he run for ‘ w _ w VJ ~ ; during I " 1 ,500 yards 2, 750 yards 3, 780 ya rods ‘ ' '3 ),403 ya

Answers

To find the answer, all you have to do is convert feet to yards.

1 foot = 0.33333333 or 1/3

0.33333333 (feet) × 4,215 (yards) = 1404.9999

The closest and reasonable answer is 1,403 yards.
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