What is a radioactive idotope?

Answers

Answer 1
Answer: an isotope is when a normal atom has too many neutrons and its weight has been offset.
Answer 2
Answer: natural or artificially created isotope of a chemical element having an unstable nucleus that decays

Related Questions

If 20.0 mL of Ca(OH)2 with an unknown concentration is neutralized by 37.5 mL of 0.124 M HCl, what is the concentration of the Ca(OH)2 solution? Show all of the work needed to solve this problem. Ca(OH)2 + 2 HCl yields 2 H2 O + CaCl2
Write the atomic symbols for isotopes with the following characteristics? 1)an oxygen atom with 10 neutrons 2)a neon atom with twelve neutrons 3)25 electrons and 28 neutrons 4)a mass number of 24 and 13 neutrons 5)a titanium atom with 25 neutrons
An atom has 6 electrons in its valence shell. how many unpaired electrons does it have?
From which of these atoms in the ground state can a valence electron beremoved using the least amount of energy?(1) nitrogen (3) oxygen(2) carbon (4) chlorine
77. A voltaic cell consists of a Zn/Zn2+ half-cell and a Ni/Ni2+ half-cell at 25°C. The initial concentrations of Ni2+ and Zn2+ are 1.50 M and 0.100 M, respectively. a. What is the initial cell potential? b. What is the cell potential when the concentration of Ni2+ has fallen to 0.500 M? c. What are the concentrations of Ni2+ and Zn2+ when the cell potential falls to 0.45 V?

In a chemical equation the arrow (indicating a reaction) points in which direction

Answers

As previously stated, depending on if the reaction is reversible it will point in both left and right directions. If it is irreversible it points to the right.
Depending if the reaction is a reversible or an irreversible one, the direction of the arrow will point in one direction or 2 directions from reactants to products.

1-Propanol is combusted to provide heat. The equation and the enthalpy change for the process are shown below. C₃H₇​OH(l)+4.5O₂​( g)→3CO₂​( g)+4H₂​O(l)ΔH=−2,021 kJ Below is a list of sentences that describe a chemical process. Choose all of the sentences that apply to the above rea Check all that apply. a This process is exothermic. b The enthalpy change for 2C₃H₇​OH(l)+9O₂​( g)→6CO₂​( g)+8H₂​O(l) is 2,021 kJ c The enthalpy change for 2C₃H₇​OH(l)+9O₂​( g)→6CO₂​( g)+8H₂​O(l) is −4,042 kJ d The enthalpy change for 2C₃H₇​OH(l)+9O₂​( g)→6CO₂​( g)+8H₂​O(l) is −2,021 kJ e This chemical process transfers heat from the surroundings to the system. f The enthalpy change for 2C₃H₇​OH(l)+9O₂​( g)→6CO₂​( g)+8H₂​O(l) is 4,042 kJ g This process is endothermic. h This chemical process transfers heat from the system to the surroundings.

Answers

Explanation:

Let's analyze the statements one by one:

a) This process is exothermic.

True. The negative enthalpy change (-2,021 kJ) indicates that heat is released during the reaction, making it exothermic.

b) The enthalpy change for 2C₃H₇OH(l)+9O₂(g)→6CO₂(g)+8H₂O(l) is 2,021 kJ.

False. The balanced chemical equation and enthalpy change given are for the combustion of 1 mole of propanol, not 2 moles.

c) The enthalpy change for 2C₃H₇OH(l)+9O₂(g)→6CO₂(g)+8H₂O(l) is -4,042 kJ.

False. This statement suggests a doubled enthalpy change value in the wrong direction. The correct direction is negative (exothermic), but the magnitude is not doubled.

d) The enthalpy change for 2C₃H₇OH(l)+9O₂(g)→6CO₂(g)+8H₂O(l) is -2,021 kJ.

False. This statement suggests the correct direction but doubles the magnitude. The correct magnitude is -2,021 kJ for 1 mole of propanol.

e) This chemical process transfers heat from the surroundings to the system.

False. The process is exothermic, which means it releases heat from the system to the surroundings.

f) The enthalpy change for 2C₃H₇OH(l)+9O₂(g)→6CO₂(g)+8H₂O(l) is 4,042 kJ.

False. This statement suggests the correct magnitude but in the wrong direction. The correct direction is negative (exothermic).

g) This process is endothermic.

False. The process is exothermic, as indicated by the negative enthalpy change.

h) This chemical process transfers heat from the system to the surroundings.

True. An exothermic process like this releases heat from the system to the surroundings.

So, the correct statements are:

a) This process is exothermic.

e) This chemical process transfers heat from the surroundings to the system.

h) This chemical process transfers heat from the system to the surroundings.

What is released when the chemical bond is broken between the second and third phosphates of an atp?

Answers

The question was "What is realesed when the chemical bond is broken between the second and third phosphates of an atp?" The answer is hydrolysis.

Final answer:

The breaking of the chemical bond between the second and third phosphates of ATP (Adenosine triphosphate) releases significant energy, transforming ATP into adenosine diphosphate (ADP) and an inorganic phosphate group. The energy released powers various biological processes and reactions within cells. This cycle of breaking and reforming ATP, often referred to as hydrolysis, is crucial to cellular function.

Explanation:

Adenosine triphosphate (ATP) is a high-energy molecule that powers cellular processes. When the chemical bond between the second and third (or beta and gamma) phosphates of ATP is broken, it releases significant energy. This reaction, known as hydrolysis, transforms ATP into adenosine diphosphate (ADP) and an inorganic phosphate group (P;), both of which have lower free energy than the reactants. Here is the specific reaction: ATP + H₂O → ADP + P¡ + free energy.

The breaking of phosphates' strong bonds (phosphoanhydride bonds) releases enough energy to power various cellular reactions and processes. These bonds are considered 'high-energy' due to the amount of energy they release upon breaking.

This continuous cycle of ATP breaking down into ADP and phosphate, followed by their recombination, effectively powers the life processes within cells.

Learn more about Hydrolysis here:

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Which of the following Is true about semi-conductors-neither free eletrons nor hoes are considered charge carriers in a semi-conductor
-exposing a crysal of a semiconductor to heat or light starts displacing valence electrons which then move throughout the crystal
-a material is classified as a semiconductor if its resistance to the flow of electric current is too low to permit it to be called a conductor

Answers

The statement that is true about semi conductors is this: A MATERIAL IS CLASSIFIED AS A SEMI CONDUCTOR IF ITS RESISTANCE TO THE FLOW OF ELECTRIC CURRENT IS TOO LOW TO PERMIT IT TO BE CALLED A CONDUCTOR.

Semi conductors refers to those materials that can conductor electricity only under suitable conditions, their resistance to the flow of electricity lies between that of conductors and non conductors. Semi conductors are usually used in some electric circuits because the flow of electricity through them can easily be controlled. Examples of semi conductors are silicon, germanium and selenium.

This is the equation for the combustion of propane.C3H8 + 5O2 → 3CO2 + 4H2O + heat

Which are the reactants and the products in this reaction?

A.
The reactants are C3H8 (propane) and H2O (water). The products are O2 (oxygen) and CO2 (carbon dioxide).

B.
The reactants are C3H8 (propane) and O2 ( oxygen). The products are CO2 (carbon dioxide) and H2O (water).

C.
The reactants are CO2 (carbon dioxide) and H2O (water). The products are C3H8 (propane) and O2 ( oxygen).

D.
The reactants are O2 (oxygen) and CO2 (carbon dioxide). The products are C3H8 (propane) and H2O (water).

Answers

Answer:

B

Explanation:

Reactants are the compounds which reaction produce the products. In general terms this can be expressed symbolically as follows:

reactants -> products

Other phenomena like heat are omitted because are not always present, that is, only compounds are included. Therefore, in this reaction the reactants are C3H8 (propane) and O2 ( oxygen) and the products are CO2 (carbon dioxide) and H2O (water)

Answer:

\huge \boxed{\mathrm{Option \ B}}

\rule[225]{225}{2}

Explanation:

\sf C_3 H_8 +O_2 \Rightarrow CO_2 + H_2 O

Balancing Carbon atoms on the right side,

\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 + H_2 O

Balancing Hydrogen atoms on the right side,

\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 +4 H_2 O

Balancing Oxygen atoms on the left side,

\sf C_3 H_8 +5O_2 \Rightarrow 3CO_2 +4 H_2 O

The reactants are on the left side of the reaction:

\sf \boxed{\sf C_3 H_8 +O_2}  \Rightarrow CO_2 + H_2 O

Propane and oxygen are the reactants.

The products are on the right side of the reaction:

\sf C_3 H_8 +O_2 \Rightarrow \boxed{\sf CO_2 + H_2 O}

Carbon dioxide and water are the products.

\rule[225]{225}{2}

1. In general, the nucleus of a small atom is stable. Therefore, over very short distances, such as those in a small nucleus, a. the strong nuclear force is much greater than the electric force.
b. the electric force is much greater than the strong nuclear force.
c. the strong nuclear force equals the electric force.
d. the strong nuclear force and the electric force are both attractive.
9. Uranium-238 undergoes alpha decay. Therefore, uranium-238 will
a. remain stable.
b. change into a different element altogether.
c. emit neutral particles and no energy.
d. none of the above

Answers

1. Answer;

a. the strong nuclear force is much greater than the electric force.

Explanation;

  • For an atom to be stable it means it has enough amount of binding energy to hold its nucleus together permanently.
  • Therefore, an unstable atom lacks enough amount of binding energy to hold its nucleus permanently and thus undergoes decay to achieve stability. Unstable atoms are therefore referred to being radioactive.
  • Small atoms are stable; this is because they have equal number of protons and neutrons and thus the protons and neutrons fill up energy levels while maximizing the strong force binding the nucleus together.

9. Answer;

b. change into a different element altogether.

Uranium-238 undergoes alpha decay. Therefore, uranium-238 will  change into a different element altogether.

Explanation;

  • Unstable atoms undergo radioactive decay in order to achieve stability of their nucleus.
  • Uranium-238 is an example of such atom, which may undergo decay to achieve stability.
  • Alpha decay is one of the types of decays, others being beta decay and gamma decay. In alpha decay the radioactive isotope undergoes decay such that its mass number is decreased by four and its atomic number is decreased by two.
  • Therefore, Uranium-238 undergoes alpha decay to form a different element whose mass number is 234 and atomic number is 90, known as thorium-234.
1. In general, the nucleus of a small atom is stable. Therefore, over very short distances, such as those in a small nucleus,

a. the strong nuclear force is much greater than the electric force.


9. Uranium-238 undergoes alpha decay. Therefore, uranium-238 will


b. change into a different element altogether.

Hope these answer the questions. Have a nice day.