Current flowing in a circuit depends on two variables identify these variables and their relationship to current

Answers

Answer 1
Answer: as the electrons are pushed more by the battery, they move faster through the circuit
Answer 2
Answer:

Final answer:

The current in a circuit is governed by voltage and resistance, as dictated by Ohm's Law. The voltage-current relationship can be linear in ohmic materials or nonlinear in non-ohmic materials.

Explanation:

The current flowing in a circuit depends primarily on two variables: voltage and resistance. This relationship is defined through Ohm's Law, which states that the current (I) in a circuit is equal to the voltage (V) divided by the resistance (R), or I=V/R.

When the voltage increases while the resistance remains constant, the current will increase. Conversely, when the resistance increases while the voltage remains constant, the current will decrease. Thus, for example, if the resistance doubles, the current is cut in half.

However, it is important to note that not all materials follow this linear relationship. Some materials, known as ohmic materials, follow Ohm's Law, while others, known as non-ohmic materials, exhibit a nonlinear voltage-current relationship.

Learn more about Ohm's Law here:

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Is electronegativity the tendency to attract electrons?

Answers

Answer:

Electronegativity, symbol χ, is a chemical property that describes the tendency of an atom to attract a shared pair of electrons (or electron density) towards itself. An atom's electronegativity is affected by both its atomic number and the distance at which its valence electrons reside from the charged nucleus.

Explanation:

Answer:

Yes

Explanation:

The higher the electronegativity the higher tendency to attract electrons, the lower the electronegativity the higher tendency to give away electrons/lose electrons.

The time required for one-half of the atoms from a sample of a radioactive substance to decay is called its _____.a. half-life
b. beta decay
c. alpha decay
d. isotope number

Answers

The half life, this is how long it takes for half of the atoms to decay

1. Eleanor weights 300 N. She walks up a small hill which is 5 meters high. It takes her 4 seconds. How much work did Eleanor do when she climbed the hill? (3 points)Hint: What is the equation used to calculate work? Does time affect the amount of work completed?

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The equation is Work equals the force times the distance in the direction of the force. This is 300 N * 5 m = 1500 J.

The time does not affect the amount of work.

if eqaul volumes of 0.1 m naoh and 0.1 m hcl arw mixed, the resulting solution will contain a salt and what

Answers

It will contain NaCl.  The acid base reaction will look like this: HCl(aq)+NaOH(aq)⇒H₂O(l)+NaCl(aq)

The reaction occurs due to the fact that HCl (being a strong acid) will dissociate into H⁺ and Cl⁻ while NaOH (being a strong base) will dissociate into OH⁻ and Na⁺.  The H⁺ and OH⁻ will react together to form water and the Na⁺ and Cl⁻ will remain in solution as the salt.  (this is sometimes called a neutralization reaction since the HCl and NaOH neutralize each other.)

I hope this helps. Let me know if anything is unclear.

Which type of concentration is calculated when the grams of solute is divided by the grams of the solution, and the result is multiplied by 1 000 000?(1) molarity (2) parts per million(3) percent by mass (4) percent by volume

Answers

The correct answer is option 2. One way of expressing concentration is by expressing it by parts per million or ppm. It is calculated by dividing the grams of solute and the grams of the solution, and the result is multiplied by 1 000 000. Parts per million is equal to 1 milligram of solute per kilogram of solution. 

The constant-pressure specific heat of air at 25°C is 1.005 kJ/kg °C. Express this value in kJ/kg-K. J/g °C, kcal/kg-°C, and Btu/lbm-°F.

Answers

Answer:

Cp= 1.005 kJ/kg °C =  1.005 kJ/(kg*K) = 1.005 J/g°C = 4.206 J/g°C = 0.776 BTU/lb°F

Explanation:

for the specific heat

1) Cp= 1.005 kJ/kg °C * (1 °C/ 1 K) (temperature differences) = 1.005 kJ/(kg*K)

2) Cp= 1.005 kJ/kg °C * (1000 J/ kJ)* (1 kg/1000 gr) = 1.005 J/g°C

3) Cp= 1.005 kJ/kg °C * (4.186 kcal/kJ) = 4.206 J/g°C

4) Cp= 1.005 kJ/kg °C * (1 BTU/1.055 kJ)* (0.4535 kg/lb)*(1.8°C/°F)= 0.776 BTU/lb°F