Which of these factors are experienced by a space shuttle in orbit? Check all that apply. A. gravity
B. air resistance
C. friction
D. inertia
E. centripetal force

Answers

Answer 1

Answer:

Answer:

Gravity, inertia, centripetal force

Explanation:

Gravity: A space shuttle in orbit experiences gravity not just from the planet it is orbiting but from other celestial bodies too

Air resistance: There is no atmosphere in space so the shuttle experiences no air resistance

Friction: There is no atmosphere or surface that it is moving on so the shuttle experiences no friction

Inertia: Any body that is moving or stationary experiences inertia, the resistance to change in velocity whether it is moving or stationary

Centripetal force: The shuttle is in orbit, what keeps it in orbit is the centripetal force towards the center of the body it is orbiting

Answer 2

Answer: A. gravity (of any planet/star/celestial body around )

D. Inertia

E. Centripetal force

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When 70.4 g of benzamide (C,H,NO) are dissolved in 850. g of a certain mystery liquid X, the freezing point of the solution is 2.7 C lower than the freezing point of pure X. On the other hand, when 70.4 g of ammonium chloride (NH CI) are dissolved in the same mass of X, the freezing point of the solution is 9.9 °C lower than the freezing point of pure X. Calculate the van't Hoff factor for ammonium chloride in X. Be sure your answer has a unit symbol, if necessary, and round your answer to 2 significant digits.

Answers

Answer:

1.60 is the van't Hoff factor for ammonium chloride in X.

Explanation:

$\Delta T_f=iK_f* m$

$Delta T_f=K_f* \frac{\text{Mass of solute}}{\text{Molar mass of solute}* \text{Mass of solvent in Kg}}$ ...(1)

where,

$\Delta T_f$ =Elevation in boiling point =

i = van't Hoff factor

$K_f$ = Freezing point constant

m = molality

1) When 70.4 g of benzamide are dissolved in 850. g of a certain mystery liquid X.

Mass of benzamide = 70.4 g

Molar mass of benzamide = 121 g/mol

i = 1 (organic molecule)

Mass of liquid X = 850 g = 0.850 kg

$K_f$ = Freezing point constant of liquid X= ?

$\Delta T_f=2.7^oC$

Putting all value in a (1):

$2.7^oC=K_f* (70.4 g)/(121 g/mol* 0.850 kg)$

$K_f=3.944 ^oC kg/mol$

2) When 70.4 g of ammonium chloride are dissolved in 850. g of a certain mystery liquid X.

Mass of ammonium chloride= 70.4 g

Molar mass of ammonium chloride = 53.5 g/mol

i = ? (ionic molecule)

Mass of liquid X = 850 g = 0.850 kg

$K_f=3.944 ^oC kg/mol$

$\Delta T_f=9.9^oC$

Putting all value in a (1):

$9.9^oC=i* 3.944^oC kg/mol* (70.4 g)/(53.5 g/mol* 0.850 kg)$

i = 1.6011 ≈ 1.60

1.60 is the van't Hoff factor for ammonium chloride in X.

Final answer:

The van't Hoff factor, which measures ionization, for ammonium chloride in the mysterious liquid X can be calculated to be approximately 1.01. This is calculated by first determining the cryoscopic constant from the observed depression of the freezing point by benzamide (which does not ionize), and then utilizing this value to calculate the theoretical freezing point depression for ammonium chloride (pretending it does not ionize either). Since the observed depression was 9.9℃ and the calculated was 9.8℃, the van't Hoff factor is their quotient, or approximately 1.01.

Explanation:

To solve this problem, we need to understand that the van't Hoff factor (i) is a measure of the extent of ionization in solution. It can be calculated using the formula i = ΔTf observed / ΔTf calculated, where ΔTf observed is the observed freezing point depression and ΔTf calculated is the theoretical freezing point depression if no ionization occurs.

First, we calculate the theoretical freezing point depression for ammonium chloride. We know that this is given by the benzamide that reduces the freezing point of the same amount of liquid X by 2.7℃. Therefore we assume the van't Hoff factor of benzamide is 1 (since it does not ionize) and we get the cryoscopic constant (Kf) of X from ΔTf = Kf * m * i. Substituting into the formula and rearranging gives Kf = ΔTf / (m * i) = 2.7 ℃/(70.4 g/850 g) = 2.7 ℃/0.082824 = 32.6 ℃ kg/mol.

We then use this Kf to calculate the ΔTf calculated for ammonium chloride: ΔTf calculated = Kf * m * i (where we again assume i=1) = 32.6 ℃ kg/mol * (70.4 g/850 g) = 9.8 ℃. Finally we can calculate the van't Hoff factor for ammonium chloride using the original formula: i = ΔTf observed / ΔTf calculated = 9.9 ℃ / 9.8 ℃ = 1.01.

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The combustion of 1 mole of CO according to the reaction CO(g) + ½O2(g) → CO2(g) + 67.6 kcal gives off how much heat?-67.6 kcal
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Answers

Combustion usually occurs when a hydrocarbon reacts with oxygen to produce carbon dioxide and water. Combustion reactions are almost always exothermic CO(g) + ½O2(g) → CO2(g) + 67.6 kcal
base from the reaction, the stoichiometric ratio is 1 mole CO produce 67.6 kcal so the anwer is - 67.6 kcal because is it exothermic

I got 67.6 kcal not -67.6

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Answers

Answer:

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Explanation:

NOT MY WORK! HOPE THIS HELP!

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Answers

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Answers

Answer:

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Stained glass can be useful for _____________________a. transmitting light and displaying colorful images.
b. churches to draw in new patrons who want to view its beauty from inside.
c. reflecting and absorbing light, as well as displaying colorful images.
d. creating mirrored images of light and colors on the surrounding walls of a religious structure.

Answers

Stained glass can be useful for churches to draw in new patrons who want to view its beauty from inside.

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Stained glass is defined as a glass material which is made colored by means of adding metallic salts during the manufacturing process which imparts color to the glass.

These are used in many decorative purposes like decorating windows . The colors are imparted to the glass by mixing metal oxides into the colorless glass in its melted state.Sometimes fusion of a colored glass with a plain glass to make a stained glass is also used.

Stained glass is also prepared by glass paint where in streaks are introduced in glass by means of light firing in a furnace or a kiln.Silver stain is a range of compounds where in silver compound are mixed with binding substances and then applied to surface of glass,which are then fired in a furnace or in a kiln.

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