Which equation represents the total ionic equation for the reaction of HNO3 and NaOH?

Answers

Answer 1

Answer: Answer: H⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + OH⁻(aq) —> NO₃⁻(aq) + Na⁺(aq) + H2O(l)

Explanation:

1) The first step is understand the nature of the reactants and the kind of reaction that they carry on:

HNO₃ is an acid (nitric acid) and NaOH is a base (sodium hydroxide).

So, this is an acid base reaction, which is a double replacement reaction, whose result is a salt and water.

2) It is also helpful writing the molecular equation. And you should include the phases. This is:

HNO₃(aq) + NaOH(aq) --> NaNO₃(aq) + H₂O(l)

3) Next, you should separate each ionic compound into its ions. This is:

HNO₃(aq) = H⁻(aq) + NO₃⁺(aq), and

NaOH = Na⁺(aq) + OH⁻(aq)

4) Write the reactant side in the form of ions:

H⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + OH⁻(aq) →

5) write the product side: H+ + OH- form water and the other two ions,.althoug form the sal, if are soluble remain as ions in the solution.

NO₃⁻(aq) + Na⁺(aq) + H2O(l)

6) Write both sides:

H⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + OH⁻(aq) —> NO₃⁻(aq) + Na⁺(aq) + H2O(l)

And this last one is the total ionic equation.

Answer 2

Answer:

Answer: The net ionic equation is written below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of nitric acid and sodium hydroxide is given as:

$HNO_3(aq.)+NaOH(aq.)\rightarrow NaNO_3(aq.)+H_2O(l)$

Ionic form of the above equation follows:

$H^+(aq.)+NO_3^-(aq.)+Na^+(aq.)+OH^-(aq.)\rightarrow Na^+(aq.)+NO_3^-(aq.)+H_2O(l)$

As, sodium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$H^+(aq.)+OH^-(aq.)\rightarrow H_2O(l)$

Hence, the net ionic equation is written above.

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Answers

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Answer:

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Bromine, a liquid at room temperature has a boiling point of 58 degrees celsius and a melting point at -7.2 degree celsius bromine can be classified as a

Answers

Hello!

Bromine can be classified as a pure substance.

Why?

Bromine is an element with atomic number 35 on group 17 of the Periodic Table. That's the first sign that shows us that it is a pure substance.

But the fact that it has a clear and defined boiling and melting point is a sign that we are in the presence of a pure substance. Pure substances are characterized by defined boiling and melting points.

Mixtures usually have a range of temperatures in which they melt and boil.

Have a nice day!

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