CHEMISTRY HIGH SCHOOL

The functional group in an alcohol is the _____ group.

Answers

Answer 1

Answer:

Answer is: hydroxyl group (-OH).

A functional group is a group of atoms that determines many of the properties of an organic molecule.

Functional group for alcohol is hydroxyl group or hydroxy group (-OH).

In organic chemistry, alcohol and carboxylic acids contain hydroxy groups.

The atoms of functional groups are linked to each other and to the rest of the molecule with covalent bonds.

Answer 2

Answer: The functional group in Alcohol is the Hydroxyl group.

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Determine the mass of 5.20 moles of C6H12 (gram-formula mass = 84.2 grams/mole).
Carvone is a substance that occurs in two forms having different arrangements of the atoms but the same molecular formula (c10h14o) and mass. one type of carvone gives caraway seeds their characteristic smell, and the other type is responsible for the smell of spearmint oil. calculate the mass percent of each element in carvone.

An igneous rock originally has 3 grams of uranium 238 in it. When dated the rock only contains 1.8 grams. What are the parent and daughter concentrations (in percentages) and what is its age?

Answers

Answer :

The parent and daughter concentrations (in percentages) is, 60 % and 40 % respectively.

The age of rock is $3.32* 10^9\text{ years}$

Explanation :

First we have to calculate the parent and daughter concentrations (in percentages).

$\text{Parent concentrations}=(1.8g)/(3g)* 100=60\%$

and,

$\text{Daughter concentrations}=((3-1.8)g)/(3g)* 100=40\%$

As we know that, the half-life of uranium-238 = $4.5* 10^9$ years

Now we have to calculate the rate constant, we use the formula :

$k=(0.693)/(t_(1/2))$

$k=\frac{0.693}{4.5* 10^9\text{ years}}$

$k=1.54* 10^(-10)\text{ years}^(-1)$

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

$t=(2.303)/(k)\log(a)/(a-x)$

where,

k = rate constant = $1.54* 10^(-10)\text{ years}^(-1)$

t = time passed by the sample = ?

a = initial amount of the reactant = 3 g

a - x = amount left after decay process = 1.8 g

Now put all the given values in above equation, we get

$t=(2.303)/(1.54* 10^(-10))\log(3)/(1.8)$

$t=3.32* 10^9\text{ years}$

Therefore, the age of rock is $3.32* 10^9\text{ years}$

Consider the following for the reaction at 300 K:3 ClO– (aq)  ClO3– (aq) + 2 Cl– (aq)ExperimentInitial [ClO–] (M)Initial Rate of Formation of ClO3– (aq)(M/min)10.4521.048 × 10–420.9034.183 × 10–4(7) (4 pts) What is the order of the reaction with respect to ClO– (aq)?A) 0B) 1C) 2(8) (4 pts) For experiment #2, what is the initial rate of consumption of ClO–

Answers

Answer:

Second order

Δ[ClO⁻]/Δt = - 4.183 x 10⁻⁴ M/min

Explanation:

Given the data:

Experiment # [ClO–] (M) Initial Rate of Formation of ClO3– (M/min)

1 10.452 1.048 x 10⁻⁴

2 20.903 4.183 x 10⁻⁴

we need to determine the order of the reaction with respect to ClO⁻.

We know the rate law for this reaction will have the form:

Rate = k [ClO⁻]^n

where n is the order of the reaction. Thus, what we need to do is to study the dependence of the initial rate on n for the experiment.

If the reaction were zeroth order the rate would not change, so we can eliminate n= 0

If the reaction were first order, doubling the concentration of [ClO–] , as it was done exactly in experiment # 2, the initial rate should have doubled, which is not the case.

If the reaction were second order n: 2, doubling the concentration of [ClO–] , should quadruple the initial rate of formation of ClO3–, which is what it is observed experimentally. Therefore the reaction is second order respect to ClO–.

The initial rate of consumption of ClO⁻ is the same as the rate of formation of ClO₃⁻ since:

Δ = - Δ[ClO⁻]/Δt = + Δ[ClO₃⁻]/Δt = + 1/2 [Cl⁻] /Δt

where t is the time.

from the coefficients of the balanced chemical equation.

- Δ[ClO⁻]/Δt = + Δ[ClO₃⁻]/Δt = + 1/2 [Cl⁻ ] = rate

Δ[ClO⁻]/Δt = - 4.183 x 10⁻⁴ M/min

I will give u brainliest if u get it right. I want someone smart.

Answers

Answer:

A just A

Explanation:

Answer:

so is c they have the same mass.

Which is the correct name for the comound N2O3

Answers

Dinitrogen trioxide is the compound N2O3. :)

Answer:

dinitrogen trioxide

Explanation:

It's a covalent compound. Using the naming convention of the IUPAC and prefixes.

A lahar is a type of mudflow that occurs?A. after a volcanic eruption
B. before a hurricane make landfall.
C. after a severe thunderstorm
D. during a tornado

Answers

A lahar is a type of mudflow that occurs after a volcanic eruption. It is a sort of mudflow or trash stream made out of a slurry of pyroclastic material, rough flotsam and jetsam, and water. The material streams down from a fountain of liquid magma, normally along a waterway valley. Lahar is the most deadly by-products of the eruption because of the speed they can travel.

A lahar is a type of mud flow that occurs? The answer is, A. after a volcanic eruption.

The chemical formula below shows how salt is produced.HCl + NaOH -----> NaCl + H2O

Which substances are the reactants?

Answers

Answer:

reactants: HCl and NaOH

Explanation:

A chemical reaction or equation can be explained with reference of two components: the reactants and products

Reactants are atoms, molecules or ions that are present of the left side of the equation. These could either be a single entity which can break or decompose under a given conditions or they could combine with other entities appropriately to form new molecules, atoms, ions etc. These new molecules occupy the right side of the reaction and are termed as Products.

The given reaction is and acid-base neutralization reaction

HCl + NaOH -----> NaCl + H2O

Reactants:

HCl, hydrochloric acid

NaOH, sodium hydroxide

Products:

NaCl, sodium chloride

H2O, water

hydrochloric acis and sodium hydroxide

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