If energy can neither be created nor destroyed in a chemical reaction, what can happen to the energy

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Answer 1
Answer: while energy cannot be destroyed or created, it can however be transformed into other forms of energy.

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77. A voltaic cell consists of a Zn/Zn2+ half-cell and a Ni/Ni2+ half-cell at 25°C. The initial concentrations of Ni2+ and Zn2+ are 1.50 M and 0.100 M, respectively. a. What is the initial cell potential? b. What is the cell potential when the concentration of Ni2+ has fallen to 0.500 M? c. What are the concentrations of Ni2+ and Zn2+ when the cell potential falls to 0.45 V?

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Answer :

(a) The initial cell potential is, 0.53 V

(b) The cell potential when the concentration of Ni^(2+) has fallen to 0.500 M is, 0.52 V

(c) The concentrations of Ni^(2+) and Zn^(2+) when the cell potential falls to 0.45 V are, 0.01 M and 1.59 M

Explanation :

The values of standard reduction electrode potential of the cell are:

E^0_([Ni^(2+)/Ni])=-0.23V

E^0_([Zn^(2+)/Zn])=-0.76V

From this we conclude that, the zinc (Zn) undergoes oxidation by loss of electrons and thus act as anode. Nickel (Ni) undergoes reduction by gain of electrons and thus act as cathode.

The half reaction will be:

Reaction at anode (oxidation) :Zn\rightarrow Zn^(2+)+2e^-     E^0_([Zn^(2+)/Zn])=-0.76V

Reaction at cathode (reduction) :Ni^(2+)+2e^-\rightarrow Ni     E^0_([Ni^(2+)/Ni])=-0.23V

The balanced cell reaction will be,  

Zn(s)+Ni^(2+)(aq)\rightarrow Zn^(2+)(aq)+Ni(s)

First we have to calculate the standard electrode potential of the cell.

E^o=E^o_(cathode)-E^o_(anode)

E^o=E^o_([Ni^(2+)/Ni])-E^o_([Zn^(2+)/Zn])

E^o=(-0.23V)-(-0.76V)=0.53V

(a) Now we have to calculate the cell potential.

Using Nernest equation :

E_(cell)=E^o_(cell)-(0.0592)/(n)\log ([Zn^(2+)])/([Ni^(2+)])

where,

n = number of electrons in oxidation-reduction reaction = 2

E_(cell) = emf of the cell = ?

Now put all the given values in the above equation, we get:

E_(cell)=0.53-(0.0592)/(2)\log ((0.100))/((1.50))

E_(cell)=0.49V

(b) Now we have to calculate the cell potential when the concentration of Ni^(2+) has fallen to 0.500 M.

New concentration of Ni^(2+) = 1.50 - x = 0.500

x = 1 M

New concentration of Zn^(2+) = 0.100 + x = 0.100 + 1 = 1.1 M

Using Nernest equation :

E_(cell)=E^o_(cell)-(0.0592)/(n)\log ([Zn^(2+)])/([Ni^(2+)])

Now put all the given values in the above equation, we get:

E_(cell)=0.53-(0.0592)/(2)\log ((1.1))/((0.500))

E_(cell)=0.52V

(c) Now we have to calculate the concentrations of Ni^(2+) and Zn^(2+) when the cell potential falls to 0.45 V.

Using Nernest equation :

E_(cell)=E^o_(cell)-(0.0592)/(n)\log ([Zn^(2+)+x])/([Ni^(2+)-x])

Now put all the given values in the above equation, we get:

0.45=0.53-(0.0592)/(2)\log ((0.100+x))/((1.50-x))

x=1.49M

The concentration of Ni^(2+) = 1.50 - x = 1.50 - 1.49 = 0.01 M

The concentration of Zn^(2+) = 0.100 + x = 0.100 + 1.49 = 1.59 M

What is the study of the spectra produced from the emission and absorption of electromagnetic radiation? study of absorption spectrums study of emission spectrum nanotechnology spectroscopy

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Answer the correct answer out of the four is option c spectroscopy

Explanation- The interaction between electromagnetic radiation and matter studied. This study is commonly known as spectroscopy. It can also be named as study of absorption spectra or emission spectra.

The former spectrum is formed when energy is absorbed from Photons or light energy by electrons while the latter spectrum is formed due to a wavelength of light that is released when electrons jump from higher to lower level.  

Answer:

D spectroscopy

Explanation:

_____ magma is a mix between basaltic and rhyolitic magma. The eruption that would most likely result from this magma is a _____ eruption.

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Answer:

Explanation:

_Andesitic__ magma is a mix between basaltic and rhyolitic magma. The eruption that would most likely result from this magma is a _strombolian____ eruption.

Andesitic magma straddles between basaltic and rhyolitic magma. They produce rocks that shows both basaltic and rhyolitic affinity. Examples of rocks that results from this type of magma is andesite.

Strombolian eruptions results from this type of magma. They are charactised by moderate to low bursts of magma. Their explosivity is between 2 and 3.

Absolute proof about the origin of a crater on the moon or the "star of Bethlehem" cannot be determinedusing the scientific method.
True
False

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Correct Answer: TRUE

The other answer is incorrect, I just did the assignment and got it right.

your answer is False love!

Which of the following choices represents a balanced chemical equation? Ca3(PO4)2 + 6SiO2 → P4O10 + 3CaSiO3 2Ca3(PO4)2 + 6SiO2 → P4O10 + 6CaSiO3 2Ca3(PO4)2 + 3SiO2 → 2P4O10 + 2CaSiO3 3Ca3(PO4)2 + 2SiO2 → P4O10 + 4CaSiO3

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2Ca_3(PO_4)_2 + 6SiO_2 -> P_4O_(10) + 6CaSiO_3 Hence, option B is correct.

What is a balanced equation?

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total oxidation numbers is the same for both the reactants and the products.

2Ca_3(PO_4)_2 + 6SiO_2 -> P_4O_(10) + 6CaSiO_3 represents a balanced chemical equation.

Learn more about the balanced equation here:

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Here is the correct answer: 2Ca3(PO4)2 + 6SiO2 -> P4O10 + 6CaSiO3

The adrenal glands respond to______

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The adrenal gland respond to stress that is experienced in your body.  These are produced within the medulla. The cortisol helps regulate your metabolism, sugar levels and blood pressure. The adrenal glands are controlled by the pituitary gland.

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