Compared to the atoms of nonmetals in period 3, the atoms of metals in period 3 have1. fewer valence electrons
2. more valence electrons
3. fewer electron shells
4. more electron shells

Answers

Answer 1
Answer:

Compared to the atoms of nonmetals in period 3, the atoms of metals in period 3 have fewer valence electrons.

Option 1 is correct.

In the periodic table, the period runs from left to right on the table while the group runs from top to bottom on the table.

In period 3, the period starts with Sodium Na(alkali metal), Magnesium Mg(alkaline earth metals), Aluminium Al(other non metals), Silicon Si (non metals), Phosphorus (non-metals), Sulfur (non-metals). etc.

From left to right across period 3, the valence electrons in the outermost increase.

Hence, the metals will have fewer valence electrons since the metals start period 3.

Therefore, we can conclude that compared to the atoms of nonmetals in period 3, the atoms of metals in period 3 have fewer valence electrons.

Learn more about the periodic table here:

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Answer 2
Answer:

Answer : Option A) Fewer valence electrons

Explanation : Compared to the atoms of non metals in period 3, atoms of metals in period 3 have fewer valence electrons.

There are 8 elemental members in third period which are eight: sodium, magnesium, aluminium, silicon, phosphorus, sulfur, chlorine, and argon.

The first 2 elements belong to s-block whereas the other elements belong to p-block. The atomic radius is found to decrease across the period.

The electrons in the valence shell increases as we go from left to right in the period, which means when we move from metal to non-metal side the number of valence electrons also increases. This clearly shows that metals have fewer valence electrons as compared to the non-metals.


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952 grams of ammonium carbonate are dissolved to make 1750 mL of solution

Answers

(%m/v) =mass of solute (in g) / volume of solution (in mL) x 100
       
            = 952 g (NH4)2CO3 / 1750 mL x 100
    
            = 0.544 x 100
       
(%m/v) = 54.4 g /mL or 54.4% concentration of ammonium carbonate 
                                                solution



What is the ph of a solution with [H+]=3.3x10

Answers

pH=-log[H⁺]

That means that the pH=-log(3.3×10)=-1.52

I hope this helps.  Let me know if anything is unclear.

OSHA standards appear in the ___________ and are then broken down into ____________.

Answers

OSHA standards appear in the Code of Federal Regulations (CFR) and was then broken down into two parts. It contains standards to ensure a comfortable and high quality research tools like the databases. These standards are to be strictly monitored to ensure  the safety of workers. 

The answer is

OSHA standards appear in the Code of Federal Regulations (CFR) and was then broken down into two parts.

The explanation:

OSHA standards are rules that describe the methods that employers must use to protect their employees from hazards. There are OSHA standards for Construction work, Maritime operations, and General Industry, which is the set that applies to most worksites. These standards limit the amount of hazardous chemicals workers can be exposed to, require the use of certain safe practices and equipment, and require employers to monitor hazards and keep records of workplace injuries and illnesses

It contains standards to ensure a comfortable and high quality research tools like the databases. These standards are to be strictly monitored to ensure  the safety of workers.

The gray balls represent _____ and have a neutral charge. protons neutrons electrons

Answers

Protons have a positive charge.Electrons have a negative charge.Neutrons have no (neutral) charge.

Answer: The correct answer is neutrons.

Explanation:

There are 3 subatomic particles that are present in an atom. They are: protons, electrons and neutrons.

Protons carry positive charge and are found inside the nucleus of an atom.

Electrons carry negative charge and are found around the nucleus in the orbits.

Neutrons does not carry any charge and are found inside the nucleus of an atom.

Hence, the correct answer is neutrons.

How many grams of calcium bromide are in 50.0 mL of a 0.25 M calcium bromide solution?

Answers

The mass of the compound can be calculated by the molarity. The mass of the calcium bromide in the given solution is 2.5 g.

The mass of the given compound can be calculated by the molarity formula,

\bold {M = \frac {w}{m* v} * 1000}\n\n\bold {w = \frac {M* m* v}{ 1000}}

Where,

M- molarity of the solution =  0.25 M

w - given mass =?

m -molar mass of Calcium bromide =  200 g/mol

v-volume in mL= 50 mL

Put the values in the formula,

\bold {w = \frac {0.25* 200* 50}{ 1000}}\n\n\bold {w = 2.5\ g}

Therefore, the mass of the calcium bromide in the given solution is 2.5 g.

To know more about Molarity,

brainly.com/question/12127540

C_(m)=(n)/(V_(r))\n\nm=(m)/(M)\n\nC_(m)=(m)/(MV_(r)) \ \ \ \ \Rightarrow \ \ \ \ m=C_(m)MV_(r)}\n\nC_(m)=0.25(mol)/(L)\nM_{CaBr_(2)}=200(g)/(mol)\nV_(r)=50mL=0.05L\n\nm=0.25(mol)/(L)*200(g)/(mol)*0.05L= \emph{\textbf{2.5g}}

The Haber process can be used to produce ammonia (NH3) from hydrogen gas (H2) and nitrogen gas (N2). The balanced equation for this process is shown below.3H2 + N2 mc025-1.jpg 2NH3

The molar mass of NH3 is 17.03 g/mol. The molar mass of H2 is 2.0158 g/mol. In a particular reaction, 0.575 g of NH3 forms. What is the mass, in grams, of H2 that must have reacted, to the correct number of significant figures?
0.1
0.102
0.10209
0.1021

Answers

Answer : The mass of H_2 in grams is 0.102g.

Solution : Given,

Molar mass of NH_3 = 17.03 g/mole

Molar mass of H_2 = 2.0158 g/mole

Given Mass of NH_3 = 0.575 g

First we have to calculate the moles of NH_3.

\text{ Moles of }NH_3=\frac{\text{ Given mass of }NH_3}{\text{ Molar mass of }NH_3} = (0.575g)/(17.03g/mole) = 0.0337 moles

The given balanced equation is,

3H_2(g)+N_2(g)\rightarrow 2NH_3(g)

From the above reaction, we conclude that

2 moles of NH_3 produced from 3 moles of H_2

then the 0.0337 moles of NH_3 produces to give (3moles* 0.0337moles)/(2moles) moles of H_2

The moles of H_2 = 0.0505 moles

The mass of H_2 = Moles of H_2 × Molar mass of H_2 = 0.0505 moles × 2.0158 g/mole = 0.10179 g

The mass of H_2 in the correct number of significant figures is 0.102 g.