CHEMISTRY HIGH SCHOOL

A solution of h2so4(aq) with a molal concentration of 6.80 has a density of 1.318 g/ml. what is the molar concentration of this solution?

Answers

Answer 1

Answer:

The molalconcentration of the solution is 5.38 M.

The molal concentration of sulphuric acid = 6.80 m

The density of the solution = 1.318 g/ml

Mass of the sulphuric acid in the solution is,

$= 6.80 * 9.80$

$=666.4 \: g$

The mass of sulphuric acid present in the solution is 666.4 g.

Let the mass of the solvent in which sulphuric acid is dissolved be 1000 grams.

So the total mass of the solution is,

= Mass of solvent + Mass of sulphuric acid

$= 666.4 \: + \: 1000$

$= 1666.4 \: g$

The total volume of the solution is,

$= (1666.4 * 1)/(1.318 * 1000)$

$= 1.264 \: L$

The volume of the solution is 1.264 liters.

The molal concentration of this solution is,

$= (6.80)/(1.264)$

$= 5.38 \: M$

Therefore, the molal concentration of the solution is 5.38 M.

To know more about molarity, refer to the below link:

brainly.com/question/16587536

#SPJ4

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In what way would readings from a digital thermometer be preferable to those from a liquid-based thermometer?

Answers

A digital thermometer is more preferable than a liquid-based thermometer because it gives accurate data than the liquid thermometer. Liquid thermometer is affected by the temperature, and when it does, the liquid expands and so des the material covering the thermometer. For the digital thermometer, it has less error because it already has a sensor inside it that determines the temperature of the substance.

Observe the nature changing around your home. You can observe plants, animals, and parts of your actual home as you begin to notice changes in matter. Collect data for two examples of changes in matter. Use the Changes in Matter observation questions to determine if your examples are physical or chemical changes.Your answer should include two examples, the types of changes observed, and evidence of how the examples were formed. You can use this format:

Example 1:

Type of Change:

Evidence:

Answers

Answer:

Example 1. One change I observed was when cooking, I needed to boil water. The water was later evaporated due to the increase of heat from the stove below the pot. Heat traveled and transferred from the stove to the pot then the water. This change is from liquid to gas.

Example 2. I was mixing sugar into my tea, the sugar dissolved into the tea. This is an example of dissolving a solid into a liquid. The tea took the properties of the sugar and turned the drink sweet.

Extra, taking a hot shower and steam leaves the shower. This change is of evaporation.

Explanation:

Hope this helps, even though it was late! <3 :)

Where are people exposed to chemicals?O A. Mostly in public buildings
O B. Only in the home
C. Mostly outside
O D. Everywhere

Answers

Answer:

I believe the correct answer is D.

Explanation:

You are breathing in dinitrogen and dioxygen. You exhale dinitrogen and carbon dioxide. And the atmosphere contains traces of other gases. You drink water. You have a wash with water, and soap. You eat carbohydrates and proteins. You ride to work on a vehicle powered by hydrocarbons, which spits out carbon dioxide exhaust fumes, and also some nitrogen oxides. And so your exposure to chemicals is pervasive, and unavoidable.

Answer:

Explanation:

Given 16.2 grams of substance Y, if the substance absorbs 2722 joules of energy and the specific heat of the substance is 9.22 J/g·°C, what is the final temperature of the substance if the initial was 26 degrees Celsius?

Answers

Since the substance absorbs heat, it is expected that the temperature will rise. The formula for the internal energy of a substance is given by the equation:

ΔU = mCpΔT

where:

ΔU = internal energy
m = mass of substance
Cp = specific heat capacity of substance
ΔT = change in temperature

ΔU = 2722 Joules = 16.2 grams (9.22 J/g-°C) (Tf - 26°C)

This gives a final temperature of Tf = 44.22 °C

a gas has a volume of 590 mL at a temperature of 590 mL at a temperature of -55.0 degrees Celsius. What volume will the gas occupy at 30.0 degrees Celsius?

Answers

Answer: The volume that gas occupy will be 820.04mL.

Explanation:

To calculate the volume of the gas at different temperature, we will use the equation given by Charles' Law.

This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

$V\propto T$

or,

$(V_1)/(T_1)=(V_2)/(T_2)$

where,

$V_1\text{ and }T_1$ are the initial volume and initial temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and final temperature of the gas.

We are given:

$T(K)=273+T(^oC)$

$V_1=590mL\nT_1=-55^oC=218K\nV_2=?mL\nT_2=30^oC=303K$

Putting values in above equation:

$(590)/(218)=(V_2)/(303)\n\nV_2=820.04mL$

Hence, the volume that gas occupy will be 820.04mL.

describe how the current modern atomic theory and model differs from the model jj Thompson proposed ?

Answers

J.J Thompson’s model shows a sphere with electrons that are moving around freely. However, Thompson’s model does not show protons or neutrons. The model that we have today gives a clearer structure showing protons, neutrons, and electrons inside an atom.

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