Answers
Given data:
Density of iron (Fe) = 7.9 g/cm3
Length of one side of the iron cube = 1.64 * 10^2 cm
Now, the volume (V) of a cube in which the length of the side is 'a' cm is given as:
V = a^3
Volume of iron cube = (1.64 *10^2 cm)^3 = 4.41 * 10^6 cm3
The density (D) of an object of mass (m) and volume (V) is given as:
D = m/V
or, m = D*V
Therefore, mass of iron cube = 7.9 g/cm3 * 4.41 * 10^6 cm3
= 34.84 *10^6 g
Related Questions
Consider the neutralization reaction 2HNO3(aq) + Ba(OH)2 ( aq ) ⟶ 2H2O ( l ) + Ba ( NO3)2 ( aq ). A 0.125 L sample of an unknown HNO 3 solution required 32.3 mL of 0.200 M Ba ( OH ) 2 for complete neutralization. What is the concentration of the HNO 3 solution?
A solid that forms from a solution during a chemical reaction is called a(an)
A pharmacist wishes to strengthen a mixture from 10%alcohol to 30% alcohol. How much pure alcohol should be added to 7 liters of the 10% mixture?
Which of the two aqueous solutions will be a better conductor of electricity in the following examples? Explain why in each case.a)1.0M NaCl vs. 0.010 M Naclb)0.10 M NaCl vs. 0.10 M Al2(SO4)3 (assume complete dissociation of both salts).c) 1.0 mole of NaCl added to water vs. 1.0 mole of pbCl2 added to water (hint: remember the solubility rules).
(b)SO3 + H2O? (Assume an excess of water and that the product dissolves)
(c) SrO + H2SO4?
Answers
Explanation:
A balanced equation is defined as the one that has equal number of atoms of all the elements present on both reactant and product side.
(a)
Number of atoms on reactant side are as follows.
Mg = 1
O = 6
H = 3
Cl = 1
Number of atoms on product side are as follows.
Mg = 1
O = 9
H = 2
Cl = 2
So, to balance this equation we multiply by 2 on reactant side and multiply
by 2 on product side.
Therefore, the balanced reaction equation is as follows.
(b)
Number of atoms on reactant side are as follows.
S = 1
O = 4
H = 2
Number of atoms on product side are as follows.
S = 1
O = 4
H = 2
Therefore, this equation is balanced as it has same number of atoms on both reactant and product side.
(c)
Number of atoms on reactant side are as follows.
Sr = 1
O = 1
H = 2
S = 1
O = 4
Number of atoms on product side are as follows.
Sr = 1
O = 1
H = 2
S = 1
O = 4
Therefore, this equation is balanced.
Answers
Answer:
hydrogen have electronic configuration of 1s¹ to acquire a stable state it can either lose electron and form H+cation or gain an electron( to compete its 1s subshell ) to form H- anion. As it has ±1 valency it is placed neither in group 1(alkaline metals ) nor in group 17 (halogens) .
Answers
Explanation:
Ionic equation
NaCl(aq) --> Na+(aq) + Cl-(aq)
Na2SO4(aq) --> 2Na+(aq) + SO4^2-(aq)
In NaCl solution, 1 mole of Na+ is dissociated in 1 liter of solution while in Na2SO4, 2 moles of Na+ is dissociated in 1 liter of solution.
Molecular weight of NA2SO4 = (23*2) + 32 + (16*4)
= 142 g/mol
Molecular weight of NaCl = 23 + 35.5
= 58.5 g/mol
Masses
% Mass of NA+ in Na2SO4 = mass of Na+/total mass of Na2SO4 * 100
= 46/142 * 100
= 32.4%
% Mass of NA+ in NaCl = mass of Na+/total mass of NaCl * 100
= 23/58.5 * 100
= 39.3%
Therefore, the % mass of Na+ in NaCl and Na2SO4 are different so it cannot be used.
Final answer:
You cannot substitute Na2SO4 directly for NaCl based on mass since they have different molar masses. The same mass of Na2SO4 will provide more Na+ ions than NaCl, leading to a change in the Na+ ion concentration.
Explanation:
No, you cannot substitute the same number of grams of Na2SO4 for the NaCl in a solution. This is because NaCl and Na2SO4 have different molar masses and therefore different numbers of moles per gram. The concentration of a solution is determined by the number of moles of solute per unit volume of solvent, not the mass. Hence, using the same mass of a different compound would alter the concentration of Na+ ions in the solution.
For instance, if one mole of NaCl gives us one mole of Na+, one mole of Na2SO4 will provide two moles of Na+. In other words, the same mass of Na2SO4 contains more Na+ ions than the same mass of NaCl. So using the same mass of Na2SO4 in place of NaCl will result in a solution with a higher Na+ ion concentration.
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Answers
Speed of the car =
Given time = 37.0 s
Converting time from seconds to hours:
1 hr= 60 min; 1 min = 60 s
Calculating distance from speed and time:
Converting distance from km to m:
So the distance traveled by the car in 37.0 s is 894 m.
Answers
Final answer:
The combustion of ethane yields carbon dioxide, and with 5.90 moles of ethane being reacted, it results in the production of 11.8 moles of CO2.
Explanation:
The question pertains to the concept of stoichiometry in chemistry, and the chemical reaction in question is a combustion reaction involving ethane (C2H6). From the balanced reaction, it is evident that 2 moles of ethane (C2H6) produce 4 moles of carbon dioxide (CO2). Therefore, if we have 5.90 moles of ethane reacting, it's a straightforward calculation to determine that this would yield twice that many moles of CO2. We simply multiply the moles of ethane by the stoichiometric ratio (4/2) to get the moles of CO2.
Example Calculation: 5.90 moles of ethane x (4 moles CO2 / 2 moles C2H6) = 11.8 moles CO2
So, when 5.90 moles of ethane are burned in an excess of oxygen, 11.8 moles of CO2 are produced.
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Final answer:
In the combustion of ethane, for every mole of ethane burned, two moles of carbon dioxide are produced. Hence, when 5.90 moles of ethane are burned, 11.8 moles of carbon dioxide are produced.
Explanation:
The chemical reaction given, 2C2H6(g) + 7O2(g) ⟶ 4CO2(g) + 6H2O(g), states that 2 moles of ethane (C2H6) produce 4 moles of carbon dioxide (CO2). Thus, the mole-to-mole ratio of ethane to carbon dioxide is 2:4, or simplified, 1:2. So, for every mole of ethane burned, two moles of carbon dioxide are produced.
Given that 5.90 moles of ethane are burned, we can calculate the quantity of carbon dioxide produced by multiplying 5.90 moles by 2. Hence, when 5.90 moles of ethane are burned in an excess of oxygen, 11.8 moles of carbon dioxide are produced.
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What is she most known for?
Write down three interesting facts about her
life.
Answers
Answer:
See explanation
Explanation:
Hypatia is popular for her work in mathematics. She also did some work in the area of astronomy. Her well know work in mathematics is her ideas about conic sections.
She was born the Theon of Alexandria and she was a professional mathematician in her life time.
She was the greatest mathematician of her time and she was telling leader of the Neoplatonist school of philosophy in Alexandria. By so doing, she conquered the culture of sexism in her time.
She was trained by her father in mathematics and eventually replaced him. She was the last major mathematician in the Alexandrian tradition.