A pharmacist wishes to strengthen a mixture from 10%alcohol to 30% alcohol. How much pure alcohol should be added to 7 liters of the 10% mixture?

Answers

Answer 1
Answer:

Answer:

2 litres of pure alcohol will be added to make the overall concentration of 9 litres of mixture as 30%.

Explanation:

Suppose x is the number of litres added to the 10% mixture than the quantity of new mixture is given as below

  • n_(old)=7 litres
  • n_(new)=7+x litres

Also the quantity of alcohol is given as

  • q_(old)=10 \% \, of \, 7 \, litres =0.7
  • q_(added)=x
  • q_(new)= 30 \% \,of \,new\, quantity = 0.3(7+x)

Now the equation is as

                                  q_(old)+q_(added)=q_(new)\n0.7+x=0.3(7+x)\n0.7+x=2.1+0.3x\nx-0.3x=2.1-0.7\n0.7x=1.4\nx=2 \, litres

So 2 litres of pure alcohol will be added to make the overall concentration of 9 litres of mixture as 30%.


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Which of the following reactions would have the smallest value of K at 298 K? Which of the following reactions would have the smallest value of K at 298 K? A + B → 2 C; E°cell = -0.030 V A + 2 B → C; E°cell = +0.98 V A + B → C; E°cell = +1.22 V A + B → 3 C; E°cell = +0.15 V More information is needed to determine.

Answers

The reactions that would have the smallest value of K is

A + B → 2 C; E°cell = -0.030 V

Option A

Generally the equation for the number of electrons transferred  is mathematically given as

nFE^o_(cell)=RT\ln K

where

T= Temperature

F=25C(298K)

R = Gas constant

R= 8.314 J/K.mol

F = Faraday's constant

F= 96500 C

We see from the equation that the E-cell is directly proportional to K(equilibrium constant of the reaction)

Hence, The reactions that would have the smallest value of K is

A + B → 2 C; E°cell = -0.030 V

For more information on Reaction

brainly.com/question/11231920

Answer:

The reaction with smallest value of K is :

A + B → 2 C; E°cell = -0.030 V

Explanation:

nFE^o_(cell)=RT\ln K

where :

n = number of electrons transferred

F = Faraday's constant = 96500 C

E^o_(cell) = standard electrode potential of the cell

R = Gas constant = 8.314 J/K.mol

T = temperature of the reaction = 25^oC=[273+25]=298K

K = equilibrium constant of the reaction

As we cans see, that standard electrode potential of the cell is directly linked to the equilibrium constant of the reaction.

  • Higher E^o_(cell) higher will be the value of K.
  • Lower E^o_(cell) lower will be the value of K.

So, the reaction with smallest value of electrode potential will have smallest value of equilibrium constant. And that reaction is:

A + B → 2 C; E^o_(cell) =-0.030 V

A 230 kg steel crate is being pushed along a cement floor. The force of friction is 480 N to the left and the applied force is 1860 N to the right. The forces acting on the crate are

Answers

are radioactive waves , hope this helps

What is the principal reason we must consider the uncertainty principle when discussing electrons and other subatomic particles but not when discussing our macroscopic world?

Answers

The principal reason why we must consider the uncertainty principle when discussing electrons and other subatomic particles but not when discussing our macroscopic world is:

  • Photons of certain frequencies can be absorbed as the electron changes energy state

According to the given question, we need to state the principal reason why the uncertainty principle is used when discussing electrons and other subatomic particles but not used in our macroscopic world.

As a result of this, we can see that the reason for this is because there are certain frequencies at which the photons can be absorbed during the electron change as energy becomes more random.

Read more here:

brainly.com/question/15868729

Here is the correct answer of the given question above. The principal reason that we must consider the uncertainty principle when discussing electrons and other subatomic particles, but not when discussing our macroscopic world is that photons of only certain allowed frequencies can be absorbedor emitted as the electron changes energy state. Hope this answer helps.

Given that e = 9.0 v , r = 98 ω and c = 23 μf , how much charge is on the capacitor at time t = 4.0 ms

Answers

Let charge across the capacitor be Q, current through the circuit be I.
Voltage difference across the resistor = rI
Voltage difference across the capacitor = Q/c
Loop rule: net voltage change through a loop must be zero, so
9 = rI + Q/c. Since I = dQ/dt,
r dQ/dt + Q/c = 9
Solving, Q = 9c (1 - e^(t/rc)). Plug in the numbers from the problem for the numerical answer.

How do you figure out the # of
neutrons?

Answers

Answer:

Subtracting the number of protons from the atomic mass.

Answer:

Subtract Protons

Explanation:

Since the vast majority of atom's mass is found it's protons and neutrons, Subtracting the Number of Protons ( i.e. the atomic number ) from the atomic mass will give you the calculated number of neutrons in a atom,

If a large marshmallow has a volume of 2.75 in3 and density of 0.242 g/cm3, how much would it weigh in grams? 1 in3=16.39 cm3.

Answers


•   
Volume of the marshmallow:

V = 2.75 in^3          (but, 1 in^3 = 16.39 cm^3)

V = 2.75 × 16.39 cm^3

V = 2.75 × 16.39 cm^3

V = 45.0725 cm^3


•   Density:

d = 0.242 g/cm^3


•  Mass:

m = d × V

m = (0.242 g/cm^3) × (45.0725 cm^3)

m = (0.242 g/cm^3) × (45.0725 cm^3)

m = 10.907545 g

m ≈ 10.9 g   <———  this is the answer.


I hope this helps. =)

Answer:

9.92g

Explanation:

2.50 in31×16.39 cm31 in3×0.242 gcm3=9.92 g