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How many grams of CuSO4 5 H20 are needed to make 1 liter of a 2% (w/v) CuSO4. REPORT TO THE NEAREST 1/10 G.

Answers

Answer 1

Answer:

Answer:

19.9 grams of $CuSO_4.5H_2O$ will be needed.

Explanation:

Required strength of the solution = 2% (w/v)

This means that 2 gram of solute in 100 ml of solution.

Mass of $CuSO_4.5H_2O$ = 2 g

Moles of $CuSO_4.5H_2O$ = $(2 g)/(249.68 g/mol)=0.008010 mol$

Volume of the solution = 100 mL = 0.1 L

Molarity of the solution:

$M=(0.008010 mol)/(0.1 L)=0.08010 mol/L$

0.08010 moles of $CuSO_4.5H_2O$ are present 1 l of the solution.

Then mass of 0.08010 moles of $CuSO_4.H_2O$ will be:

0.08010 mol × 249.68 g/mol = 19.9993 g≈ 19.9 g

19.9 grams of $CuSO_4.5H_2O$ will be needed.

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Given the information about each pair of acids fill in the correct answer. a. Acid A has a lower % ionization than B:_______ is a stronger acid. b. Acid B has a larger K_a than acid A._______ will have a larger percent ionization. c. A is a stronger acid than B. Acid B will have________ percent ionization than A.
How many atoms are in 2.3 moles Au?
The table shows a chemical equation and the dimensional analysis used by a student to calculate the number of moles of Ba3N2 required to produce 6.7 moles of Ba(OH)2. Student's Dimensional Analysis Chemical Equation Dimensional Analysis Ba3N2 + 6H2O → 3Ba(OH)2 + 2NH3 3 mol of Ba(OH)2 x 1 mol of Ba3N2 / 6.7 mol of Ba(OH)2 What is the error in the dimensional analysis?
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The enthalpy of combustion of acetylene C2H2 is described by C2H2(g) + (5/2) O2(g) →2CO2(g) + H2O(l), Hrxn= –1299 kJ/mol. Calculate the enthalpy of formation of acetylene, given the following enthalpies of formation Hf[CO2(g)] = –393.5 kJ/mol Hf[H2O(l)] = –285.8 kJ/mo

Use molecular orbital theory to determine whether f22+ is paramagnetic or diamagnetic.

Answers

We have to know whether F₂²⁺ is paramagnetic or diamagnetic.

F₂²⁺ is paramagnetic.

If number of unpaired electron in any species is equal to zero, the species is diamagnetic and the species contains unpaired electrons, then the species is paramagnetic.

The magnetic property can be explained using molecular orbital theory.

Total number of electron present in F₂²⁺ is equal to 16 (i.e, 9+9-2). From the molecular orbital electronic configuration, number of electrons present in pi orbitals present is equal to 2.

So, F₂²⁺ is paramagnetic.

Answer : $F_2^(2+)$ is paramagnetic.

Explanation :

According to the molecular orbital theory, the general molecular orbital configuration will be,

$(\sigma_(1s)),(\sigma_(1s)^*),(\sigma_(2s)),(\sigma_(2s)^*),[(\pi_(2p_x))=(\pi_(2p_y))],(\sigma_(2p_z)),[(\pi_(2p_x)^*)=(\pi_(2p_y)^*)],(\sigma_(2p_z)^*)$

As there are 9 electrons present in fluorine.

The number of electrons present in $F_2^(2+)$ molecule = 2(9) - 2 = 16

The molecular orbital configuration of $F_2^(2+)$ molecule will be,

$(\sigma_(1s))^2,(\sigma_(1s)^*)^2,(\sigma_(2s))^2,(\sigma_(2s)^*)^2,(\sigma_(2p_z))^2,[(\pi_(2p_x))^2=(\pi_(2p_y))^2],[(\pi_(2p_x)^*)^1=(\pi_(2p_y)^*)^1],(\sigma_(2p_z)^*)^0$

Paramagnetic compounds : They have unpaired electrons.

Diamagnetic compounds : They have no unpaired electrons that means all are paired.

The number of unpaired electron in molecule is, 2. So, this is paramagnetic. That means, more the number of unpaired electrons, more paramagnetic.

Thus, is paramagnetic.

Boyd takes additional measurements of the mass of product formed in a reaction. He uses a balance that has smaller graduations than the first balance he used. What is Boyd most likely trying to change?
He is trying to increase his accuracy but not his precision.
He is trying to increase his precision but not his accuracy.
He is trying to decrease his precision and increase his accuracy.
He is trying to increase his precision and decrease his accuracy.

apparently not He is trying to increase his accuracy but not his precision.

Answers

Boyd is most likely trying to increase his accuracy but not his precision. Therefore, option A is correct.

What are accuracy and precision?

Accuracy and precision can be described as two measures of observational error. Accuracy can be defined as how close a given set of measurements, are to their true value, while precision can be defined as how close the measurements are with respect to each other.

In other words, precision can be considered a description of random errors, as well as a measure of statistical variability. Accuracy is a description of systematic errors while low accuracy can bring a difference between a result and a true value.

Accuracy as describing a combination of both kinds of observational error, so high accuracy needs both high precision and high trueness.

In simpler terms, given a set of data points from repeated measurements of the same amount, the sample can be said to be accurate if its average is close to the true value being measured.

Learn more about accuracy and precision, here:

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Answer:

The answer is D) He is trying to increase his accuracy and precision.

Explanation:

edg2020

hope this helped :)

Lithium (Li) has a charge of +1, and oxygen has a charge of -2. Which is the chemical formula?

Answers

Considering the formation of a chemical formula, the chemical formula is Li₂O.

Ionic compounds

Cations (positivelycharged ions) and anions (negatively charged ions) combine to form ionic compounds, which must be electrically neutral. Therefore, the cations and anions must combine in such a way that the net charge contributed by the total number of cations exactly cancels the net charge contributed by the total number of anions.

Formation of a chemical formula

To form the chemical formula:

It is first necessary to place the chemical symbol of the element that is a cation, and then the negative part (anion).
Since the net charge of the compound formed must be zero (that is, add zero), when cations and anions with different charges are joined, it is necessary to cross them and place them as subscripts of the other element. In this way, balanced loads are obtained, that is, the algebraic sum is equal to zero.

Chemical formula in this case

Lithium (Li) has a charge of +1, and oxygen has a charge of -2. Taking into account the above, the chemical formula is Li₂O.

Answer:

Lithium formula=Li+

Oxygen formula=O2(2-)

Explanation:

Quick note: These kinds of formula are really easy to google. Next time, google the chemical name, include the charge and include "formula" and you should get the answer.

Are the bonds that chlorine forms with sodium (to form NaCl) and with carbon (to form CCl4) the same in both compounds?

Answers

Taking into account the definition of ionic and covalent bond, the bonds that chlorine forms with sodium (to form NaCl) and with carbon (to form CCl₄) are different in both compounds.

Ionic bond

An ionic bond is a type of chemical bond that occurs when one atom gives up an electron to the other, in order for both to achieve electronic stability.

This union normally occurs between metal and nonmetal elements with different electronegativity, which means that the elements have different capacity to attract electrons.

In other words, an ionic bond is produced between metallic and non-metallic atoms, where electrons are completely transferred from one atom to another. During this process, one atom loses electrons and another one gains them, forming ions. Usually, the metal gives up its electrons forming a cation to the nonmetal element, which forms an anion.

Covalent bond

The covalent bond is the chemical bond between atoms where electrons are shared, forming a molecule. Covalent bonds are established between non-metallic elements, such as hydrogen H, oxygen O and chlorine Cl. These elements have many electrons in their outermost level (valence electrons) and have a tendency to gain electrons to acquire the stability of the electronic structure of noble gas.

Bonds of NaCl and CCl₄

In the case of NaCl, Na is a metal while Cl is a nonmetal. So NaCl is an ionic bond.

On the other hand, in the case of CCl₄ both C and Cl are two non-metallic elements. So CCl₄ is a covalent bond.

In summary, the bonds that chlorine forms with sodium (to form NaCl) and with carbon (to form CCl₄) are different in both compounds.

Learn more about

ionic bond:

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covalent bond:

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Answer:

No, NaCl is formed by an ionic bond, and CCl4 would be formed by covalent bonds.

Explanation:

NaCl is an ionic bond because of their opposite charges while carbon and chlorine are sharing their electrons making it a covalent bond.

Which indicator will be the same color in hydrochloric acid as it is in pure water?1.methyl orange
2.phenolphthalein
3.bromcresol green

Answers

Phenolphthalein
In acid it is colourless and in water also colourless

A mixture of neon and xenon gases, at a total pressure of 739 mm Hg, contains 0.919 grams of neon and 19.1 grams of xenon. What is the partial pressure of each gas in the mixture?_______g Xe

Answers

Answer:

Partial pressure of neon = 175 mmHg

Partial pressure of xenon = 564 mmHg

Explanation:

The partial pressure of a gas in a mixture can be calculated as the product of the mole fraction of the gas (Xi) and the total pressure (Pt), as follows:

Pi = Xi Pt

The total pressure is 739 mmHg ⇒ Pt = 739 mmHg

In order to calculate the mole fraction of each gas, we have to first calculate the number of moles of each gas (n) by dividing the mass of the gas into the molar mass (MM):

For neon gas (Ne):

MM(Ne) = 20.18 g/mol

n(Ne)= mass/MM = 0.919 g x 1 mol/20.18 g = 0.045 mol Ne

For xenon gas (Xe):

MM(Xe) = 131.3 g/mol

n(Xe)= mass/MM = 19.1 g x 1 mol/131.3 g = 0.145 mol Xe

Now, we calculate the mole fraction (X) by dividing the number of moles of the gas into the total number of moles (nt):

nt= moles Ne + moles Xe = 0.045 mol + 0.145 mol = 0.190 mol

X(Ne) = moles Ne/nt = 0.045 mol/0.190 mol = 0.237

X(Xe) = moles Xe/nt = 0.145/0.190 mol = 0.763

Finally, we calculate the partial pressures of Ne and Xe as follows:

P(Ne) = X(Ne) x Pt = 0.237 x 739 mmHg = 175 mmHg