Answer the following questions about the last lesson below. What did we figure out about chain reactions? What did we figure out about fission? Fission produce more energy than a typical fuel sources, chain reaction

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Answer 1

Answer:

Answer:

(Nothing)-But No answer

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When 2.25 g of sodium hydroxide (NaOH) was dissolved in 150.00 g of water a value of 11.00oC was obtained for ΔT.1. Calculate the molarity of the sodium hydroxide solution.
2. Calculate the value (calories) for the heat of solution of 2.25 g of NaOH.
3. Calculate the number of calories that would be produced if one mole of sodium hydroxide was dissolved. (ΔHsolnNaOH)

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Answer:

For 1: The molarity of sodium hydroxide solution is 0.375 M

For 2: The amount of heat absorbed by solution is 1674.75 Cal

For 3: The enthalpy change of the reaction when 1 mole of NaOH is dissolved is 1674.75 Cal

Explanation:

For 1:

To calculate mass of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of water = 1 g/mL

Mass of water = 150.00 g

Putting values in above equation, we get:

$1g/mL=\frac{150.00g}{\text{Volume of water}}\n\n\text{Volume of water}=(1g/mL* 150.00g)=150.00mL$

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}* 1000}{\text{Molar mass of solute}* \text{Volume of solution (in mL)}}$

We are given:

Mass of solute (sodium hydroxide) = 2.25 g

Molar mass of sodium hydroxide = 40 g/mol

Volume of solution = 150.00 mL

Putting values in above equation, we get:

$\text{Molarity of solution}=(2.25g* 1000)/(40g/mol* 150mL)\n\n\text{Molarity of solution}=0.375M$

Hence, the molarity of sodium hydroxide solution is 0.375 M

For 2:

To calculate the amount of heat absorbed, we use the equation:

$q=mc\Delta T$

where,

m = mass of solution = (2.25 + 150) = 152.25 g

c = specific heat capacity of water = 1 Cal/g.°C

$\Delta T$ = change in temperature = 11°C

Putting values in above equation, we get:

$q=152.25g* 1Cal/g.^oC* 11^oC\n\nq=1674.75Cal$

Hence, the amount of heat absorbed by solution is 1674.75 Cal

For 3:

To calculate the enthalpy change of the reaction, we use the equation:

$\Delta H_(rxn)=(q)/(n)$

where,

$q$ = amount of heat absorbed = 16

74.75 Cal

n = number of moles = 1 mole

$\Delta H_(rxn)$ = enthalpy change of the reaction

Putting values in above equation, we get:

$\Delta H_(rxn)=(1674.75Cal)/(1mol)=1674.75Cal/mol$

Hence, the enthalpy change of the reaction when 1 mole of NaOH is dissolved is 1674.75 Cal

Final answer:

The molarity of the sodium hydroxide is 0.375 M. The heat of solution of the sodium hydroxide is -1650 cal, and the heat of solution per mole of sodium hydroxide is -29333.33 cal/mol.

Explanation:

To answer your questions, we first need to convert the mass of the sodium hydroxide (NaOH) to moles. Sodium hydroxide has a molar mass of approximately 40 g/mol, so 2.25 g is 0.05625 mol.

1. The molarity of the solution is the number of moles of solute per liter of solution. Given that the solution was made up in 150.00 g of water, which is approximately 0.150 L (since the density of water is approximately 1 g/mL), the molarity is 0.05625 mol / 0.150 L = 0.375 M.

2. The heat of solution can be calculated using the equation q = m * c * ΔT, where m is the mass of the water, c is the specific heat capacity of the water (approximately 1 cal/g°C), and ΔT is the change in temperature. Plugging in the known values, q = 150.00 g * 1 cal/g°C * 11°C = 1650 cal. This is the heat absorbed by the water and so the heat of solution of NaOH is -1650 cal (as the process of dissolving is exothermic).

3. The heat of solution per mole of sodium hydroxide can be calculated by dividing the total heat of solution by the number of moles of sodium hydroxide. So ΔHsoln NaOH = -1650 cal / 0.05625 mol = -29333.33 cal/mol.

Learn more about Thermodynamics and Stoichiometry here:

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Answer:

Mhmmm I Agree

Explanation:

Its Because I Strongly Agree

Which part of the electromagnetic spectrum is nearest to x rays

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to the left of X rays are Gamma rays and to the right if X rays ate Ultra Violet rays.

Answer:

I say microwaves

Explanation:

Suppose you perform a titration of an unknown weak acid solution. You start with 4.00 mL of the weak acid and find that it takes 14.2 mL of 0.0500 M NaOH to reach the equivalence point. What is the concentration of the unknown weak acid solution

Answers

Answer:

0.1775 M

Explanation:

The reaction that takes place is:

HA + NaOH → NaA + H₂O

Where HA is the unknown weak acid.

At the equivalence point all HA moles are converted by NaOH. First we calculate how many NaOH moles reacted, using the given concentration and volume:

0.0500 M NaOH * 14.2 mL = 0.71 mmol NaOH

That means that in 4.00 mL of the weak acid solution, there were 0.71 weak acid mmoles. With that in mind we can now calculate the concentration:

0.71 mmol HA / 4.00 mL = 0.1775 M

How many grams of NaBr must he measure out to have 4.20 moles?

Answers

Answer: 432 grams

Explanation:NaBr must he measure out to have 4.20 moles.

Please help me out asap. I’ll give brainliest

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Answer:

I belive the answer is A but the image quality is hard to tell.

Explanation:

As pressure increases the higher the melting point of rock becomes making it harder to melt, thats why molten rocks brought to the surface melt because of the change in pressure.

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