Be sure to answer all parts.Calculate the percent composition by mass (to 4 significant figures) of all the elements in calcium
phosphate (Ca3(PO4)2), a major component of bone.
% Ca
%P
% 0​

Answers

Answer 1
Answer:

Answer:

38.7%

41.3%

20%

Explanation:

The percentage composition helps to know the what percent of the total mass of a compound is made up of each of the constituent elements or groups.

To solve this problem:

  • find the formula mass by adding the atomic masses of the atoms that makes up the compound.
  • place the mass contribution of the element or group to the formula mas and multiply by 100;

Compound:

 Ca₃(PO₄)₂

  Formula mass = 3(40) + 2[31 + 4(16)]

                           = 120 + 2(95)

                           = 120 + 190

                           = 310

%C = (3(40))/(310) x 100  = 38.7%

%P = (8(16))/(310) x 100  = 41.3%

%O = (2(31))/(310) x 200  = 20%


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7. A species is _ when its population has become so low that it is close to becoming extincta. Massive logging b. endangered c. pollutants d. population

pa help po,,,​

Answers

Answer:

Endangered. The meaning of endangered is when a species declines in number- this might be because they are being eaten by another animal which has a higher popupayion, or perhaps because they are being hunted by humans for their meat or fur. Neither reason might be that their food or habitat has been destroyed b humans to create land for farming or housing. one example of name endangered species is Polar Bears: they like in the Antarctic where there is no land, simply ice. Due to humans causing climate change, the world is warming up and the ice is melting. This means polar bears are dying out because it would be too tiring to swim to find ice. For the same reason, other animals are dying in the Antarctic meaning that Poplar Bears have less to eat (being at the top of the food chain -no animal eats polar bears).

Does H form cation, anion both or neither ions?

Answers

Answer:

hydrogen have electronic configuration of 1s¹ to acquire a stable state it can either lose electron and form H+cation or gain an electron( to compete its 1s subshell ) to form H- anion. As it has ±1 valency it is placed neither in group 1(alkaline metals ) nor in group 17 (halogens) .

Write the number 4.92 x 10-3 from scientific notation to regular.
Please help?????

Answers

Explanation:

4.92*10-3=4.92/10^3=

4.92/1000=0.00492

Suppose, in an experiment to determine the amount of sodium hypochlorite in bleach, you titrated a 26.34 mL sample of 0.0100 M K I O 3 with a solution of N a 2 S 2 O 3 of unknown concentration. The endpoint was observed to occur at 15.51 mL . How many moles of K I O 3 were titrated

Answers

Answer:

0.1 M

Explanation:

The overall balanced reaction equation for the process is;

IO3^- (aq)+ 6H^+(aq) + 6S2O3^2-(aq) → I-(aq) + 3S4O6^2-(aq) + 3H2O(l)

Generally, we must note that;

1 mol of IO3^- require 6 moles of S2O3^2-

Thus;

n (iodate) = n(thiosulfate)/6

C(iodate) x V(iodate) = C(thiosulfate) x V(thiosulfate)/6

Concentration of iodate C(iodate)= 0.0100 M

Volume of iodate= V(iodate)= 26.34 ml

Concentration of thiosulphate= C(thiosulfate)= the unknown

Volume of thiosulphate=V(thiosulfate)= 15.51 ml

Hence;

C(iodate) x V(iodate) × 6/V(thiosulfate) = C(thiosulfate)

0.0100 M × 26.34 ml × 6/15.51 ml = 0.1 M

Final answer:

To determine the moles of KIO_3 titrated, use the balanced equation 2 KIO_3 + 5 Na_2S_2O_3 + 6 HCl → 3 I_2 + 6 NaCl + 6 NaClO + 3 H_2O. Therefore, 0.001551 mol of KIO_3 were titrated.

Explanation:

To determine the moles of KIO3 titrated, we need to use the balanced equation for the reaction:

2 KIO3 + 5 Na2S2O3 + 6 HCl → 3 I2 + 6 NaCl + 6 NaClO + 3 H2O

From the equation, we can see that 2 moles of KIO3 react with 5 moles of Na2S2O3. Therefore, the moles of KIO3 titrated can be calculated using the following proportion:

(0.0100 M KIO3 / 1 L) * (15.51 mL / 1000 mL) * (2 mol KIO3 / 5 mol Na2S2O3) = 0.001551 mol KIO3

Learn more about Moles of KIO_3 titrated here:

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The Heat of vaporization for NH3= 1360 J/g. Calculate the quantity of heat energy (in kJ)needed to completely boil a 155 gram sample at its boiling point
general formula

Answers

Answer:

Q=210.8kJ

Explanation:

Hello!

In this case, since the heat of vaporization is related with the energy required by a substance to undergo the phase transition from liquid to gas, we can compute such amount of energy as shown below:

Q=m\Delta H_(vap)

In such a way, since the enthalpy of vaporization is given as well as the mass, we compute the energy as shown below:

Q=155g*1360J/g\n\nQ=210.8kJ

Best regards!

When 28 g of nitrogen and 6 g of hydrogen react, 34 g of ammonia are produced. If 100 g of nitrogen react with 6 g of hydrogen, how much ammonia will be produced? 106 g 34 g 128 g 40 g

Answers

Answer:

34 g

Explanation:

Let's consider the following balanced equation.

N₂ + 3 H₂ → 2 NH₃

The theoretical mass ratio of N₂ to H₂ is 28g N₂ : 6g H₂ = 4.6g N₂ : 1g H₂.

The experimental mass ratio of N₂ to H₂ is 100g N₂ : 6g H₂ = 16.6g N₂ : 1g H₂.

As we can see, hydrogen is the limiting reactant.

According to the task, we 6 g of H₂ react completely, 34 g of ammonia are produced.