Answers
Answer:
Formation of precipitate
Formation of soluble salts
Explanation:
Let's consider the molecular equation that takes place when an aqueous solution of cesium sulfate is mixed with an aqueous solution strontium perchlorate.
Cs₂SO₄(aq) + Sr(ClO₄)₂(aq) ⇒ 2 CsClO₄(aq) + SrSO₄(s)
According to the solubility rules:
- CsClO₄ is a soluble salt.
- SrSO₄ is an insoluble salt that precipitates as a solid.
For a double displacement reaction to occur, at least one of the products must be insoluble or volatile.
Answer:
It's b) Formation of a precipitate
Explanation:
I took the quiz and got it right.
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Consider the following balanced redox reaction: 2CrO2-(aq) + 2H2O(l) + 6ClO-(aq) LaTeX: \longrightarrow⟶ 2CrO42-(aq) + 3Cl2(g) + 4OH-(aq) 1. Which species is being oxidized? 2. Which species is being reduced? 3. Which species is the oxidizing agent? 4. Which species is the reducing agent? 5. How many electrons are being transferred? Hint: If you were to balance this equation how many electrons would be in each half-reaction? That is how many electrons are transferred.
Answers
Answers
Answer:
- lowered vapor pressure
- higher boiling point
Explanation:
The colligative properties of a given solution can be defined as the properties of that solution that are dependent on the concentration of the molecules or ions of the solute in the solution, and not on the type or identity of that solute. Examples include:
1. vapor pressure lowering
2. boiling point elevation
3. freezing point depression
4. Osmotic pressure
In this case, vapor pressure would be lowered because with an electrolyte introduced into a solution, the number of solute particles would be larger because the solute particles dissociate into ions, thereby competing with the solvent molecules at the surface of the solution, which in turn reduces the rate at which the solvent evaporates and condenses. Vapor pressure is lower compared to a solution with the same number of moles of nonelectrolyte solute.
The higher the number of ions in the solution, the greater the colligative properties of the solution will be impacted.
Final answer:
The presence of a strong electrolyte in solution affects the colligative properties differently than a non-electrolyte solute. Strong electrolytes dissociate into ions, increasing the number of particles in solution. This affects colligative properties such as vapor pressure, boiling point elevation, freezing point depression, and osmotic pressure.
Explanation:
The presence of a strong electrolyte in solution affects the colligative properties differently than the same number of moles of a non-electrolyte solute. This is because strong electrolytes dissociate into ions when dissolved in solution, while non-electrolytes do not. The dissociation of strong electrolytes increases the total number of particles in solution, which affects colligative properties such as vapor pressure, boiling point elevation, freezing point depression, and osmotic pressure.
For example, let's compare a solution of 1 mole of sodium chloride (NaCl) to a solution of 1 mole of sucrose (C12H22O11). The sodium chloride will dissociate into Na+ and Cl- ions, which means there are now 2 particles in solution (1 Na+ and 1 Cl-) instead of just 1 molecule of sucrose. This higher particle concentration will result in a greater depression of the freezing point and elevation of the boiling point compared to the sucrose solution.
In summary, the presence of a strong electrolyte increases the number of particles in solution, leading to greater deviations in colligative properties compared to the same number of moles of a non-electrolyte solute.
Learn more about Colligative properties here:
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Answers
Answer :
Sugar : Compound
Air : Homogeneous mixture
Hot tea : Homogeneous mixture
Salt water : Homogeneous mixture
Explanation :
Element : It is a pure substance which is composed of atoms of similar elements.
Compound : It is a pure substance which is made from atoms of different elements combined together in a fixed ratio by mass.
Heterogeneous mixtures : It is a mixture that has non-uniform composition throughout the solution and the particle size or shapes are also different.
There is a physical boundary between the dispersed phase and dispersion medium.
Homogeneous mixtures : It is a mixture that has uniform composition throughout the solution and the particle size or shapes are not different.
There is no physical boundary between the dispersed phase and dispersion medium.
As per question,
Sugar : It is a compound that is made from atoms of different elements combined together in a fixed ratio by mass.
Air : It is a homogeneous mixture of the gaseous substances of nitrogen, oxygen, and smaller amounts of other substances.
Hot tea : It is a homogeneous mixture because its composition is the same throughout the solution.
Salt water : It is a homogeneous mixture because its composition is the same throughout the solution.
Sugar compound
Air Homogeneous mixture
Hot tea Homogeneous mixture
Salt water Homogeneous mixture
Element:
An element is a simplest type of a pure substance which is composed of only one type of matter. For examples; silver, gold platinum etc.
Pure substance:
A compound is a pure substance which is composed of two or more type of matter in definite proportion. For examples; water which is composed by Hydrogen and oxygen etc.
Mixture:
A mixture is made from two or more type of matter in any proportion. Mixture are generally two types:
1. Homogeneous mixture
This is also known as solution, in which the composition of the substances is uniform.
Lemon-flavored water is an example of homogeneous mixture because in this the composition of the substances is uniform.
2. Heterogeneous mixture
In this form of mixture the composition of substance are not uniform and the component of mixture also visible.
Stuffed mushrooms is an example of Heterogeneous mixture because in this form of mixture the composition of substance are not uniform and the component of mixture also visible.
step.
B. The enthalpy is determined from the enthalpy of similar reactions.
C. The enthalpy from the final equation in a series of reactions is
used
D. Intermediate equations with known enthalpies are added together.
Answers
Hess's law is used to measure the enthalpy of a desired chemical reaction because: D. Intermediate equations with known enthalpies are added together.
What is Hess's Law?
Hess's Law is also known as Hess's law of constant heat summation (enthalpy) and it was named after a Swiss-born Russian chemist called Germain Hess.
Hess's Law states that the energy change (enthalpy) experienced in a desired chemical reaction is equal to the sum of the energy changes (enthalpies) in each chemical reactions that it is made up of or contains.
Read more on Hess's Law here: brainly.com/question/9328637
Answers
The number which should be placed in front of CaSO4 to give the same total number of sulfate ions on each side of the equation is; 3.
According to the question;
- We are required to determine what number should be placed in front of CaSO4 to give the same number of each side of the equation.
The equation given is;
?CaSO4 + AlCl3 → CaCl2 + Al2(SO4)3
There are 3 moles of SO4 on the right hand side of the equation and as such, there should be the same number of SO4 on the left too.
In essence, the number that should be added in front of CaSO4 is; 3.
Read more:
Answer : The number placed in front of should be, three (3).
Explanation :
Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.
The given unbalanced chemical reaction is,
This chemical reaction is an unbalanced reaction because in this reaction, the number of atoms of chloride and sulfate ion are not balanced.
In order to balanced the chemical reaction, the coefficient 3 is put before the , the coefficient 2 is put before the
and the coefficient 3 is put before the
.
Thus, the balanced chemical reaction will be,
Therefore, the number placed in front of should be, three (3).
Answers
Answer:
38.96383282 amu
Explanation:
39.0983 = (40.9618 0.067302) + ( ?
(1-0.067302)
39.0983 = 2.756811064 + ( ? 0.932698)
subtract 2.756811064 from both sides
36.34148894 = ( ? 0.932698)
divide both sides by 0.932698
? = 38.96383282 amu
Answer:
38.96383282 amu
Explanation:
39.0983 = (40.9618 0.067302) + ( ? (1-0.067302)
39.0983 = 2.756811064 + ( ? 0.932698)
subtract 2.756811064 from both sides
36.34148894 = ( ? 0.932698)
divide both sides by 0.932698
? = 38.96383282 amu