How many formula units are in a 7.3 x 10-3 gram sample of lithium chloride, LiCI?

Answers

Answer 1
Answer:

Answer: 1.0 * 10^(20) formula units

Explanation:

so lets start off by looking at what we have. we have 7.3 * 10^(-3) g of LiCl

which is called Lithium Chloride. in order to convert g to moles, we divide the g by the molar mass of Lithium Chloride.

whip out that HANDY DANDY PERIODIC TABLE man the PERIODIC TABLE WILL SAVE YOUR LIFE SOME DAY! someone will walk up to you all mean, and youll be like, "what, you tryna MUG me?" and then you whack 'em with the periodic table like BAM! GOTTEM!

okay so lets look at the periodic table and we notice that the atomic mass of Lithium is 6.941 and the atomic mass of Chlorine is 35.453. notice that in LiCl there is only one of each. so lets add 6.941 + 35.453 = 42.394 g/mol.

now look at what we were given: converting the given quantity to standard format instead of scientific format, we have 0.0073 grams of lithium chloride. we can convert this to moles by dividing it by its molar mass which is 42.394. 0.0073 / 42.394 = 1.72 * 10^(-4)

now lets use AVOCADOS NUMBER i mean AVOGADROS NUMBER!! which is 6.02 * 10^(23)

multiply (1.72 * 10^(-4)) * (6.02 * 10^(23)) and we get 10.35 * 10^(19) formula units.

if you want to be specific about the significant figures, notice that the given quantity in the question only has two significant figures. so we can alter our final answer to only have two sig figs. lets change it: 1.0 * 10^(20) formula units


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A biochemist studying breakdown of the insecticide DDT finds that it decomposes by a first-order reaction with a half-life of 12.0 yr. How long does it take DDT in a soil sample to decompose from 809 ppbm to 10.0 ppbm (parts per billion by mass)

Which of the following statements regarding redox reactions is true? Which of the following statements regarding redox reactions is true? Redox reactions are only seen in the electron transport chain. Redox reactions involve an oxidation reaction coupled with a reduction reaction. No metabolic reactions are redox reactions. Redox reactions must either be oxidizing reactions or reducing reactions.

Answers

Answer:

Redox reactions involve an oxidation reaction coupled with a reduction reaction.

Explanation:

A redox reaction is called like that because it involves a substance that is reducing and a substance that is oxidating, so it is Re-dox, this means that all of the chemicals reactions that involve a substance that looses an electron, are redox reactions, they are present in almost all of chemistry, from syntetic to biological chemistry, so the only correct option would be:

Redox reactions involve an oxidation reaction coupled with a reduction reaction.

Answer: An oxidation reaction is defined as the when in a reaction the oxidation number of a species involved increased, and reduction reaction is reversed, it when the oxidation number of a species is decreased. And a redox reaction is in which both of oxidation and reduction reaction takes place simultaneosly. Because chemical reaction follows the law of conservation of mass.

6CO2 + 6H20 --> C6H12O6 + 602What is the total number of moles of CO2 needed to make 2 moles of CH1206?

Answers

Answer:

12 mol CO₂

General Formulas and Concepts:

Atomic Structure

  • Compounds
  • Moles
  • Mole Ratio

Stoichiometry

  • Analyzing reactions rxn
  • Using Dimensional Analysis

Explanation:

Step 1: Define

Identify

[rxn] 6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

[Given] 2 mol C₆H₁₂O₆

[Solve] mol CO₂

Step 2: Identify Conversions

[rxn] 6CO₂ → C₆H₁₂O₆

Step 3: Convert

  1. [DA] Set up:                                                                                                   \displaystyle 2 \ mol \ C_6H_(12)O_6((6 \ mol \ CO_2)/(1 \ mol \ C_6H_(12)O_6))
  2. [DA] Multiply [Cancel out units]:                                                                      \displaystyle 12 \ mol \ CO_2

Which of the following describes the element Mg. Choose all that apply. is very reactive as a metal forms a basic solution in water is found in nature only combined with other elements reacts vigorously with alkali metals to form salts consists of diatomic molecules in elemental form is one of the group of the least reactive elements

Answers

Answer:

The statements that describe Mg are:

1. is very reactive as a metal  

2. forms a basic solution in water  

3. is found in nature only combined with other elements

Explanation:

Magnesium is a s-block chemical element that belongs to group 2 and period 3 of the periodic table. It is a reactive alkaline earth metal that exists in nature only in the combined state with elements such as carbon, calcium and oxygen.

Magnesium reacts with water at room temperature, to give strongly basic metal oxide of the formula, MgO, which forms a basic solution in water.

It also reacts vigorously with halogens such as chlorine and bromine, to form salts.

Final answer:

Magnesium is a highly reactive alkaline earth metal that forms a basic solution in water and can react vigorously with alkali metals to form salts. It consists of diatomic molecules in its elemental form.

Explanation:

Magnesium is one of the alkaline earth metals, which are found in Group 2 of the periodic table. It is a highly reactive metal that forms a basic solution in water and can react vigorously with alkali metals to form salts. Magnesium also consists of diatomic molecules in its elemental form. However, it is not one of the least reactive elements; rather, it is one of the more reactive elements in Group 2.

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You have a stock solution of epinephrine at a concentration of 1 mg/mL. Knowing that the pipette you will use delivers 20 drops/mL, a. calculate the number of drops of the stock solution that must be added to a smooth muscle bath containing 25 mL of Locke’s solution so that the final concentration of epinephrine in the muscle bath will be 100 µg/mL, and

Answers

Answer : The number of drops pf the stock solution mist be added are, 50 drops.

Explanation :

As we are given that the concentration of stock solution 1 mg/mL and pipette delivers 20 drops/mL. That means,

1 mg of epinephrine = 1 mL = 20 drops

The final volume of Locke's solution = 25 mL

and the final concentration needed = 100\mu g/mL

As, 1 mL of solution contains = 100\mu g

So, 25 mL of solution contains = (25mL)/(1mL)* 100\mu g=2500\mu g=2.5mg

Conversion used :1\mu g=0.001mg

Now we have to determine the number of drops needed.

As, 1 mg of epinephrine contains 20 drops.

So, 2.5 mg of epinephrine contains 2.5 × 20 = 50 drops.

Therefore, the number of drops pf the stock solution mist be added are, 50 drops.

Final answer:

If you want to achieve a final concentration of 100 µg/mL of epinephrine in a 25 mL solution, when using a stock solution of 1 mg/mL and a pipette that delivers 20 drops/mL, you need to add 50 drops of your stock solution.

Explanation:

Since we are asked to find the number of drops of stock solution required to achieve a final concentration of 100 µg/mL in a 25 mL solution, the first step is to convert the concentration of the stock solution to the same units, µg/mL. Hence, 1 mg/mL is equal to 1000 µg/mL. Further, we know that 1 mL of the stock solution contains 1000 µg of epinephrine, and our pipette delivers 20 drops/mL, so 1 drop of stock solution contains 1000 µg / 20 drops = 50 µg. Thus, if we need a 100 µg/mL concentration in 25 mL, we need a total of 100 µg/mL * 25 mL = 2500 µg of epinephrine. Therefore, to achieve this, we must add 2500 µg / 50 µg/drop = 50 drops of our stock solution. Hence,

50 drops

of the stock solution should be added to achieve the desired concentration.

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In metallic bonds, the mobile electrons surrounding the positive ions are called a(n)

Answers

It is called, Noble gas

A chemist designs a galvanic cell that uses these two half-reactions:O2 (g) + 4H+(aq) + 4e− → 2H2O (l) Eo =+1.23V
Zn+2 (aq) + 2e− → Zn(s) Eo=−0.763V

Answer the following questions about this cell.

Write a balanced equation for the half-reaction that happens at the cathode.
Write a balanced equation for the half-reaction that happens at the anode.
Write a balanced equation for the overall reaction that powers the cell. Be sure the reaction is spontaneous as written. Do you have enough information to calculate the cell voltage under standard conditions

Answers

Answer: The reaction is spontaneous and there is not enough information to calculate the cell voltage.

Explanation:

The substance having highest positive E^o reduction potential will always get reduced and will undergo reduction reaction.

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

  • For a:

The half reactions for the cell occurring at cathode follows:

O_2(g)+4H^+(aq)+4e^-\rightarrow H_2O(l);E^o_(cathode)=+1.23V

  • For b:

The half reactions for the cell occurring at anode follows:

Zn(s)\rightarrow Zn^(2+)+2e^-;E^o_(anode)=-0.763V    ( × 2)

  • For c:

The balanced equation for the overall reaction of the cell follows:

O_2(g)+4H^+(aq)+2Zn(s)\rightarrow H_2O(l)+2Zn^(2+)(aq)

For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative.

Relationship between standard Gibbs free energy and standard electrode potential follows:

\Delta G^o=-nFE^o_(cell)

For a reaction to be spontaneous, the standard electrode potential must be positive.

To calculate the E^o_(cell) of the reaction, we use the equation:

E^o_(cell)=E^o_(cathode)-E^o_(anode)

Putting values in above equation, we get:

E^o_(cell)=1.23-(-0.763)=1.993V

As, the standard electrode potential of the cell is coming out to be positive, the reaction is spontaneous in nature.

  • To calculate the EMF of the cell, we use the Nernst equation, which is:

E_(cell)=E^o_(cell)-(0.059)/(n)\log ([Zn^(2+)]^2)/([H^(+)]^4* p_(O_2))

As, the concentrations and partial pressures are not given. So, there is not enough information to calculate the cell voltage.

Hence, the reaction is spontaneous and there is not enough information to calculate the cell voltage.