Answers
The weighted average (Avg) for these values has been 5.35.
The weighted average has been an arithmetic calculation of the mean value for the percent abundance of each value.
Computation for weighted average
The weighted average (Avg) for the values has been given by:
The values have been given,
The weighted average has been given as:
For the given set of values, the weighted average (Avg) has been given as:
The weighted average (Avg) for these values has been 5.35.
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Answer:
5.35
Explanation:
Value 5.00 6.00 7.00
Weight 75.0% 15.0% 10.0 %
We can determine the weighted average of these values using the following expression.
Weighted average = ∑ wi × xi
where,
w: relative weight
x: value
Weighted average = 5.00 × 0.750 + 6.00 × 0.150 + 7.00 × 0.100
Weighted average = 5.35
Related Questions
Please help 25 points :DPhases of Matter ActivityNow it is your turn to show what you know about phases of matter and thermal energy transfer! Your task is to create a presentation to explain the transformation of a substance as it changes phases. You may choose to write a story or create a comic strip. For your story or comic, you will create a main character and detail the adventure as your character is exposed to thermal energy, causing it to undergo phase changes from a solid, to a liquid, to a gas. You may create your own comic strip using drawings, presentation software, or this comic strip template.Your presentation must include the following:title and introduction of your character, including what substance the character is made ofsource of thermal energy your character encountered (conduction, convection, and/or radiation)a detailed description and/or diagram of the particle transformation from solid to liquid phasea detailed description and/or diagram of the particle transformation from liquid to the gas phaseYou may get creative on this activity. If you are unsure if your idea or software for a presentation will work, contact your instructor for assistance. Be sure to review the grading rubric before you begin.
In an attempt to prepare n−propylbenzene, a chemist alkylated benzene with 1−chloropropane and aluminum chloride. However, two isomeric hydrocarbons were obtained in a ratio of 2:1, the desired n−propylbenzene being the minor component. What do you think was the major product? How did it arise?
Calculate ΔHrxn for the following reaction: C(s) + H2O(g) --> CO(g) + H2(g) Use the following reactions and given ΔH values: C (s) + O2 (g) → CO2 (g), ΔH = -393.5 kJ 2 CO (g) + O2 (g) → 2 CO2 (g), ΔH= -566.0 kJ 2 H2 (g) + O2 (g) → 2 H2O (g), ΔH= -483.6 kJ
The combustion of ethane (C2H6) produces carbon dioxide and steam. 2C2H6(g)+7O2(g)⟶4CO2(g)+6H2O(g) How many moles of CO2 are produced when 5.90 mol of ethane is burned in an excess of oxygen?
Answers
Answer:
Explanation:
Hello!
In this case, since the phosphoric acid is a triprotic acid, we infer it has three stepwise ionization reactions in which one hydrogen ion is released at each step, considering they are undergone due to the presence of water, thus, we proceed as follows:
Moreover, notice each step has a different acid dissociation constant, which are quantified in the following order:
Ka1 > Ka2 > Ka3
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b. 90°.
c. 109°.
d. 120°.
e. 180°.
Answers
Answer:
Explanation:
BrCl₃ is an interhalogen compound with a hybridization of sp³d. The approximate bond angles can be predicted from the structure (attached below). Although, the lewis structure might be predicted to be trigonal bipyramidal from the structure, it is however a T-shaped geometry because of it's two lone pairs.
Also, from the structure attached, it can be predicted that the approximate bond angles about the central atom is 120° (360 ÷ 3) since each of the three chlorine atoms is equally spaced about the central atom.
The Lewis structure for BrCl₃ is attached to the image below. The bond angles around the central atom, bromine (Br), are 90 degrees between the bromine and each chlorine atom. Therefore, option B is correct.
A Lewis structure, also known as an electron-dot structure or Lewis dot structure is a diagram that represents the valence electrons of an atom or molecule.
Bromine (Br) is in Group 7A and has 7 valence electrons, while each chlorine (Cl) atom in Group 7A also has 7 valence electrons.
Br: 1 atom × 7 valence electrons = 7 valence electrons
Cl: 3 atoms × 7 valence electrons = 21 valence electrons
Total valence electrons = 7 + 21 = 28
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B) 3
C) 4
D) 7
Answers
Answer
A(1)
Explanation:
If you don't see a coefficient, which is the big number in front of the formula, then it's only one molecule.
Example of coefficient
4H3PO4
Answers
Zn(s) \ Zn²⁺(aq,0.100 M) // Zn²⁺(aq, x M) \ Zn(s)
voltage = 16 mV x (1V / 10³ mV) = 16 x 10⁻³ V
- In the cell notation, the concentration on the left is that of the anode and that on the right is that of the cathode.
- Oxidation takes place at the anode and reduction takes place at the cathode.
so [Zn²⁺]oxidation = 0.100 M
[Zn²⁺] reduction = x M
From Nernst equation:
Ecell = -0.0592 / n log [Zn²⁺] oxidation / [Zn²⁺]reduction
Number of electrons, n = 2. Substitute and solve for x:
16 x 10⁻³ V = - 0.0592 / 2 log (0.100 /x)
log 0.100 / x = - 0.54
0.100 / x = 0.288
x = 0.347
So the concentration of Zn²⁺ at the cathode = 0.406
Answers
The amount left after 1 half life = 16*1/2 = 8 g Then after each half life the amount of x will be 4 , 2 ,1 , 1/2, 1/4 grams
That's a total of 6 half-lives. Answer
Age s rock = 6*220,000 = 1,320,000 years Answer
Answers
Final answer:
The given reaction will shift towards cis-2-butene once placed in equilibrium. This can be determined by calculating the reaction quotient and comparing it with the equilibrium constant.
Explanation:
The reaction could either shift towards the cis-2-butene or trans-2-butene depending on whether the reaction quotient, Q, is lesser or greater than the equilibrium constant, Kp.
Bear in mind that Kp = Ptrans/Pcis. Let's say that Pt is the partial pressure of trans-2-butene and Pc is the partial pressure of cis-2-butene at equilibrium. If we start with 5 atm of each gas, the change in Pc is -x and the change in Pt is +x.
So, Kp = (5+x)/(5-x). We are given that Kp = 3.4. Solving these two equations will show that x is a negative value, which means that the system shifts towards cis-2-butene.
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Final answer:
For the isomerization reaction cis-2-butene ⇌ trans-2-butene, with an initial pressure of 5.00 atm for both gases and a Kp of 3.40, the system will shift towards the product, trans-2-butene, as Kp > Qp (1). This reflects the principle that a chemical system at equilibrium will shift to counteract any change.
Explanation:
In terms of the equilibrium constant (K), for gas-phase reactions, Kp represents equilibrium in terms of partial pressures, while Kc represents it in molar concentrations. For instance, in the isomerization reaction given cis-2-butene ⇌ trans-2-butene, Kp is given as 3.40. To determine the behavior of the system, we need to compare it to reaction quotient (Q). Given that the flask initially contains 5.00 atm of each gas, Qp is 1 (since Qp = partial pressure of trans-2-butene / partial pressure of cis-2-butene). Since Kp > Qp, the reaction will shift towards the products, hence the system will shift towards trans-2-butene. From this, it is clear that the equilibrium constant and reaction quotient play vital roles in determining the direction of shift in a chemical equilibrium.
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