In an attempt to prepare n−propylbenzene, a chemist alkylated benzene with 1−chloropropane and aluminum chloride. However, two isomeric hydrocarbons were obtained in a ratio of 2:1, the desired n−propylbenzene being the minor component. What do you think was the major product? How did it arise?
Answers
Answer:
2-Phenylpropane (Cumene)
Explanation:
Famous Friedel Craft Alkylation.
Aluminum Chloride grasped the 1-chloropropane forming an intermediate product composed of Aluminum tetrachloride and n-propylcation. It is well understood that primary carbocations are unstable and therefore undergo hydrogen shifting to attain stability. n-Propylcarbocation undergone hydrogen shifting, forming isopropylcarbocation which reacted with benzene forming 2-Phenylpropane as the major product and HCl as a byproduct.
AlCl3 + CH3CH2CH2Cl --> AlCl4- + CH3CH2CH2+
CH3CH2CH2+ ---> CH3CH(+)CH3
C6H6 + CH3CH(+)CH3 ---> C6H5CH(CH3)2 + H+
AlCl4- + H+ ---> HCl + AlCl3
Answer:
From the given problem statement,he was attempting to prepare n−propylbenzene by alkylation benzene with 1−chloropropane and aluminum chloride,but 1-propyle benze was a major product in result.
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A solution of HNO3HNO3 is standardized by reaction with pure sodium carbonate. 2H++Na2CO3⟶2Na++H2O+CO2 2H++Na2CO3⟶2Na++H2O+CO2 A volume of 27.71±0.05 mL27.71±0.05 mL of HNO3HNO3 solution was required for complete reaction with 0.9585±0.0007 g0.9585±0.0007 g of Na2CO3Na2CO3 , (FM 105.988±0.001 g/mol105.988±0.001 g/mol ). Find the molarity of the HNO3HNO3 solution and its absolute uncertainty.
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Answer: the gas is lighter than CO2 and it is hydrogen
Explanation:Please see attachment for explanation
Answers
Answer:
Explanation:
Hello,
In this case, considering that 1 m equals 10 dm, the required diameter of the atom in decimetres is:
Best regards.
Final answer:
The diameter of an atom is approximately 1 * 10^-10 * m, which translates to 1 * 10^-11 decimeters by multiplying the meter measurement by 10.
Explanation:
The subject of this question is a unit conversion. We are trying to convert the diameter of an atom from meters to decimeters.
The process is as follows:
- First, we need to understand that 1 meter equals 10 decimeters because the prefix 'deci-' means one-tenth.
- So, if the diameter of an atom is approximately 1 * 10^-10 * m, then in decimeters the diameter would be 1 * 10^-11 * dm
In essence, to convert meters to decimeters, we need to multiply the meter measurement by 10. But because the meter measurement of the atom is in the power of -10, the decimeter equivalent would be in the power of -11.
Learn more about Unit Conversion here:
#SPJ3
Answers
Answer:
Explanation:
Hello there!
In this case, according to the given chemical reaction, it is possible for us to realize that the 46.2 kJ of energy are given per mole of reaction, which are related to 3 moles of hydrogen; Thus, we can calculate the energy per mole of hydrogen as shown below:
Now, to calculate the total energy, we convert the grams to moles of hydrogen as shown below:
Best regards!
_ ML = 8,000,000 L
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Answer:
To find the value of the blank in the equation "_ ML = 8,000,000 L," you can simply fill in the blank with a number:
"_ ML = 8,000,000 L" can be filled in as "8,000 ML = 8,000,000 L."
So, the answer is 8,000 ML.
Culled from AI
Answers
Answer:
See attachment
Explanation:
The amine group of N,N-dimethylaniline is an electron-donating group and will cause the benzene ring to act as a nucleophile in an electrophilic aromatic substitution reaction with the diazonium salt of sulfanilic acid.