Answers
Answer:
1.06x10²² formula units
Explanation:
First we convert 5.164 g of CaI₂ into moles, using its molar mass:
- 5.164 g ÷ 293.887 g/mol = 0.0176 mol
Then we convert 0.0176 moles into formula units, using Avogadro's number, which relates the number of formula units present in 1 mol:
- 0.0176 mol * 6.023x10²³ FormulaUnits/mol = 1.06x10²² formula units
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If you mix different amounts of two ideal gases that are originally at different temperatures, what must be true of the final state after the temperature stabilizes? (There may be more than one correct choice.) a) Both gases will reach the same final temperature. b) The final rms molecular speed will be the same for both gases. c) The final average kinetic energy of a molecule will be the same for both gases.
Answers
Answer:
0.01454 grams of oxygen is present per kilogram of human muscle.
0.1454 grams of oxygen is present per kilogram of sperm whale muscle.
Explanation:
Given : The myoglobin is fully saturated with oxygen gas.
Moles of myoglobin = Moles of oxygen gas
Molecular mass of myoglobin = 17,600 g/mol
(assumed same fro whale and human )
Myoglobin content in humans = 8 g/kg
Mole of molyoglobin in human muscles per kg :
Mass of oxygen present in per kg of human muscle:
Moles of oxygen gas × 32g/mol :
g/kg of human muscle
Myoglobin content in whales= 80 g/kg
Mole of molyoglobin in whale muscles per kg :
Moles of myoglobin = Moles of oxygen gas
Mass of oxygen present in per kg of sperm whale muscle:
Moles of oxygen gas × 32g/mol :
g/kg of whale muscle
Answers
Answer:
The correct answer is 16.61 grams methanol and 57.38 grams water.
Explanation:
The mole fraction (X) of methanol can be determined by using the formula,
X₁ = mole number of methanol (n₁) / Total mole number (n₁ + n₂)
X₁ = n₁/n₁ + n₂ = 0.14
n₁ / n₁ + n₂ = 0.14 ---------(i)
n₁ mole CH₃OH = n₁ mol × 32.042 gram/mol (The molecular mass of CH₃OH is 32.042 grams per mole)
n₁ mole CH₃OH = 32.042 n₁ g
n₂ mole H2O = n₂ mole × 18.015 g/mol
n₂ mole H2O = 18.015 n₂ g
Thus, total mole number is,
32.042 n₁ + 18.015 n₂ = 74 ------------(ii)
From equation (i)
n₁/n₁ + n₂ = 0.14
n₁ = 0.14 n₁ + 0.14 n₂
n₁ - 0.14 n₁ = 0.14 n₂
n₁ = 0.14 n₂ / 1-0.14
n₁ = 0.14 n₂/0.86 ----------(iii)
From eq (ii) and (iii) we get,
32.042 × 0.14/0.86 n₂ + 18.015 n₂ = 74
n₂ (32.042 × 0.14/0.86 + 18.015) = 74
n₂ = 74 / (32.042 × 0.14/0.86 + 18.0.15)
n₂ = 3.1854 mol
From equation (iii),
n₁ = 0.14/0.86 n₂
n₁ = 0.14/0.86 × 3.1854
n₁ = 0.5185 mol
Now, presence of water in the mixture is,
= 3.1854 mole × 18.015 gram per mole
= 57.38 grams
Methanol present in the mixture is,
= 0.5185 mol × 32.042 gram per mole
= 16.61 grams
Final answer:
In a 74.0 g aqueous solution of methanol with a mole fraction of 0.140, the mass of methanol is approximately 10.36 g and the mass of water is approximately 63.64 g.
Explanation:
The problem involves the calculation of the mass of the components of an aqueous solution of methanol (CH3OH). First, we need to know that the mole fraction is defined as the ratio of the number of moles of a component to the total number of moles of all components in the mixture.
Given that the mole fraction of methanol is 0.140, this means that the rest of the solution (i.e., water) is 1 - 0.140 = 0.860. To find the mass of each component, we need to consider the total mass of 74.0 g.
The mass of methanol can be calculated as 74.0 g * 0.140 = 10.36 g. And the mass of water would be 74.0 g * 0.860 = 63.64 g.
So, in this aqueous solution, you have approximately 10.36 g of methanol and 63.64 g of water.
Learn more about Mole Fraction here:
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Answers
Answer:
C Liver
Explanation:
Answers
Answer:
1. micro
2. centi
3. milli
4. kilo
Explanation:
Prefixes, in mathematical exponents, are defined as the alphabetical names associated with the mathematical factors. Some examples are as follows:
10⁶ = Mega
10⁹ = Giga
10⁻⁹ = Nano
10⁻¹² = Pico
So, in order to name the metric system prefixes associated with each of the given mathematical factor, we first convert the factor into exponent form and then write its prefix, as follows:
10⁻⁶ = micro
1/100 = 0.01 = 1 x 10⁻² = centi
0.001 = 1 x 10⁻³ = milli
1000 = 1 x 10³ = kilo
1s2 2s2 2p6 3s2 3p2
1s2 2s2 2p6 3s2 3p6 4s2 3d4
1s2 2s2 2p6
1s2 2s2 2p6 3s2 3p6 4s2 3d6
1s2 2s2 2p6 3s2
Answers
Answer:
The number of electrons for the Mg atom are 12 electrons. The electron configuration of magnesium is,
Mg (Z= 12) = 1s2 2s2 2p6 3s2
Explanation:
The first two electrons is placed in the 1s orbital. The 1s orbital can accommodate two electrons.
The next 2 electrons for magnesium go in the 2s orbital.
The next six electrons will go in the 2p orbital. The p orbital can hold up to six electrons.
We’ll put six in the 2p orbital and then put the remaining two electrons in the 3s.
Therefore, the Magnesium electron configuration will be 1s22s22p63s2.
PLS MARK ME AS BRAINLIEST
very acidic
b.
slightly acidic
c.
very basic
d.
slightly basic
e.
neutral
Answers
Answer:
a. very acidic
Explanation:
A solution with a pH of 1.6 would be described as a very acidic solution.
The pH scale is a convenient scale for expressing the level of acidity or alkalinity of aqueous solutions.
The scale ranges from 1 to 14 in which case 1 is the lower limit and 14 the upper limit.
- An acidic solution has a pH value less than 7. As pH decreases, the acidity of the solution increases.
- Neutral solutions have a pH of 7
- An alkaline solution has a pH greater than 7 and the level of alkalinity increases as pH increases.