Solve the following problem:
Solve the following problem: - 2

Answers

Answer 1
Answer:

Answer:

Option 3.

Explanation:

Isomerism is a phenomenon where by two or more compounds have the same molecular formula but different structural patterns.

Geometric Isomerism is a type of Isomerism that occurs within a double bond i.e Geometric isomers have different arrangement within the double bond.

Considering the options given above,

The 1st option is exactly the same as the compound only, it is inverted.

The 2nd option is still the same as the compound, only it is laterally inverted.

The 3rd option satisfy geometric Isomerism as the arrangement differ from the compound in the double bond.

The 4th option is entirely a saturated compound in which geometric Isomerism is not possible.


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The air temperature surrounding a snowy driveway is 0ºC. One side of the driveway is shaded, while the other side is sunny. The snow on the sunny side melts. Which statement is true? The snow absorbed chemical energy to produce a chemical change. The snow absorbed heat energy to produce a chemical change. The snow released heat energy to produce a physical change. The snow absorbed radiant energy to produce a physical change.
Use the internet or your textbook as a reference to compare and contrast the Arrhenius Theory of acids and bases vs. the Brønsted-Lowery Theory. Use the internet or your textbook as a reference to name the following and indicate if they are an acid or a base: a. HCI b. KOH c. HNO d. Mg(OH),
How many grams of solid sodium cyanide should be added to 1.00 L of a 0.119 M hydrocyanic acid solution to prepare a buffer with a pH of 8.809
2. Which test for iron(II) ions is conclusive ​

How are radiation levels kept in balance? Outgoing

Earth emits


Back toward the sun in the form of

Answers

Answer:

Explanation:We known that Earths energy machine is driven by sunlight which acts as fuel for this machine and to strike a balance between outgoing long wave radiation and short wave radiation there are many factors which are involved in this process.Sun emits this energy in the form of short wave radiation because of the huge energy it has and short wave radiation are higher in energy.Hence, they reach the earth surface mostly as visible and UV rays.After reaching the earths surface what happens with these rays is that they get absorbed by the clouds and other constituents of Earth.

Now, this energy needs to be emitted back in to space in order to balance out the energy budget of earth and that is why this energy is emitted back as long wave radiation which have less energy and also earth has less energy unlike the sun.Loss of this energy is essential as Earth looses most of its energy through this and results in cooling.But when this OLR decreases it should be a cause of concern for us.

This imbalance is caused by a wide range of different human induced activities which has a cumulative effect on the temperature of earth.These activities gives rise to a huge gain in the CO2 concentration which is why this word has gain so much popularity and a cause of widespread concern for us.At community level we contribute to this heating by increasing usage of personal automobiles rather than going for public transport , advancement in technology has greatly changed our lifestyles making it more simpler and easier but this demands more energy consumption.Landscape changes are one of the most important because its taking place at a faster rate.Most of the land being cleared off to built new houses which means clearing off the existing vegetation which leads to temperature rise.Setting up of Industry depending on its type can reduce the amount of OLR escaping the surface by introducing more amount of GHGs in to the atmosphere.

Its these small communities which add up to become the entire human population causing a massive damage and hence at community level if people realize and take necessary steps things will start to change.

Arrange the following aqueous solutions in order of decreasing freezing points: 0.10 m KNO3, 0.10 m BaCl2, 0.10 m ethylene glycol ​[C2H4(OH)2, antifreeze], and 0.10 m Na3PO4.

Answers

Answer:

The freezing point of a solution is lowered compared to the freezing point of the pure solvent. The amount of depression of the freezing point is proportional to the molality of the solute. The greater the molality of a solution, the lower its freezing point. To compare the freezing points of these solutions, we need to determine which one has the highest molality.

First, we need to determine the number of particles that each solute will produce in solution, as this affects the amount of depression of the freezing point.

KNO3 dissociates into two ions: K+ and NO3-, so it will produce two particles per formula unit.

BaCl2 dissociates into three ions: Ba2+ and two Cl-, so it will produce three particles per formula unit.

Ethylene glycol does not dissociate in solution, so it will produce one particle per molecule.

Na3PO4 dissociates into four ions: three Na+ and one PO43-, so it will produce four particles per formula unit.

Now, we can calculate the molality (moles of solute per kilogram of solvent) for each solution:

For 0.10 m KNO3: molality = 0.10 mol / 1 kg = 0.10 m

For 0.10 m BaCl2: molality = 0.10 mol x 3 particles / 1 kg = 0.30 m

For 0.10 m ethylene glycol: molality = 0.10 mol / 1 kg = 0.10 m

For 0.10 m Na3PO4: molality = 0.10 mol x 4 particles / 1 kg = 0.40 m

So, the solutions in order of decreasing freezing points are:

0.10 m Na3PO4 (highest molality)

0.10 m BaCl2

0.10 m KNO3 and 0.10 m ethylene glycol (same molality, but KNO3 has a smaller van't Hoff factor than ethylene glycol, so it will have a slightly higher freezing point)

Explanation:

15.0 L of an ideal gas at 298 K and 3.36 atm are heated to 383 K with a new pressure of 5.60 atm. What is the new volume in liters

Answers

Answer:

V_2=11.6L

Explanation:

Hello!

In this case, since we volume, pressure and temperature which are all changing, we can use the combined ideal gas law to write:

(P_1V_1)/(T_1) =(P_2V_2)/(T_2)

Thus, since the final volume V2 is required, by solving for it, we write:

V_2=(P_1V_1T_2)/(T_1P_2)

In such a way, we plug in the given data to obtain:

V_2=(3.36atm*15.0L*383K)/(298K*5.60atm)\n\nV_2=11.6L

Which means that the process compressed the gas.

Best regards.

Final answer:

To find the new volume, we can use the combined gas law equation.

Explanation:

To solve this problem, you can use the combined gas law equation, which relates the initial and final conditions of pressure, volume, and temperature.

The combined gas law equation is: P1 * V1 / T1 = P2 * V2 / T2

Substituting the given values into the equation, we can solve for the new volume:

(3.36 atm * 15.0 L) / 298 K = (5.60 atm * V2) / 383 K

Simplifying and solving for V2, the new volume, we find V2 = 11.78 L.

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The Earth can gain or lose matter. True False​

Answers

Answer:

True

Explanation:

According to some calculations, the Earth is losing 50,000 metric tons of mass every single year, even though an extra 40,000 metric tons of space dust converge onto the Earth's gravity well, it's still losing weight.

Answer:

true

Explanation:

Which choice(s) include(s) d-orbital contribution in the hybridization scheme: pcl3, no3─, i3─, h2se ?

Answers

Among all three PCl₃, NO₃⁻ , I₃⁻, H₂Se only I₃⁻ will involve participation of d-orbitals in hybridization as bonding in I₃⁻ will include, s, p and d orbital as shown in the image attached. there will be sp³d hybridization, there will be presence of three lone pairs and 2 bonds as

I⁻ has 8 valence electrons and 2 neighbours atoms which will need one electron each to satisfy their valency.

so the number of electrons on central atom will be:

8-1-1=6

That 6 electrons will make 6/2 =3 lone pairs.

Consider the following reaction at equilibrium. What effect will adding 1.4 mole of He to the reaction mixture have on the system? 2 H2S(g) + 3 O2(g) ⇌ 2 H2O(g) + 2 SO2(g) Consider the following reaction at equilibrium. What effect will adding 1.4 mole of He to the reaction mixture have on the system? 2 H2S(g) + 3 O2(g) ⇌ 2 H2O(g) + 2 SO2(g) The reaction will shift to the left in the direction of reactants. No effect will be observed. The reaction will shift to the right in the direction of products. The equilibrium constant will increase. The equilibrium constant will decrease.

Answers

Answer:

The reaction will shift to the left in the direction of reactants.

Explanation:

According to Le Chatelier's principle, when an external constraint is applied to a chemical system in equilibrium, the system adjust in order to annul the effect impose on it by the external system.

Also, from the principle, the addition of an inert gas can affect the equilbrium of a gaseous system, but only if the volume is allowed to change.

There are two cases on which equilibrium depends. These are:

1. Addition of an inert gas at constant volume:

When an inert gas is added to the system in equilibrium at constant volume, the total pressure will increase. But the concentrations of the products and reactants (i.e. ratio of their moles to the volume of the container) will not change.  Hence, there will be no effect on the equilibrium.  

2. Addition of an inert gas at constant pressure:

When an inert gas is added to a system in equilibrium at constant pressure, then the total volume will increase(i.e. the number of moles per unit volume of various reactants and products will decrease). Hence, the equilibrium will shift towards the direction in which there is increase in number of moles of gases.  

Considering the given reaction in equilibrium:

2H₂S(g) + 3O₂(g) ⇌ 2H₂O(g) + 2SO₂(g)

The addition of an inert gas at constant pressure to the above reaction will shift the equilibrium towards the backward direction because the number of moles of reactants is more than the number of moles of the products.

Final answer:

Adding 1.4 moles of He to the reaction mixture will have no effect on the equilibrium of the system.

Explanation:

Adding 1.4 moles of He to the reaction mixture will have no effect on the system. The equilibrium of the reaction will not shift to the left or right, and there will be no change in the equilibrium constant. This is because He is considered an inert gas and does not participate in the reaction.

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