Use the internet or your textbook as a reference to compare and contrast the Arrhenius Theory of acids and bases vs. the Brønsted-Lowery Theory. Use the internet or your textbook as a reference to name the following and indicate if they are an acid or a base:
a. HCI
b. KOH
c. HNO
d. Mg(OH),

Answers

Answer 1
Answer:

Answer and Explanation:

1. Arrhenius Theory which describes the concept protonic. The substance that gives H+ ions when diluted in water is called as an acid (e.g. HCl) and the substance that dissociates OH-ions whenever it is diluted in water is called as the base (e.g. NaOH)

on the other hand

Bronsted Lowery Theory describes the concept of a proton donor-acceptor. The proton-donating species is an acid and the proton-accepting species is known as a base.

2. The Chemical name and nature of acid is shown below:-

Nature Chemical Name

a. HCl Acidic Hydrochloric Acid

b. KOH Basic Potassium hydroxide

c. HNO Acidic Nitric Acid

d. Mg(OH)2 Basic Magnesium hydroxide


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When palmitoleic acid reacts with hydrogen to form a saturated fatty acid, indicate the stoichiometry of the reaction and the product that is formed. If the stoichiometry of H2 or the product is not integral, enter a fraction (i.e. 3/2)

Answers

Answer:

Stoichiometric coefficient of hydrogen gas is 1.

Stoichiometric coefficient of palmitic acid is 1.

Explanation:

Addition of hydrogen to double bond is termed as hydrogenation reaction.

C_(16)H_(30)O_2+H_2\rightarrow C_(16)H_(32)O_2

According to stoichiometry, 1 mole of palmitoleic acid reacts with 1 mole of hydrogen gas to give 1 mole of palmitic acid.

Stoichiometric coefficient of hydrogen gas is 1.

Stoichiometric coefficient of palmitic acid is 1.

Barium chloride + sodium phosphate 
Answer with double replacement

Answers

Answer:

Barium chloride + Sodium phosphate    →   barium phosphate + sodium chloride

Explanation:

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AC +BD

Chemical equation:

BaCl₂ + Na₃PO₄         →     Ba₃(PO₄)₂ + NaCl

Balanced chemical equation:

3BaCl₂ + 2Na₃PO₄         →     Ba₃(PO₄)₂ + 6NaCl

The cation and anion of both reactants are exchanged with each other.

Ba²⁺ react with PO₄³⁻ and form Ba₃(PO₄)₂ while Cl⁻ react with Na⁺ and form sodium chloride.  

Molecular equation:

Barium chloride + Sodium phosphate    →   barium phosphate + sodium chloride

Final answer:

A double replacement reaction between barium chloride and sodium phosphate results in the formation of barium phosphate and sodium chloride.

Explanation:

The given chemical equation represents a double replacement reaction. The chemical reactants are barium chloride (BaCl2) and sodium phosphate (Na3PO4). In a double replacement reaction, the cations and anions of the two reactants switch places to form two new compounds.

So here is how the reaction would proceed: BaCl2 + Na3PO4 -> Ba3(PO4)2 + NaCl.

This translates to: Barium chloride reacts with sodium phosphate to form barium phosphate and sodium chloride.

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Joan has four containers. The chart below shows the mass and volume of each of the containers. Two of the containers are filled with solids, one is filled with a liquid, and one is filled with a gas.

Answers

Answer:

This question is incomplete

Explanation:

This question is incomplete. However, it should be noted that if the containers are compared with an equal average volume, the containers having solids will have larger masses than that containing liquid which will also have a larger mass than that containing gas. This is because solids have there molecules touching each other in compact manner which makes the molecule exert a certain combined force/mass. The molecules of liquid are also close to one another but are not compact like the solids and are hence exerting a lesser force/mass than solids. Gases have free molecules that are far apart and thus are usually the lightest when they occupy the same volume as liquids and solids.

Iridium-192 is used in medicine to treat prostate cancer. Iridium-192 has two modes of radioactive decay: 96% of the time it decays by beta emission and 4% of the time it decays by electron capture. What are the daughter nuclides of these two decay processes?

Answers

Answer:

The daughter nuclides of these two decay processes are ^(192)_(78)Pt and ^(192)_(76)Os.

Explanation:

The beta emission is represented by:

A = (Z + 1) + (n - 1) = is invariant

n: neutron

p: proton

^(A)_(Z)X \rightarrow ^(A)_(Z+1)Y

Hence, the daughter nuclide of the beta emission of Ir-192 is:

^(192)_(77)Ir \rightarrow ^(192)_(78)Pt      

Now, electron capture is represented by:

A = (Z - 1) + (n + 1) = is invariant

^(A)_(Z)X \rightarrow ^(A)_(Z-1)Y

Then, the daughter nuclide of the electron capture of Ir-192 is:

^(192)_(77)Ir \rightarrow ^(192)_(76)Os    

Therefore, the daughter nuclides of these two decay processes are ^(192)_(78)Pt and ^(192)_(76)Os.

I hope it helps you!

The activiation energy required for a chemical reaction can be decreased by? A) increasing the surface area of the reactant.
B) increasing the temperature of the reactant.
C) adding a catalyst to the reaction.
D)adding more reactant​

Answers

Answer:

C)

Explanation:

C) adding a catalyst to the reaction.

Calculate the pH of the cathode compartment solution if the cell emf at 298 K is measured to be 0.660 V when (Zn^2+)=0.22 M and(P_H2)= 0.87atm.

Answers

Answer:

pH = 2.059

Explanation:

At the Cathode:

The reduction reaction is:

2H^+ + 2e^- \to H_2   \ \ \ \mathbf{E^0_(red)= 0.00 \ V}

At the anode:

At oxidation reaction is:

Zn \to Zn^(2+) +2e^-   \ \ \ \mathbf{E^0_(ox) = 0.76 \ V}

The overall equation for the reaction is:

\mathbf{Zn + 2H^+ \to Zn^(2+) + H_2}

The overall cell potential is:

\mathbf{E^0_(cell)= E^0_(ox) + E^0_(red)}

\mathbf{E^0_(cell)= 0.76 \ V +0.00 \ V}

\mathbf{E^0_(cell)= 0.76\ V}

Using the formula for the Nernst equation:

E = E^0 - ( (0.0591)/(n))log (Q)\n

where;

E = 0.66

(Zn^2+)=0.22 M

Then

0.66 =0.76- ( (0.0591)/(2))log \bigg ( ([Zn^(2+) ] PH_2)/([H^+]^2) \bigg )

0.66 =0.76- 0.02955 * log \bigg ( (0.22*0.87)/([H^+]^2) \bigg )

3.4 = log ( 0.1914) - 2 log [H⁺]

3.4 = -0.7180 - 2 log [H⁺]

3.4 + 0.7180 = - 2 log  [H⁺]

4.118  = - 2  log  [H⁺]

pH = log [H⁺] = 4.118/2

pH = 2.059

The pH of the solution as described in the question is 2.7.

The equation of the reaction is;

Zn(s) + 2H^+(aq) ----> Zn^2+(aq) + H2(g)

The partial pressure of hydrogen can be converted to molarity using;

P= MRT

M = P/RT

M =  0.87atm/0.082 LatmK-1mol-1 × 298 K = 0.036 mol/L

We have to obtain the reaction quotient

Q = [Zn^2+] [H2]/[H^+]^2

Q = [0.22 ] [0.036]/[H^+]^2

Recall that, from Nernst equation;

E = E° - 0.0592/nlog Q

E° = 0.00V - (-0.76V) = 0.76V

0.660 =  0.76 - 0.0592/2logQ

0.660 - 0.76  =  - 0.0592/2logQ

-0.1 =  - 0.0592/2logQ

-0.1 × 2/ - 0.0592 = logQ

3.38 = log Q

Q = Antilog (3.38)

Q= 2.39 × 10^3

Now;

2.39 × 10^3 =  [0.22 ] [0.036]/[H^+]^2

2.39 × 10^3 = 7.92  × 10^-3/[H^+]^2

[H^+]^2 = 7.92  × 10^-3/2.39 × 10^3

[H^+] = 1.82  × 10^-3

pH = -log[H^+]

pH = -log[ 1.82  × 10^-3]

pH = 2.7

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