Describe how you would make 250 ml of a 3 M solution of sodium acetate (NaOAc = 82.03 g/mol). First figure out how much sodium acetate you would need, then describe how you would make the solution if you were given a bottle of solid sodium acetate, a volumetric flask, and DI water.

Answers

Answer 1

Answer:

Answer:

You need to do the following conversion to pass from 3M in 250 mL to g of sodium acetate

$3 M (mol/L)*(1L/1000 mL)*(250 mL)*(82.03 g/1 mol)=61.52 g$

Explanation:

First, you need to dissolve 61.52 g of solid sodium acetate (MW 82.03 g/mol) in 200 ml of DI water. Then, using a volumetric flask add water to bring the total volume of the solution to 250 mL.

Related Questions

Determine the end (final) value of n in a hydrogen atom transition, if the electron starts in and the atom emits a photon of light with a wavelength of 486 nm. Group of answer choices
Arrange the following substances in order of increasing solubility of water. C6H14, C6H13Br, C6H13OH, C6H12(OH)2.
Is it possible for three or more elements to form a solid solution? Explain your answer.
The vapor pressure of carbon disulfide is 355.6 torr at 25°C. What is the vapor pressure of a solution prepared by dissolving 10.60 g naphthalene (C10H8, Molar Mass = 128.2 g/mol) in 155 mL CS2 liquid (Molar Mass = 76.14 g/mol, density = 1.261 g/mL)? Assume the solution obeys Raoult's law, and treat naphthalene as a nonvolatile solute.
Consider the following chemical equilibrium: C(s) + 2H2 (g) <------> CH4 (g) Now write an equation below that shows how to calculate Kp from Kc for this reaction at an absolute temperature T. You can assume T is comfortably above room temperature. If you include any common physical constants in your equation be sure you use their standard symbols, found in the ALEKS Calculator.

Predict the sign of the entropy change,Delta S, for each of the following reactions:The signs are either going to be pos or negativea) Pb^2+(aq) + 2Cl-(aq) ---> PbCl2(s)b) CaCO3(s) ---> CaO(s) + CO2 (g)c) 2NH3(g) ---> N2(g) + 3H2(g)d) P4(g) + 5O2(g) ---> P4O10(s)e) C4H8(g) + 6O2(g) ---> 4CO2(g) + 4H2O(g)f) I2(s) ---> I2(g)

Answers

Answer: a) $Pb^(2+)(aq)+2Cl^-(aq)\rightarrow PbCl_2(s)$ : negative

b) $CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$ : positive

c) $2NH_3(g)\rightarrow N_2(g)+3H_2(g)$ : positive.

d) $P_4(g)+5O_2(g)\rightarrow P_4O_(10)(s)$ : negative

e) $C_4H_8(g)+6O_2(g)\rightarrow 4CO_2(g)+4H_2O(g)$ : positive.

f) $I_2(s)\rightarrow I_2(g)$ : positive.

Explanation:

Entropy is the measure of randomness or disorder of a system. If a system moves from an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.

$\Delta S$ is positive when randomness increases and $\Delta S$ is negative when randomness decreases.

a) $Pb^(2+)(aq)+2Cl^-(aq)\rightarrow PbCl_2(s)$

As ions are moving to solid form , randomness decreases and thus sign of $\Delta S$ is negative.

b) $CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

As solid is changing to gas, randomness increases and thus sign of $\Delta S$ is positive.

c) $2NH_3(g)\rightarrow N_2(g)+3H_2(g)$

As 2 moles of reactants are converted to 4 moles of products , randomness increases and thus sign of $\Delta S$ is positive.

d) $P_4(g)+5O_2(g)\rightarrow P_4O_(10)(s)$

As gas is changing to solid, randomness decreases and thus sign of $\Delta S$ is negative.

e) $C_4H_8(g)+6O_2(g)\rightarrow 4CO_2(g)+4H_2O(g)$

As 7 moles of reactants are converted to 8 moles of products , randomness increases and thus sign of $\Delta S$ is positive.

f) $I_2(s)\rightarrow I_2(g)$

As solid is changing to gas, randomness increases and thus sign of $\Delta S$ is positive.

4.What volume of 0.120 M HNO3(aq) is needed to
completely neutralize 150.0 milliliters of 0.100 M
NaOH(aq)?
A. 62.5 mL
B. 125 ml
C.
180. mL
D. 360. mL

Answers

Answer:

B) 125 mL

Explanation:

M1V1=M2V2

(0.120M)(x)=(150.0 mL)(0.100M)

x= 125 mL

*Text me at 561-400-5105 for private tutoring if interested: I can do homework, labs, and other assignments :)

What factors govern the position of an IR absorption peak? Select one or more correct answers.(A) strength of the bond
(B) effect of a magnetic field on nucleus spin
(C) masses of the atoms involved in the bond
(D) the type of vibration being observed

Answers

Answer:

The factors that govern the position of an IR absorption peak are:

(A) strength of the bond

(C) masses of the atoms involved in the bond

(D) the type of vibration being observed

Explanation:

In infrared spectroscopy the molecules absorb the frequencies that are characteristic of their structure. These absorptions occur at resonance frequencies, that is, the frequency of the absorbed radiation coincides with the frequency of vibration. The energies are affected by the shape of molecular potential energy surfaces, the masses of atoms and the associated vibronic coupling. The resonance frequencies are also related to the strength of the bond and the mass of the atoms at each end of it. Therefore, the frequency of vibrations is associated with a particular normal movement mode and a particular type of link.

How is the kinetic energy of the particles of a substance affected during a phase change? A.) Kinetic energy increases during exothermic changes and decreases during endothermic changes.
B.) Kinetic energy decreases during exothermic changes and increases during endothermic changes.
C.) Kinetic energy does not change, but the potential energy does.
D.) Kinetic energy changes in the opposite way that the potential energy changes.

Answers

Answer:

Explanation:

Answer: A. Kinetic energy increases during exothermic changes and decreases during endothermic changes

Explanation: During an exothermic change potential energy is converted to kinetic energy. I hope this is correct. :)

To measure the solubility product of lead (II) iodide (PbI2) at 25°C, you constructed a galvanic cell that is similar to what you used in the lab. The cell contains a 0.5 M solution of a lead (II) nitrate in one compartment that connects by a salt bridge to a 1.0 M solution of potassium iodide saturated with PbI2 in the other compartment. Then you inserted two lead electrodes into each half-cell compartment and closed the circuit with wires. What is the expected voltage generated by this concentration cell? Ksp for PbI2 is 1.4 x 10-8. Show all calculations for a credit.

Answers

Answer:

0.2320V

Explanation:

Voltage can be defined as the amount of potential energy available (work to be done) per unit charge, to move charges through a conductor.

Voltage can be generated by means other than rubbing certain types of materials against each other.

Please look at attached file for solution to the problem.

Final answer:

The expected voltage generated by this concentration cell is approximately 0.113 V.

Explanation:

To calculate the voltage generated by the concentration cell, we can use the Nernst equation. The Nernst equation relates the concentration of the ions in the two compartments to the voltage of the cell. The equation is:

E = E° - (RT/nF) ln(Q)

Where:

E is the voltage of the cell
E° is the standard cell potential
R is the gas constant (8.314 J/mol·K)
T is the temperature in Kelvin (25 + 273 = 298 K)
n is the number of moles of electrons transferred (2 in this case)
F is Faraday's constant (96,485 C/mol)
ln(Q) is the natural logarithm of the reaction quotient

The reaction quotient (Q) can be calculated using the concentrations of the lead (II) and iodide ions in each compartment.

Since this is a concentration cell, the standard cell potential (E°) for this system is 0 V. Therefore, the equation simplifies to:

E = - (RT/nF) ln(Q)

Now we can calculate the voltage:

Calculate Q:

The solubility product constant (Ksp) for PbI2 is 1.4 x 10-8. Because PbI2 is in a saturated solution, the concentration of Pb2+ ions and I- ions are both equal to the solubility of PbI2. We can substitute these values into the equation to calculate Q:

Q = [Pb²+] x [I-]

Q = (1.4 x 10-8) x (1.4 x 10-8) = 1.96 x 10-16

Calculate E:

Now we can calculate the voltage using the given values:

For the Nernst equation, we need to convert the temperature to Kelvin:

T = 25°C + 273 = 298 K

Substitute the values into the equation:

E = - (8.314 J/mol·K x 298 K / 2 x 96,485 C/mol) ln(1.96 x 10-16)

E ≈ 0.113 V

Therefore, the expected voltage generated by this concentration cell is approximately 0.113 V.

Learn more about Voltage generated by a concentration cell here:

brainly.com/question/30226316

#SPJ11

In both industry and research there are often times when one particular component of a mixture needs to be separated from a solution. Maybe it is a rare metal that is dissolved in a mixture of minerals. Maybe it is a particular protein from lysed plant cells. If the desired component is volatile, distillation could be used. But if the goal is to separate ions in solution, fractional precipitation is preferred.a. True
b. False

Answers

Answer:

a. True

Explanation:

Distillation process is a process that is used to separate the components or the substances from the liquid mixtures by using selectively boiling and condensation.

While fractional precipitation is a process which separates the ions from solution based on the different solubilities.

Therefore, the answer is true.

Other Questions

MassWhat is the percent composition by mass ofnitrogen in the compound N,H, (gram-formula32 g/mol)?(1) 13%(3) 88%(2) 44%(4) 93%

For the Bradford assay, the instructor will make a Bradford reagent dye by mixing 50 ml of 95% v/v ethanol with 100 mg of Coomassie Blue followed by the addition of 50 ml of 85% v/v phosphoric acid. This entire mixture is then diluted to 1 liter with water. What is the final concentration of phosphoric acid?

3.7500*10^4+9.7100*5

Which response gives the products of hydrolysisofNH4Cl?A. NH4+ + HClB. NH3 + OH- + HClC. NH3 + H+D. NH4OH + HClE. No hydrolysis occurs.