Which response gives the products of hydrolysisofNH4Cl?
A. NH4+ + HCl
B. NH3 + OH- + HCl
C. NH3 + H+
D. NH4OH + HCl
E. No hydrolysis occurs.

Answers

Answer 1
Answer:

Answer : The correct option is, (C) NH₃ + H⁺

Explanation:

Hydrolysis : It is defined as the chemical reaction in which the breakdown of compound takes place due to reaction with water.

As per question:

First ammonium chloride completely dissociates into ion.

NH_4Cl(aq)\rightarrow NH_4^+(aq)+Cl^-(aq)

Now ammonium ion react with water to give ammonia and hydronium or hydrogen ion.

The balanced hydrolysis reaction will be:

NH_4^++H_2O\rightarrow NH_3+H_3O^+

Hence, the correct option is, (C) NH₃ + H⁺

Answer 2
Answer:

Answer:

NH₃ and H⁺

Explanation:

The dissociation of NH₄Cl will lead to two ions , i.e. , NH⁴⁺  and Cl⁻ .

Hence , the reaction is -

NH₄Cl  →  NH⁴⁺   +   Cl⁻

We can conclude that  NH₄Cl can be formed from the ions , NH⁴⁺  and Cl⁻

Hence ,

According to the reaction ,

NH⁴⁺ + H₂O  ⇆  NH₃ + H₃O⁺

Therefore ,

The reactant that will lead to the formation of NH₄Cl are -  NH₃ and H⁺


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Plants make their own food through a process called ____________.(6th grade science)

Answers

Answer:

Photosynthesis

Explanation:

Question:

Plants make their own food through a process called ____________.(6th grade science)

Answer:

The correct answer to the blank is photosynthesis. Photosynthesis is the process that enables plants to get energy from the sun. Light energy from the sun is converted into chemical energy by chlorophyll. Chlorophyll gives plants their green color.

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What is the change in electrons for nitrogen in the following reaction?S + NO3 - -> SO2 + NO


A. Gain 2 electrons
B. Gain 3 electrons
C. Lose 2 electrons
D. Lose 3 electrons

Answers

Nitrogen changes from +5 in NO_3- to +2 in NO. This means nitrogen has gained 3 electrons. Option B

To determine the change in electrons for nitrogen in the given reaction, we need to compare the oxidation state of nitrogen in the reactant (NO_3-) and the product (NO).

In the reactant, -, nitrogen is in the +5 oxidation state. This is because oxygen has an oxidation state of -2, and there are three oxygen atoms in NO_3-. Therefore, nitrogen must have an oxidation state of +5 to balance the overall charge of NO_3-.

In the product, NO, nitrogen is in the +2 oxidation state. This is because oxygen has an oxidation state of -2, and there is only one oxygen atom in NO. Therefore, nitrogen must have an oxidation state of +2 to balance the overall charge of NO.

By comparing the oxidation states of nitrogen in the reactant and the product, we can determine the change in electrons. The change in oxidation state corresponds to the change in the number of electrons gained or lost by the nitrogen atom.

In this case, nitrogen changes from +5 in NO_3- to +2 in NO. This means nitrogen has gained 3 electrons.

Therefore, the correct answer is B) Gain 3 electrons.

The nitrogen atom undergoes a reduction because it gains electrons, reducing its oxidation state from +5 to +2 in the reaction.

Option B

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Which of the following Ph levels would indicate the weakest base?15

8

6

2​

Answers

Answer:

8

Explanation:

7 is neutral any anything above it is basic and anything below is acidic which means 8 would be the lowest base

Answer:

The pH of a weak base falls somewhere between 7 and 10.

Explanation:

Like weak acids, weak bases do not undergo complete dissociation; instead, their ionization is a two-way reaction with a definite equilibrium point

You are asked to prepare 500 mL 0.300 M500 mL 0.300 M acetate buffer at pH 4.904.90 using only pure acetic acid ( MW=60.05 g/mol,MW=60.05 g/mol, pKa=4.76), pKa=4.76), 3.00 M NaOH,3.00 M NaOH, and water. Answer the questions regarding the preparation of the buffer. 1. How many grams of acetic acid will be needed to prepare the 500 mL buffer? Note that the given concentration of acetate refers to the concentration of all acetate species in solution.

Answers

The quantity of acetic acid that is needed to prepare the 500 mL buffer is 9.0075 grams.

Given the following data:

  • Volume of acetate buffer = 500 mL to L = 0.5 L.
  • Molarity of acetate buffer = 0.300 M.
  • pH = 4.90.
  • MW = 60.05 g/mol.
  • pKa = 4.76.

How to calculate the mass of acetic acid.

First of all, we would write the equilibrium chemical reaction for acetate-acetic acid as follows:

                                CH_3COOH \rightleftharpoons CH_3COO^(-)+H^+

Next, we would calculate HA by applying Henderson-Hasselbalch equation:

pH =pka+ log_(10) (A^-)/(HA)

Where:

  • HA is acetic acid.
  • A^-  is acetate ion.

Substituting the given parameters into the formula, we have;

4.90 =4.76+ log_(10) (A^-)/(HA)\n\n4.90 -4.76+ log_(10) (A^-)/(HA)\n\n(A^-)/(HA)=1.38\n\nA^- = 1.38[HA]

For the concentration of both acids, we have:

[HA]+[A^-]=0.300M\n\n[HA]+1.38[HA]=0.300M\n\n2.38[HA]=0.300M\n\nHA = 0.126

For acetate ion:

A^- = 1.38[HA] = 1.38 * 0.126\n\nA^- =0.174

At a volume of 0.5 liters, we have:

HA = 0.5 * 0.126\n\nHA = 0.063 \;moles

A^- =  0.5 * 0.174\n\nA^- =0.087 \;moles

By stoichiometry:

Total moles = 0.063 + 0.087 = 0.15 moles.

Mass = number \;of \;moles * molar\;mass\n\nMass =0.15 * 60.05

Mass = 9.0075 grams.

Read more on moles here: brainly.com/question/3173452

Answer:

You will need 9,0 g of acetic acid

Explanation:

The equilibrium acetate-acetic acid is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺ pka = 4,76

Using Henderson-Hasselbalch you will obtain:

pH = pka + log₁₀([A^(-)])/([HA])

Where HA is acetic acid and A⁻ is acetate ion

4,90 = 4,76 + log₁₀([A^(-)])/([HA])

1,38 = ([A^(-)])/([HA])(1)

As acetate concentration is 0,300M:

0,300M = [HA] + [A⁻] (2)

Replacing (2) in (1):

[HA] = 0,126 M

And:

[A⁻] = 0,174 M

As you need to produce 500 mL:

0,5 L × 0,126 M = 0,063 moles of acetic acid

0,5 L × 0,174 M = 0,087 moles of acetate

To produce moles of acetate from acetic acid:

CH₃COOH + NaOH → CH₃COO⁻ + Na⁺ + H₂O

Thus, moles of acetate are equivalents to moles of NaOH and all acetates comes from acetic acid, thus:

0,087 moles of acetate + 0,063 moles of acetic acid  ≡ 0,15 moles of acetic acid ×(60,05 g)/(1mol) = 9,0 g of acetic acid

I hope it helps!

The steps in a reaction mechanism are as follows. Which species is acting as a catalyst? Step 1: Ag+(aq) + Ce4+(aq) <-----> Ag2+(aq) + Ce3+(aq) Step 2: Tl+(aq) + Ag2+(aq) -----> Tl2+(aq) + Ag+(aq) Step 3: Tl2+(aq) + Ce4+(aq) -----> Tl3+(aq) + Ce3+(aq)

Answers

The specie which is acting as a catalyst is; Ag+(aq).

Discussion:

The catalyst is a specie that exists in the same form at the beginning and end of the reaction.

The reaction's mechanism is as follows;

  • Step 1: Ag+(aq) + Ce⁴+(aq) <-----> Ag²+(aq) + Ce³+(aq)

  • Step 2: Tl+(aq) + Ag²+(aq) -----> Tl²+(aq) + Ag+(aq)

  • Step 3: Tl²+(aq) + Ce⁴+(aq) -----> Tl³+(aq) + Ce³+(aq)

Evidently, although Ag+(aq) was converted to Ag²+(aq) in Step 1 of the reaction; the Ag²+(aq) is reverted back to Ag+(aq) in Step 2 of the reaction.

Read more:

brainly.com/question/22498090

Answer:

Ag⁺ acts as the catalyst.

Explanation:

Hello,

In this case, each step is reorganized:

- Step 1:

Ag^+(aq) + Ce^(4+)(aq) \rightleftharpoons Ag^(2+)(aq) + Ce^(3+)(aq)

- Step 2:

Tl^+(aq) + Ag^(2+)(aq) \rightarrow  Tl^(2+)(aq) + Ag^+(aq)

- Step 3:

Tl^(2+)(aq) + Ce^(4+)(aq) \longrightarrow Tl^(3+)(aq) + Ce^(3+)(aq)

In such a way, Ag⁺ is converted to Ag²⁺ in the first step, but then it is regenerated to simple Ag⁺, therefore, Ag⁺ acts as the catalyst.

Best regards.

The following figure represents the formation of an ionic compound. Substances A and B are initially uncharged, but when mixed electrons are transferred. Using the figure, identify which substance will form the cation and which will form the anion. Provide a brief (one or two sentences) explanation for your response. (Hint: How does losing electrons affect atomic radii?)

Answers

Answer:

This question is incomplete

Explanation:

This question is incomplete but some general explanation provides a clear answer to what is been asked in the question.

An ionic/electrovalent compound is a compound whose constituent atoms are joined together by ionic bond. Ionic bond is a bond involving the transfer of valence electron(s) from an atom (to form a positively charged cation) to another  atom (to form a  negatively charged anion). The atom transferring is usually a metal while the atom receiving is usually a non-metal.

For example (as shown in the attachment), in the formation of NaCl salt, the sodium (Na) transfers the single electron (valence) on it's outermost shell to chlorine (Cl) which ordinarily has 7 electrons on it's outermost shell but becomes 8 after receiving the valence electron from sodium. It should also be noted that Na is a metal while Cl is a non-metal.