For the Bradford assay, the instructor will make a Bradford reagent dye by mixing 50 ml of 95% v/v ethanol with 100 mg of Coomassie Blue followed by the addition of 50 ml of 85% v/v phosphoric acid. This entire mixture is then diluted to 1 liter with water. What is the final concentration of phosphoric acid?

Answers

Answer 1
Answer:

Answer:

4,25% v/v H3PO4

Explanation:

The concentration of phosphoric acid (H3PO4) is expressed as a volume / volume percentage, which means:

%v/v H3PO4 = (mL of pure H3PO4/mL of solution)*100%

In other words, we are only interested in the final volume of the solution to which the phosphoric acid was diluted, regardless of its composition. Which in this case is 1 L (1000 mL).

We can then apply the following equation, commonly used to calculate the initial or final concentration (or volume) of a substance when it is diluted:

Ci*Vi=Cf*Vf

Where:

Ci, is the initial concentration of the substance.

Vi, the initial volume of the substance

Cf, the final concentration reached after dilution

Vf, the final volume of the solution at which the substance was diluted

In this case, the incognite would be the final concentration of H3PO4 reached after dilution, that is, Cf. Therefore, we proceed to clear Cf from the previous equation and replace our data:

Cf = (Ci*Vi)/Vf = (85% v/v * 50 mL)/1000 mL = 4,25 % v/v

Note that being up and down in the division, the mL unit is canceled to result in% v / v.


Related Questions

The [Fe(H₂O)₆]³⁺ complex requires a relatively small amount of energy to promote an electron from the t2g to the eg. Based on the UV data, predict the spin of this complex.
Is scandium a transition metal?​
Draw the Lewis structure for the polyatomic hydronium H3O cation. Be sure to include all resonance structures that
The dry solute has a mass of 0.086 g. 0.113 g of water evaporated while heating. What is the concentration in G solute / mL solvent at 30.1 C? Remember: 1 g = 1 ml for waterA. 0.88B. 0.0860C. 0.113D. 0.761
2 SO2 (g) + O2 (g) 2 SO3 (g)If the TEMPERATURE on the equilibrium system is suddenly increased :The value of Kc A. IncreasesB. DecreasesC. Remains the sameThe value of Qc A. Is greater than KcB. Is equal to KcC. Is less than KcThe reaction must: A. Run in the forward direction to restablish equilibrium.B. Run in the reverse direction to restablish equilibrium.C. Remain the same. Already at equilibrium.The concentration of O2 will: A. Increase.B. Decrease.C. Remain the same.

Which of the following describes a way in which chemistry affects how youuse a computer?
A. The colors in the computer display are the result of substances
that glow.
B. By clicking a mouse, you can select an object or text on a
computer screen.
C. Eye stress can be reduced by sitting a certain distance from the
Screen.
D. You are able to play video games by moving your body instead of a
joystick

Answers

A way in which chemistry affects how To use a computer is  The colors in the computer display are the result of substances that glow. Option A

In modern computers, the display technology commonly used is Liquid Crystal Display (LCD) or Light Emitting Diode (LED) technology. These displays rely on the principles of chemistry to produce the colors that we see on the screen.

In LCD screens, tiny liquid crystal cells are controlled by an electric current, which causes them to either block or allow the passage of light. Each cell represents a pixel on the screen, and by controlling the intensity of light passing through each pixel, different colors can be produced.

The liquid crystals used in LCD screens are organic compounds that exhibit unique optical properties, allowing them to manipulate light in a controlled manner.

LED screens, on the other hand, use arrays of light-emitting diodes to generate light. These diodes are made of semiconducting materials, often composed of compounds like gallium, arsenic, and phosphorus. When an electric current passes through these compounds, they emit light of a specific wavelength, resulting in the different colors displayed on the screen.

So, the colors we see on a computer display are a direct result of the chemical properties and behavior of the substances used in the LCD or LED technology. Chemistry plays a crucial role in the design and functionality of computer displays, enabling us to view vibrant and accurate colors while using our computers.

Option A

For more such question on chemistry visit:

brainly.com/question/29886197

#SPJ8

Most wine is prepared by the fermentation of the glucose in grape juice by yeast: C6H12O6(aq) --> 2C2H5OH(aq) + 2CO2(g) How many grams of glucose should there be in grape juice to produce 725 mLs of wine that is 11.0% ethyl alcohol, C2H5OH (d=0.789 g/cm3), by volume?

Answers

Answer:

123.41 g

Explanation:

Given that the ethyl alcohol produced is 11.0 % by volume.

It means that 1000 mL contains 110 mL of ethyl alcohol

Given that the volume is:- 725 mL

So,

Volume of ethyl alcohol = (110)/(1000)* 725\ mL = 79.75 mL

Given that:- Density = 0.789 g/cm³ = 0.789 g/mL

So, Mass = Density*Volume = 0.789* 79.75\ g = 62.92 g

Calculation of the moles of ethyl alcohol as:-

Molar mass of ethyl alcohol = 46.07 g/mol

The formula for the calculation of moles is shown below:

moles = (Mass\ taken)/(Molar\ mass)

Thus,

Moles= (62.92\ g)/(46.07\ g/mol)

Moles=1.37\ mol

According to the reaction:-

C_6H_(12)O_6_((aq))\rightarrow 2C_2H_5OH_((aq)) +2CO_2_((g))

2 moles of ethyl alcohol is produced when 1 mole of glucose reacts

Also,

1.37 moles of ethyl alcohol is produced when (1)/(2)* 1.37 mole of glucose reacts

Moles of glucose = 0.685 Moles

Molar mass of glucose = 180.156 g/mol

Mass = Moles*Molar mass = 0.685* 180.156\ g = 123.41 g

The decomposition of a substance x is a second order reaction. it takes 0.5 h for a solution that is initially 1.00 m to decrease to 0.50 m. how much time will it take for the concentration of a solution of x to decrease from 1.00 m to 0.25 m?

Answers

speed :
((1.00 - 0.50))/(0.5) = 1 (m)/(h)
the amount of time it take to decrease from 1.00 m to 0.25 m
((1.00 - 0.25))/(1) = 0.75
the answer is 0.75 h

Exactly 1.5 g of a fuel burns under conditions of constant pressure and then again under conditions of constant volume. In measurement A the reaction produces 25.9 kJ of heat , and in measurement B the reaction produces 23.3 kJ of heat. Which measurement (A or B) corresponds to conditions of constant pressure? Which one corresponds to conditions of constant volume? Explain.

Answers

Answer:

Process B : constant pressure condition

Process A : constant volume condition

Explanation:

In case of constant pressure, some of the energy is used to do work on the surrounding to keep pressure constant. Due to this, the total heat energy is less than in case of constant volume. In Case of constant Volume all of heat is available, produced in reaction because no work is done.

If we look at our data,we will find that process B has energy 23.3 KJ which is less than process A, the energy of which is 25.9 KJ. It means Process B is occurred at constant pressure condition and Process A has occurred at constant volume condition

HELP Which type of light is stored energy?A. Kinetic
B. Potential
C. Thermal
D. Field

Answers

Answer:

B

Explanation:

Answer:

Potential

Explanation:

Calculate the percent saturated fat in the total fat in butter

Answers

about 63% of the fat in butter is saturated fat