Is scandium a transition metal?​

Answers

Answer 1
Answer:

Answer:no

Explanation:

Answer 2
Answer:

Answer:

Scandium is a transition metal

Explanation:


Related Questions

Draw an arrow-pushing mechanism for the elimination reaction between NaOH in ethanol and each of the following haloalkanes: (E1/E2)(i) 1-bromobutane;(ii) 2-bromo-2-methylpentane.
Please help with this​
Transpiration is the loss of water from the leaves of plants. The stomata of leaves must open to allowcarbon dioxide to enter the leaf for photosynthesis, but when they are open, water vapor escapes intothe atmosphere.HYPOTHESIS: As the intensity of light is increased, the rate of transpiration will increase, asmeasured in by the loss of mass of the plant.Independent variable:Dependent variable:
Determine the rate of a reaction that follows the rate law:rate = k[A]”[B]", where:k= 1.5[A] = 1 M[B] = 3 Mm = 2n = 1
The boiling point of an aqueous 1.83 m (nh4)2so4 (molar mass = 132.15 g/mol) solution is 102.5°c. determine the value of the van't hoff factor for this solute if the kb for water is 0.512°c/m. 2.7 1.8 2.3 3.0 3.6

LAST ATTEMPT IM MARKING AS BRAINLIEST!! (What is this compound ? )

Answers

Answer:

its water h²O

Explanation:

Hopeitshelp

A food is initially at a moisture content of 90% dry basis. Calculate the moisture content in wet basis

Answers

Answer:

Moisture content in wet basis = 47.4 %    

Explanation:

Moisture content expresses the amount of water present in a moist sample.Dry basis and wet basis are widely used to express moisture content.  

The next equation express the moisture content in wet basis:  

                MC_(wb)=(MC_(db))/(1+MC_(db))

where,  MC_(wb): moisture content in wet basis and  

             MC_(db): moisture content in dry basis    

We now calculate the moisture content in wet basis:

MC_(wb)=(MC_(db))/(1+MC_(db))

MC_(wb)=(0.90)/(1+0.90)

MC_(wb)= 0.474 = 47.4 % wet basis    

Have a nice day!

100 points and brainiest Please Help!!

Answers

♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

1) Enzyme A

[This is because a pH below 7 is acidic and the optimum pH is 1 for this enzyme]

2) Enzyme C

[pH 7 is neutral]

3) Enzyme D

[A pH above 7 is 'basic']

4) Enzyme B

[It is still below 7 but it is closer to neutral so it is just 'acidic']

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

ʜᴀɴɴᴀʜ ♡

1st one is A

2nd one is C

3rd one is D

4th one is B

(Brainliest plz)

A spontaneous reaction occurs

Answers

Answer:

A spontaneous reaction is a reaction that occurs in a given set of conditions without intervention. A spontaneous reactions are accompanied by an increase in overall entropy, or disorder

Explanation:

What do lactate dehydrogenase, aspartate aminotransfcrase, and creatine kinase all have in common? a. they all are allosteric enzymes b. they are all zymogens c, they are all used to diagnose medical conditions d. they all function at abeornally high temperatures

Answers

Answer:

c. they are all used to diagnose medical conditions

Explanation:

Lactate dehydrogenase, aspartate aminotransfcrase, and creatine kinase all are used to diagnose medical conditions.

15) What is the hydronium ion concentration [H3O + ] of a 0.125 M hydrocyanic acid solution with Ka = 4.9 × 10-10? The equation for the dissociation of hydrocyanic acid is: HCN(aq) + H2O(l) ⇌ H3O+(aq) + CN- (aq)

Answers

The hydronium ion concentration [H₃O⁺]=7.826 x 10⁻⁶

Further explanation

In general, the weak acid ionization reaction  

HA (aq) ---> H⁺ (aq) + A⁻ (aq)  

Ka's value  

\large {\boxed {\bold {Ka \: = \: \frac {[H ^ +] [A ^ -]} {[HA]}}}}

Reaction

HCN(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CN⁻ (aq)

0.125

x                                   x               x

0.125-x                         x               x

\tt Ka=([H_3O^+][CN^-])/([HCN^-])

\tt 4.9* 10^(-10)=(x^2)/(0.125-x)\approx (x^2)/(0.125)\n\nx^2=6.125* 10^(-11)\n\nx=7.826* 10^(-6)