3. Theoretically how many grams of magnesium is required to produce to 5.0 g ofMagnesium oxide?

Answers

Answer 1
Answer:

Answer:

3grams

Explanation:

The reaction for the production of Magnesium dioxide will be

Mg + O2  → MgO

we have 5g of MgO (molar mass 40g)

no of moles of MgO = 5/40 = 0.125

Using unitary method we have

1 mole of Mg require 1 mole of MgO

0.125 Mole of MgO = 0.125mole of Mg

n = given mass /molar mass

0.125 = mass / molar mass

mass = 0.125* 24 = 3grams

Answer 2
Answer:

Final answer:

To produce 5 grams of magnesium oxide, you would theoretically need approximately 3.013 grams of magnesium, based on the mole ratio and molecular weights of magnesium and magnesium oxide.

Explanation:

To calculate the amount of magnesium needed to produce magnesium oxide, we first need to understand the balanced chemical equation for the reaction: Mg + 1/2O2 → MgO. This equation shows that a mole of magnesium (24.31 g) reacts with half a mole of oxygen (8 g) to produce a mole of magnesium oxide (40.31 g). Therefore, if we want to produce 5g of magnesium oxide, we'll need: (5 g MgO * 24.31 g Mg) / 40.31 g MgO = 3.013 g Mg, approximately which is the theoretical amount of magnesium needed.

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When a 10% hydrochloric acid soultion is heated the test tube should alwayd be pointed?
Movement of earths tectonic plates appears to be caused by
What will an object moving at a constant velocity do?come to a stop, unless it is pushed by another forceA.increase in speedB.maintain a constant velocity until acted on by another forceC.come to a stop on its own

Chemistry work here. Please help as soon as possible. I have allot of questions that needs to be answered. Can someone do it for me?

Answers

Answer:

I dont know about the yield but I think mno2 is the limiting reactant

The element oxygen has valence electrons

Answers

Answer:

it’s electron configuration is 1s^2 2s^2 2p^4. To determine valence electrons, add the outermost s and p orbitals. In an oxygen atom, 8 electrons are present. Electron present in the first shell (n=1) 2n^2=2 (1)^2=2 (1)=2.

Increasing which factor will cause the gravitational force between two objects to decrease?weights of the objects
distance between the objects
acceleration of the objects
masses of the objects

Answers

Increasing distance between the objects factor will cause the gravitational force between two objects to decrease. Therefore, option B is correct.

What causes gravitational force to decrease?

The gravitational force grows in proportion to the size of the masses . The gravitational force weakens rapidly as the distance between masses grows. Unless at least one of the objects has a lot of mass, detecting gravitational force is extremely difficult.

Gravity is affected by object size and distance between objects. Mass is a unit of measurement for the amount of matter in an object.

The force of gravity is proportional to the masses of the two objects and inversely proportional to the square of the distance between them. This means that the force of gravity increases with mass but decreases as the distance between objects increases.

Thus, option B is correct.

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Answer:

B

Explanation:

The half-life of a pesticide determines its persistence in the environment. A common pesticide degrades in a first-order process with a rate constant of 6.5 1/hours. What is the half-life in hours of the breakdown reaction? Enter to 4 decimal places.

Answers

Answer:

0.1066 hours

Explanation:

A common pesticide degrades in a first-order process with a rate constant (k) of 6.5 1/hours. We can calculate its half-life (t1/2), that is, the times that it takes for its concentration to be halved, using the following expression.

t1/2 = ln2/k

t1/2 = ln2/6.5 h⁻¹

t1/2 = 0.1066 h

The half-life of the pesticide is 0.1066 hours.

The half-life of the breakdown reaction is 0.1066 h

The half-life of a substance is simply defined as the time taken for half of the original substance to decay.

The half-life of a first order reaction can be obtained by the following equation:

t_(1/2)  = (0.693)/(K)

Where:

t_(1/2) is the half-life

K is the decay constant

With the above formula, we can obtain the half-life of the breakdown reaction as follow:

Rate constant (K) = 6.5 h¯¹

Half-life (t_(1/2)) =.?

t_(1/2) = (0.693)/(K) \n\nt_(1/2) = (0.693)/(6.5)\n\nt_(1/2) = 0.1066 h

Therefore, the half-life of the breakdown reaction is 0.1066 h

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Models can have the same
general appearance as real-ufe
objects.
True or false

Answers

Answer:

true

Explanation:

Answer:

True

Explanation:

Because its true

The steps in a reaction mechanism are as follows. Which species is acting as a catalyst? Step 1: Ag+(aq) + Ce4+(aq) <-----> Ag2+(aq) + Ce3+(aq) Step 2: Tl+(aq) + Ag2+(aq) -----> Tl2+(aq) + Ag+(aq) Step 3: Tl2+(aq) + Ce4+(aq) -----> Tl3+(aq) + Ce3+(aq)

Answers

The specie which is acting as a catalyst is; Ag+(aq).

Discussion:

The catalyst is a specie that exists in the same form at the beginning and end of the reaction.

The reaction's mechanism is as follows;

  • Step 1: Ag+(aq) + Ce⁴+(aq) <-----> Ag²+(aq) + Ce³+(aq)

  • Step 2: Tl+(aq) + Ag²+(aq) -----> Tl²+(aq) + Ag+(aq)

  • Step 3: Tl²+(aq) + Ce⁴+(aq) -----> Tl³+(aq) + Ce³+(aq)

Evidently, although Ag+(aq) was converted to Ag²+(aq) in Step 1 of the reaction; the Ag²+(aq) is reverted back to Ag+(aq) in Step 2 of the reaction.

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Answer:

Ag⁺ acts as the catalyst.

Explanation:

Hello,

In this case, each step is reorganized:

- Step 1:

Ag^+(aq) + Ce^(4+)(aq) \rightleftharpoons Ag^(2+)(aq) + Ce^(3+)(aq)

- Step 2:

Tl^+(aq) + Ag^(2+)(aq) \rightarrow  Tl^(2+)(aq) + Ag^+(aq)

- Step 3:

Tl^(2+)(aq) + Ce^(4+)(aq) \longrightarrow Tl^(3+)(aq) + Ce^(3+)(aq)

In such a way, Ag⁺ is converted to Ag²⁺ in the first step, but then it is regenerated to simple Ag⁺, therefore, Ag⁺ acts as the catalyst.

Best regards.