Answer:
0.278 mol
Explanation:
Step 1: Given and required data
Mass of acetic acid (m): 16.7 g
Chemical formula of acetic acid: CH₃COOH (C₂H₄O₂)
Step 2: Calculate the molar mass (M) of acetic acid
We will use the following expression.
M(C₂H₄O₂) = 2 × M(C) + 4 × M(H) + 2 × M(O)
M(C₂H₄O₂) = 2 × 12.01 g/mol + 4 × 1.01 g/mol + 2 × 16.00 g/mol = 60.06 g/mol
Step 3: Calculate the number of moles (n) of acetic acid
We will use the following expression.
n = m/M
n = 16.7 g/(60.06 g/mol) = 0.278 mol
Answer:
Well atomic number 17 is Chlorine, which is most commonly found as a gas, and is period 7.
Explanation:
elements found on period 7 are some of the most unstable elements.
Answer:
11.29Kj
Explanation:
1. find moles of 33.8g of water
Molar mass of H2O: 18.02g/Mol
33.8/18.02= 1.88mols
2. find energy
1.88 x 6.02= 11.29Kj
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Answer:
Abe chutiye, Question sahi se likh laude phle
Answer
Density = 7.87g/cm^3
Explanation:
Density is the ratio of mass of the given object to the volume of the object, in this question iron is the given object, then we make use of atomic number of iron
Given:
Length= 287pm = 287*10^-10cm
Atomic mass of Fe= 56.0u
Z=2(for body centered cubic unit cell)
Avogadro number (N 0)=6.022× 10^23
Density= ZM/a^3 × N
Where
Z= body centered cubic unit cell
Then substitute
N= Avogadro's number
a=Length
Density = (2× 56)/(287*10^-10cm)^3 × (6.022 × 10^23)
Density = 7.87g/cm^3
The density of iron in a body-centered cubic unit cell can be calculated using the mass and volume of the unit cell.
The density of iron can be calculated using the formula: density = mass/volume. To determine the mass of the unit cell, we need to know the molar mass of iron and the number of atoms in the unit cell. The molar mass of iron is 55.845 g/mol, and there are two iron atoms in the body-centered cubic unit cell of iron. The volume of the unit cell can be calculated using the formula: volume = (edge length)^3.
Putting these values into the formula, we get:
density = (2 * 55.845 g/mol) / ((287 pm)^3)
Converting the edge length to meters (1 pm = 1e-12 m) and calculating, we find that the density of iron is approximately 7.86 g/cm³.
#SPJ11
iron (III) nitrite
iron (II) nitrite
iron (1) nitrite
The name of the ionic compound Fe(NO2)2 is iron (II) nitrite.
The name of the ionic compound Fe(NO2)2 is iron (II) nitrite.
Answer:
Average atomic mass = 19.9 amu
Explanation:
Isotopes can be defined as two or more forms of a chemical element that are made up of equal numbers of protons and electrons but different numbers of neutrons.
Generally, the isotopes of a chemical element have the same chemical properties because of their atomic number but different physical properties due to their atomic weight (mass number).
Given the following data;
Relative abundance of Z-19 = 55%
Relative abundance of Z-21 = 45%
Atomic mass of Z-19 = 19 amu
Atomic mass of Z-21 = 21 amu
To find the average atomic mass;
Average atomic mass = 19 * (55/100) + 21 * (45/100)
Average atomic mass = 19*0.55 + 21*0.45
Average atomic mass = 10.45 + 9.45
Average atomic mass = 19.9 amu
Therefore, the average atomic mass for element Z is 19.9 amu.