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Which is the electron configuration for lithium? A. 1s2 B. 2s3 C. 1s22s1 D. 1s12s2

Answers

Answer 1
Answer:

The electron configuration for lithium 1s^(2) 2s^(1). So, the correct answer is C.

Electronic configuration:-

The electron configuration of an element describes how electrons are distributed in its atomic orbitals. Electron configurations of atoms follow a standard notation in which all electron-containing atomic subshells (with the number of electrons they hold written in superscript) are placed in a sequence.

Electronic configuration for lithium:-

The atomic number of lithium is 3. So, the electronic configuration is as follows:-

Li= 1s^(2) 2s^(1)\n=(He) 2s^(1)

So, the correct option is C.

Learn more about the electronic configuration here:-

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Answer 2
Answer:

Answer:

C

Explanation:

just took the test on edge

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A solution of Na2CO3 is added dropwise to a solution that contains 1.05×10−2 M Fe2+ and 1.60×10−2 M Cd2+. What concentration of CO32− is need to initiate precipitation? Neglect any volume changes during the addition.

Answers

The Ksp of FeCO₃ is 3.45x10-11 and the Ksp of CdCO₃ is 8.7x10-12.

What is Ksp?

Ksp is a mathematical expression used to predict the behavior of a saturated solution. It is an abbreviation of the term “solubility product constant”, and is derived from the thermodynamic equilibrium equation that exists between a solid and its dissolved ions in a solution. Ksp is used to predict the solubility of a given ionic compound, and is a measure of the maximum amount of solute that can be dissolved in a given solvent at a given temperature and pressure.

To initiate precipitation, the concentration of CO²⁻₃ must be greater than or equal to the solubility product of the least soluble salt, which is CdCO₃.
Therefore, the concentration of CO²⁻₃ must be greater than or equal to 8.7x10-12 M.

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How many moles of carbondioxide are produced when 0.2mol of sodium carbonate react with excess hydrovhloric acid

Answers

Answer:

0.2 moles of CO₂  are produced

Explanation:

Given data:

Moles of CO₂ produced = ?

Moles of Na₂CO₃ react = 0.2 mol

Solution:

Chemical equation:

Na₂CO₃ + 2HCl       →     2NaCl + CO₂ + H₂O

Now we will compare the moles of CO₂ with Na₂CO₃ .

                   Na₂CO₃          :             CO₂

                       1                  :               1

                    0.2                :             0.2

Thus, 0.2 moles of CO₂  are produced.

In 100 grams of sweet peas there are 14.5 carbohydrates,5.7 grams of sugars,5.1 grams of dietary fiber, 5.4 grams of protein and 0.4 grams of fat what is the percent composition of each?

Answers

14.5 % carb
5.7% sugar
5.1% fiber
5.4% protein
0.4% fat

You would like to make a 100 mL buffer solution at pH 8.00. Assuming you would like to accomplish this with a hypochlorous acid (HOCl) buffer (HOCl/NaOCl), Ka= 3.0 * 10-8. If the solution is 0.3 M in HOCl, what concentration of NaOCl would be necessary in the buffer solution to obtain a pH of 8.0?

Answers

Answer:

To obtain the pH of 8.0, the concentration of NaOCl needs to be 0.9 M in the 0.3 M HOCl solution

Explanation:

This problem can be solved by Henderson-Hasselbalch equation, which gives relation between the concentration of acid, its salt, pKa and the pH of the solution. This equation is given as,

pH=-log(K_a)+log([NaOCl])/([HOCl])

By placing the known variables in the above equation we get,

8=-log(3*10^(-8))+log([NaOCl])/(0.3)

8-7.52=log([NaOCl])/([0.3])

10^(0.48)=([NaOCl])/(0.3)

[NaOCl]=10^(0.48)*{0.3}

[NaOCl]=0.9 M

The above calculations show that the required concentration of NaOCl is 0.9 M.

Identify the true statement(s) about the valence bond theory. 1. The strength of a bond depends on the amount of overlap between the two orbitals of the bonding atoms. 2. The greater the overlap between two bonding atoms, the lesser the bond strength. 3. Orbitals bond in the directions in which they protrude or point to obtain maximum overlap

Answers

Answer:

The strength of a bond depends on the amount of overlap between the two orbitals of the bonding atoms

Orbitals bond in the directions in which they protrude or point to obtain maximum overlap

Explanation:

The valence bond theory was proposed by Linus Pauling. Compounds are firmed by overlap of atomic orbitals to attain a favourable overlap integral. The better the overlap integral (extent of overlap) the better or stringer the covalent bond.

Orbitals overlap in directions which ensure a maximum overlap of atomic orbitals in the covalent bond.

Answer:

THE STRENGTH OF THE BOND DEPENDS ON THE AMOUNT OF OVERLAP BETWEEN THE TWO ORBITALS OF THE BONDING ATOMS

ORBITALS BOND IN THE DIRECTION OR POINT IN WHICH THEY PROTRUDE OR POINT TO OBTAIN MAXIMUM OVERLAP.

Explanation:

Valence bond theory describes the covalent bond as the overlap of half-filled atomic orbital yields a pair of electrons shared between the two bonded atoms. Overlapping of orbitals occurs when a portion of one orbital and the other occur in the same region of space. The strength of a bond is determined by the amount of overlap between the two orbitals of the bonding atoms. In other words, orbitals that overlap more and in the right orientation of maximum overlapping form stronger bonds that those with less overlap and right orientation for maximum overlap. The bonding occurs at a varying distance in different atoms from which it obtains its stable energy caused by the increase in the attraction of nuclei for the electrons.

Orbitals also bond in the direction to obtain maximum overlap as orientation of the atoms also affect overlap. The greater overlap occurs when atoms are oriented on a direct line mostly end to end or side by side between the two nuclei depending on the type of bond formed. A sigma bond is formed when atoms overlap end to end in which a straight line exists between the two atoms that is the internuclear axis indicating the concentrated energy  density in that region. Pi bond exits in when overlap occurs in the side -to -side orientation and the energy density is concentrated opposite the internuclear axis.

A wavelength of 4.73 x 10-7 m, and a frequency of

Answers

Answer:

Frequency =0.634×10¹⁵ s⁻¹

Explanation:

Given data:

Wavelength = 4.73×10⁻⁷ m

Frequency = ?

Solution:

Formula:

speed of light = wavelength× frequency

speed of light = 3×10⁸ m/s

Now we will put the values in formula.

3×10⁸ m/s = 4.73×10⁻⁷ m × frequency

Frequency = 3×10⁸ m/s /4.73×10⁻⁷ m

Frequency =0.634×10¹⁵ s⁻¹

s⁻¹ = Hz

Frequency =0.634×10¹⁵ Hz
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