Why can't 1−methylcyclohexanol be prepared from a carbonyl compound by reduction? select the single best answer?

Answers

Answer 1

Answer: 1−methylcyclohexanol is a tertiary alcohol. Tertiary Alcohols are synthesized by either reacting Ketone with Organometallic compounds like Grignard reagent or by hydration of substituted alkenes. 1−methylcyclohexanol can not be synthesized by reduction of carbonyl compound because it is not possible to have a starting carbonyl compound having carbonyl group along with three other alkyl groups (as carbon can only form 4 bonds).

Result:
Tertiary alcohols don't contain a hydrogen atom at carbon attached to hydroxyl group that is why it is not possible to synthesize 1−methylcyclohexanol by reduction of carbonyl compound.

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The specific spatial arrangement of amino acid residues that are close to each other in the polypeptide chain is called______the structure of a protein.a. primary.
b. secondary.
c. tertiary.
d. quaternary .

Answers

The specific spatial arrangement of amino acid residues that are close to each other in the polypeptide chain is called the tertiarystructure of a protein.

What is Protein?

Protein structure is three dimensional in shape, where the atoms are arranged in amino acid chain. The chain is polypeptide containing many amino acid sequences.

The tertiary structure have a single polypeptide chain which is called the backbone.

Therefore, the specific spatial arrangement of amino acid residues that are close to each other in the polypeptide chain is called the tertiarystructure of a protein.

Learn more on protein structure here,

brainly.com/question/17338734

Answer:

c. tertiary.

Explanation:

In this case, we can review the definition of each level of structuration in the proteins:

Primary structure

In the primary structure, the amino acids are linked by peptide bonds. That is, the order of the amino acids is the criterion that defines this type of structure.

Secondary structure

In the secondary structure, we have to look at the way in which the protein is folded. The options are:

-) Beta-laminar: A structure in which the protein has a planar shape.

-) Alpha-helix: A structure in which the protein has a cross-strand form.

Tertiary structure

In the tertiary structure, the R groups that the amino acids have in the primary structure can generate interactions with each other. Interactions such as hydrogen bridges, dipole-dipole, hydrophobic interactions. This makes the protein have a very specific three-dimensional structure, on which its function depends.

Quaternary structure

In the quaternary structure, several subunits may be attached, or there may be prostatic groups (metals that can help to attach various protein units).

With all these in mind, the deffinition that fits with the description in the question is the tertiary structure.

I hope it helps!

“the density of a subtance generally decreases as the temperature increases”

Answers

Answer:

The correct answer is D.

Explanation:

Water can evaporate, and if it does, the density decreases

Which of the following reactions would have the smallest value of K at 298 K? Which of the following reactions would have the smallest value of K at 298 K? A + B → 2 C; E°cell = -0.030 V A + 2 B → C; E°cell = +0.98 V A + B → C; E°cell = +1.22 V A + B → 3 C; E°cell = +0.15 V More information is needed to determine.

Answers

The reactions that would have the smallest value of K is

A + B → 2 C; E°cell = -0.030 V

Option A

Generally the equation for the number of electrons transferred is mathematically given as

$nFE^o_(cell)=RT\ln K$

where

T= Temperature

F=25C(298K)

R = Gas constant

R= 8.314 J/K.mol

F = Faraday's constant

F= 96500 C

We see from the equation that the E-cell is directly proportional to K(equilibrium constant of the reaction)

Hence, The reactions that would have the smallest value of K is

A + B → 2 C; E°cell = -0.030 V

For more information on Reaction

brainly.com/question/11231920

Answer:

The reaction with smallest value of K is :

A + B → 2 C; E°cell = -0.030 V

Explanation:

$nFE^o_(cell)=RT\ln K$

where :

n = number of electrons transferred

F = Faraday's constant = 96500 C

$E^o_(cell)$ = standard electrode potential of the cell

R = Gas constant = 8.314 J/K.mol

T = temperature of the reaction = $25^oC=[273+25]=298K$

$K$ = equilibrium constant of the reaction

As we cans see, that standard electrode potential of the cell is directly linked to the equilibrium constant of the reaction.

Higher $E^o_(cell)$ higher will be the value of K.
Lower $E^o_(cell)$ lower will be the value of K.

So, the reaction with smallest value of electrode potential will have smallest value of equilibrium constant. And that reaction is:

A + B → 2 C; $E^o_(cell) =-0.030 V$

Use the equation editor or "Insert Chemistry - WIRIS editor" to write the balanced molecular chemical equation for the reaction of aqueous 0.13 M lead (II) nitrate, with 0.19 M potassium carbonate. You may need to consult Appendix E to determine the states of each reactant and product. Assume any insoluble products are completely insoluble.

Answers

Answer:

Balanced equation:

$Pb(NO_(3))_(2)(aq)+K_(2)CO_(3)(aq)\rightarrow PbCO_(3)(s)+2KNO_(3)(aq)$

Explanation:

The chemical reaction between Lead(II) Nitrate and potassium carbonate is as follows.

$Lead(II)Nitrate+Potassium\,carbonate \rightarrow Lead(III)\,\,carbonate+Potassium\,nitrate$

$Pb(NO_(3))_(2)(aq)+K_(2)CO_(3)(aq)\rightarrow PbCO_(3)(s)+2KNO_(3)(aq)$

Ionic equation:

$Pb^(2+)(aq)+2NO_(3)^(-)(aq)+2K^(+)(aq)+CO_(3)^(2-)(aq)\Leftrightarrow PbCO_(3)(s)+K^(+)(aq)+2NO_(3)^(-)$

Cancel the same ions on the both sides of the reaction.

The net ionic equation is as follows.

$Pb^(2+)(aq)+CO_(3)^(2-)(aq)\Leftrightarrow PbCO_(3)(s)$

200.0 grams of an organic compounds known to contain 98.061 grams of carbon, 10.381 grams of hydrogen, 32.956 grams of oxygen and the rest is nitrogen. what is the empirical formula of the compound? what is the molecular formula of the compound if its molar mass is 194.101?

Answers

Answer:

1. The empirical formula is C₄H₅N₂O

2. The molecular formula is C₈H₁₀N₄O₂

Explanation:

The following data were obtained from the question:

Mass of compound = 200 g

Carbon (C) = 98.061 g

Hydrogen (H) = 10.381 g

Oxygen (O) = 32.956 g

Empirical formula =?

Molecular formula =?

Next, we shall determine the mass of nitrogen in the compound. This can be obtained as follow:

Nitrogen (N) = 200 – (98.061 + 10.381 + 32.956)

Nitrogen (N) = 200 – 141.398

Nitrogen (N) = 58.602 g

1. Determination of the empirical formula of the compound.

C = 98.061 g

H = 10.381 g

O = 32.956 g

N = 58.602 g

Divide by their molar masses

C = 98.061 /12 = 8.172

H = 10.381 /1 = 10.381

O = 32.956 /16 = 2.060

N = 58.602 /14 = 4.186

Divide by the smallest

C = 8.172 /2.060 = 4

H = 10.381 / 2.060 = 5

O = 2.060 / 2.060 = 1

N = 4.186 / 2.060 = 2

Thus, the empirical formula of the compound is C₄H₅N₂O

2. Determination of the molecular formula of the compound.

Empirical formula of the compound => C₄H₅N₂O

Molar mass of compound = 194.101 g/mol

Molecular formula =.?

[C₄H₅N₂O]n = 194.101

[(12×4) + (1×5) + (14×2) + 16]n = 194.101

[48 + 5 + 28 + 16]n = 194.101

97n = 194.101

Divide both side by 97

n = 194.101 /97

n = 2

Molecular formula => [C₄H₅N₂O]n

=> [C₄H₅N₂O]2

=> C₈H₁₀N₄O₂

At 25.0 ⁰C the henry's law constant for hydrogen sulfide(H2S) gas in water is 0.087 M/atm. Caculate the mass in grams of H2S gas that can be dissolved in 400.0 ml of water at 25.00 C and a H2S partial pressure of 2.42atm.

Answers

Answer: The mass of hydrogen sulfide that can be dissolved is 2.86 grams.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the gas.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_(H_2S)=K_H* p_(liquid)$

where,

$K_H$ = Henry's constant = $0.087M/atm$

$p_(H_2S)$ = partial pressure of hydrogen sulfide gas = 2.42 atm

Putting values in above equation, we get:

$C_(H_2S)=0.087M/atm* 2.42atm\n\nC_(H_2S)=0.2105M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}* 1000}{\text{Molar mass of solute}* \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.2105 M

Molar mass of hydrogen sulfide = 34 g/mol

Volume of solution = 400.0 mL

Putting values in above equation, we get:

$0.2105M=\frac{\text{Mass of hydrogen sulfide}* 1000}{34g/mol* 400.0mL}\n\n\text{Mass of }H_2S=(0.2105* 34* 400)/(1000)=2.86g$

Hence, the mass of hydrogen sulfide that can be dissolved is 2.86 grams.

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