The dry solute has a mass of 0.086 g. 0.113 g of water evaporated while heating. What is the concentration in G solute / mL solvent at 30.1 C? Remember: 1 g = 1 ml for waterA. 0.88
B. 0.0860
C. 0.113
D. 0.761

Answers

Answer 1

Answer:

The dry solute has a mass of 0.086 g. 0.113 g of water evaporated while heating, the concentration in G solute / mL solvent at 30.1 C is 0.88.

To find the concentration in g solute / mL solvent, we first need to find the mass of the solvent left after evaporation:

Mass of water before evaporation = 0.113 g

Mass of water after evaporation = 0.113 g - 0.086 g = 0.027 g

Since 1 g of water has a volume of 1 mL, the volume of water after evaporation is also 0.027 mL.

Next, we need to convert the temperature to Kelvin:

T = 30.1 + 273.15 = 303.25 K

We can now use the formula:

concentration = (mass of solute / mass of solvent) / (1 - (mass of water evaporated / mass of solvent))

Plugging in the values we get:

concentration = (0.086 g / (0.027 g)) / (1 - (0.113 g / (0.086 g + 0.027 g)))

concentration = 0.88 g/mL

Therefore, the answer is A. 0.88.

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Answer 2

Answer:

Answer:

Explanation:

worked for me on acellus

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Jun 21, 2015 · 3 posts · 1 author

Most of the time when nitrogen forms a double bond it will be sp2 hybridised. permalink; embed; save.

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Which example shows an ecosystem of organisms? A. a single monkey B. a group of tree monkeys C. a group of tree monkeys and a cluster of trees D. a group of tree monkeys, a cluster of trees, a pile of rocks, and a fierce wind

Answers

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Answers

Answer:

two monosaccharides join by dehydration synthesis

Explanation:

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Final answer:

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Explanation:

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Answers

Answer:
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Explanation:
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